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computers / comp.theory / Re: I finally completed my lexical analyzer generator ( axiomatic basis )

Re: I finally completed my lexical analyzer generator ( axiomatic basis )

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NNTP-Posting-Date: Sun, 24 Oct 2021 09:04:42 -0500
Subject: Re: I finally completed my lexical analyzer generator ( axiomatic
basis )
Newsgroups: comp.theory
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From: NoO...@NoWhere.com (olcott)
Date: Sun, 24 Oct 2021 09:04:40 -0500
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 by: olcott - Sun, 24 Oct 2021 14:04 UTC

On 10/24/2021 5:40 AM, Richard Damon wrote:
> On 10/23/21 11:29 PM, olcott wrote:
>> On 10/23/2021 10:19 PM, Richard Damon wrote:
>>> On 10/23/21 10:16 PM, olcott wrote:
>>>> On 10/23/2021 8:49 PM, Richard Damon wrote:
>>>>>
>>>>> On 10/23/21 9:27 PM, olcott wrote:
>>>>>> In order to make my halt decider a pure function it had to have a
>>>>>> way to look at the inputs to function calls. In order to look at
>>>>>> the inputs to function calls it had to know how many inputs that a
>>>>>> function has.
>>>>>>
>>>>>> This is DFA analyzes C source code to provide the number of
>>>>>> parameters of each function in the file. The number of parameters
>>>>>> per function is the number of {vt} matches per {fn} match.
>>>>>>
>>>>>> The only thing that will change with this file is that the halt
>>>>>> decider will use different halt deciding criteria so that the halt
>>>>>> decider becomes a pure function.
>>>>>>
>>>>>> https://www.researchgate.net/publication/351947980_Halting_problem_undecidability_and_infinitely_nested_simulation
>>>>>>
>>>>>>
>>>>>> In computer programming, a pure function is a function that has
>>>>>> the following properties:[1][2]
>>>>>>
>>>>>> (1) The function return values are identical for identical
>>>>>> arguments (no variation with local static variables, non-local
>>>>>> variables, mutable reference arguments or input streams).
>>>>>>
>>>>>> (2) The function application has no side effects (no mutation of
>>>>>> local static variables, non-local variables, mutable reference
>>>>>> arguments or input/output streams).
>>>>>>
>>>>>> https://en.wikipedia.org/wiki/Pure_function
>>>>>>
>>>>>>
>>>>>>
>>>>>> //
>>>>>> //  Deterministic Finite Automaton (DFA) recognizer
>>>>>> //  of C function headers.
>>>>>>
>>>>>> // Character Classes
>>>>>> //
>>>>>>      EMPTY [0]
>>>>>>      ALPHA [ABCDEFGHIJKLMNOPQRSTUVWXYZ_abcdefghijklmnopqrstuvwxyz]
>>>>>>    NUMERIC [0123456789]
>>>>>>         WS [0x09,0x0A,0x0D,0x20]
>>>>>>     LPAREN [(]
>>>>>>     RPAREN [)]
>>>>>>   ASTERISK [*]
>>>>>>      COMMA [,]
>>>>>>    COMMENT [0x2f]
>>>>>>    NEWLINE [0x0A]
>>>>>>      ASCII [0x20-0x7e]
>>>>>>    CONTROL [0x00-0x09,0x0b-0x1f,0x7f]
>>>>>>
>>>>>>
>>>>>> // Recognized Patterns
>>>>>> //
>>>>>> {et} Empty
>>>>>> {ft} Function_Type
>>>>>> {fn} Function_Name
>>>>>> {vt} Variable_Type
>>>>>> {vn} Variable_Name
>>>>>> {fh} Function_Header
>>>>>>
>>>>>> // DFA Definition to recognize C function headers
>>>>>>
>>>>>> // begin of function type
>>>>>> <00> WS    (00) ALPHA(01) NUMERIC(00) [*](00) [/](12)
>>>>>> <01> WS{ft}(03) ALPHA(01) NUMERIC(01) [*](02)
>>>>>> <02> WS{ft}(03) ALPHA(00) NUMERIC(00) [*](02)
>>>>>>
>>>>>> // begin of function name
>>>>>> <03> WS    (03) ALPHA(04) NUMERIC(00) [*](00)
>>>>>> <04> WS{fn}(05) ALPHA(04) NUMERIC(04) [*](00) [(]{fn}(06)
>>>>>> <05> WS    (05) ALPHA(00) NUMERIC(00) [*](00) [(]    (06)
>>>>>>
>>>>>> // begin of variable type
>>>>>> <06> WS    (06) ALPHA(07) NUMERIC(00) [*](00) [)]{fh}(00)
>>>>>> <07> WS{vt}(09) ALPHA(07) NUMERIC(07) [*](08) [)]{fh}(00)
>>>>>> <08> WS{vt}(09) ALPHA(00) NUMERIC(00) [*](08)
>>>>>>
>>>>>> // begin of variable name
>>>>>> <09> WS    (09) ALPHA(10) NUMERIC(00) [*]    (00)
>>>>>> <10> WS{vn}(11) ALPHA(10) NUMERIC(10) [,]{vn}(06) [)]{vn}(00)
>>>>>> <11> WS    (11) ALPHA(00) NUMERIC(00) [,]    (06) [)]    (00)
>>>>>>
>>>>>> // ignores all "//" comments
>>>>>> <12> WS     (00) ALPHA(01)  NUMERIC(00) [*](00) [/](13)
>>>>>> <13> CONTROL(13) ASCII(13)  [0x0A] (00)
>>>>>>
>>>>>
>>>>> Ok,
>>>>>
>>>>> Just remember that being a 'Pure Funciton' isn't the actual
>>>>> requirement, the decider needs to be a Mathematical Computation,
>>>>> which means that all copies of it, when given the same inputs,
>>>>> generates the same outputs.
>>>>>
>>>>> You STILL have the error that you treat H as a 'pure simulator'
>>>>> when it is not, it is only a 'pure simulatior until' and as such,
>>>>> the behavior of the copy of H in H^ DOES have an affect on the
>>>>> behavior of that H^. Remember, a 'Pure Simulator' (aka a UTM) NEVER
>>>>> stops simulating until the machine it is simulating ends, even if
>>>>> that takes forever.
>>>>>
>>>>
>>>> void Infinite_Loop()
>>>> {
>>>>    HERE: goto HERE;
>>>> }
>>>>
>>>> _Infinite_Loop()
>>>> [00000ab0](01)  55              push ebp
>>>> [00000ab1](02)  8bec            mov ebp,esp
>>>> [00000ab3](02)  ebfe            jmp 00000ab3
>>>> [00000ab5](01)  5d              pop ebp
>>>> [00000ab6](01)  c3              ret
>>>> Size in bytes:(0007) [00000ab6]
>>>>
>>>> Are you saying that the only way that a simulating halt decider can
>>>> correctly decide that the above code will never stop running is to
>>>> wait until the end of time?
>>>>
>>>
>>> No. You seem to have a reading comprension problem.
>>>
>>> The Simulating Halt Decider is fully allowed to abort the simulation
>>> of the machine it is simulationg.
>>>
>>> The only issue is that IF it does so, it can't treat itself as if it
>>> was a UTM/Pure SImulator, and thus the fact that it never saw the
>>> comptation reach a halting state isn't proof of anything.
>>
>> When a simulating halt decider acts as if it is a pure simulator and
>> watches the behavior of an infinite loop it can correctly abort the
>> simulation of this input and report that this input never halts. We
>> can generalize this simplest case of infinite execution to all other
>> cases:
>>
>> All that I am doing is generalizing this same idea. When-so-ever a
>> simulating halt decider can correctly axiomatically determine that its
>> input would never halt if it remained a pure simulator then it can
>> abort the simulation of this input and report that this input never
>> halts.
>>
>> When a simulating halt decider correctly axiomatically determines X
>> then we know that X is necessarily true.
>>
>>
>
> NO!
>
> You are making an INCORRECT generalization.

When-so-ever X is correct about Y then X is not incorrect about Y is
always true.

> t is just like claiming
> that log(a+b+c) is log(a) + log(b) + log(c) because we have the case
> that log(1+2+3) = log(1) + log(2) + log(3).
>
> You have made a claim, PROVE IT. Not just a rhetorical argument done
> with vague words, but an honest to god actual analytical proof, using
> the exact same accepted definitions of all the words. And then go and
> prove that setup does meet the conditions required by the proof to use it.
>
> You say 'axiomatically', but that is just YOUR DISHONEST DOGDE to insert
> in a statement that is FALSE.
>
> Now, part of the problem is that you make a number of small errors that
> you continue to just ignore and these build up to your false conclusion.
>
> Your statement would be correct if pronoun usage was correct and the
> usage refered to just this one COPY being adjusted, and not the shared
> copy being changed, which causes the change to change the supposed to be
> fixed algorithm employed by the input being simulated. We know that for
> THAT case, H is incorrect, as using an ACTUAL 'Pure Simulator' to
> process this input (where H^ still uses the original H that does abort)
> shows that H^ WILL HALT, and thus the claim "would not halt unless H
> aborts the simulation" is incorrect.
>

_Infinite_Loop()
[00000ab0](01) 55 push ebp
[00000ab1](02) 8bec mov ebp,esp
[00000ab3](02) ebfe jmp 00000ab3
[00000ab5](01) 5d pop ebp
[00000ab6](01) c3 ret
Size in bytes:(0007) [00000ab6]

It is always the same process. H simulates its input until it determines
that its input would never halt.

Here is what the above simulation looks like:

[00000ab0](01) 55 push ebp
[00000ab1](02) 8bec mov ebp,esp
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3
[00000ab3](02) ebfe jmp 00000ab3

Can you understand in this simplest possible case that the above is a
non halting behavior pattern?

> These errors have been pointed out to you repeatedly, but you continue
> to ignore them. Initially this could have just been passed off as
> carelessness, but your continuing shows that it can't just be that, but
> must be either stupidity, mental illness, or just that you are a liar.
>

--
Copyright 2021 Pete Olcott

"Great spirits have always encountered violent opposition from mediocre
minds." Einstein

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o I finally completed my lexical analyzer generator (needed by my halt decider)

By: olcott on Sun, 24 Oct 2021

24olcott
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