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computers / comp.theory / Re: The Halting Problem proofs have a fatal flaw [ Visual Studio c/c++ project ]

Re: The Halting Problem proofs have a fatal flaw [ Visual Studio c/c++ project ]

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Subject: Re: The Halting Problem proofs have a fatal flaw [ Visual Studio
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From: Rich...@Damon-Family.org (Richard Damon)
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Date: Wed, 28 Sep 2022 20:19:23 -0400
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 by: Richard Damon - Thu, 29 Sep 2022 00:19 UTC

On 9/28/22 7:56 PM, olcott wrote:
> On 9/28/2022 6:37 PM, Richard Damon wrote:
>> On 9/28/22 7:31 PM, olcott wrote:
>>> On 9/28/2022 6:08 PM, Richard Damon wrote:
>>>> On 9/28/22 11:44 AM, olcott wrote:
>>>>> On 9/28/2022 6:28 AM, Richard Damon wrote:
>>>>>> On 9/27/22 11:04 PM, olcott wrote:
>>>>>>> On 9/27/2022 9:46 PM, Richard Damon wrote:
>>>>>>>>
>>>>>>>> On 9/27/22 10:30 PM, olcott wrote:
>>>>>>>>> On 9/27/2022 9:24 PM, Richard Damon wrote:
>>>>>>>>>> On 9/27/22 10:02 PM, olcott wrote:
>>>>>>>>>>> On 9/27/2022 8:50 PM, Richard Damon wrote:
>>>>>>>>>>>> On 9/27/22 9:33 PM, olcott wrote:
>>>>>>>>>>>>> On 9/27/2022 8:15 PM, Richard Damon wrote:
>>>>>>>>>>>>>> On 9/27/22 9:00 PM, olcott wrote:
>>>>>>>>>>>>>>> On 9/27/2022 6:02 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> On 9/27/22 11:19 AM, olcott wrote:
>>>>>>>>>>>>>>>>> On 9/27/2022 6:00 AM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>> On 9/26/22 11:49 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>> On 9/26/2022 10:29 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>> On 9/26/22 11:04 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>> On 9/26/2022 9:58 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>> On 9/26/22 10:41 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>> On 9/26/2022 9:23 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/22 10:18 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/2022 8:49 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/22 9:26 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/2022 8:15 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/22 8:58 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/2022 7:36 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/22 8:25 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/2022 6:59 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/22 7:46 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/2022 6:12 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/22 2:03 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/2022 12:48 PM, Mr Flibble wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On Mon, 26 Sep 2022 12:42:02 -0500
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> olcott <polcott2@gmail.com> wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/2022 12:19 PM, Mr Flibble
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On Mon, 26 Sep 2022 12:15:15 -0500
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> olcott <none-ya@beez-waxes.com>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 9/26/2022 11:05 AM, Kaz
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Kylheku wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> On 2022-09-26, Lew Pitcher
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> <lew.pitcher@digitalfreehold.ca>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Sorry, guy, but comp.lang.c is
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> not the place to discuss this
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> sort of thing. Why don't you
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> try comp.theory ?
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Because Olcott postings will
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> push you out of visibility?
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> If people would give me a fair
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> and honest review I could quit
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> posting. You gave up on me before
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> I could point out the error with
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> the diagonalization argument that
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> you relied on for your rebuttal:
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> The diagonalization argument
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> merely proves that no value returned
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> to P from its call to H can
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> possibly be correct. This argument
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> totally ignores that the return
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> value from H is unreachable by its
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> simulated P caller when H is
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> based on a simulating halt decider.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> This makes it impossible for P to
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> do the opposite of whatever H
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> decides.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Complete halt deciding system
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> (Visual Studio Project)
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> (a) x86utm operating system
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> (b) complete x86 emulator
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> (c) Several halt deciders and
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> their inputs contained within
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Halt7.c
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> https://liarparadox.org/2022_09_07.zip
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> You keep making the same mistake
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> again and again. H IS NOT SUPPOSED
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> TO BE RECURSIVE.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> H(P,P) is not recursive.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Your H is recursive because P isn't
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> recursive and yet you have to abort
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> your infinite recursion: the
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> recursion is caused by your H and
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> not by
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> P.  Nowhere in any halting problem
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> proof does it state that the call to
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> H by P is recursive in nature
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> BECAUSE H IS NOT SUPPOSED TO EXECUTE
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> P, H
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> IS SUPPOSED TO *ANALYSE* P.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> /Flibble
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Nowhere in any HP proof (besides
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> mine) is the idea of a simulating
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> halt decider (SHD) ever thought all
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> the way through.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Because the proof doesn't care at all
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> how the decider got the answer,
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Because the definition of a UTM
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> specifies that the correct simulation
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> of a machine description provides the
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> actual behavior of the underlying
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> machine whenever any simulating halt
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> decider must abort its simulation to
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> prevent infinite simulation it is
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> necessarily correct to report that
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> this input does not halt.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Right, which means it CAN'T be a UTM,
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> and thus *ITS* simulation does not
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> define the "behavior of the input".
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> The behavior of the correct simulation
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> of the input is its actual behavior.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> That H correctly predicts that its
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> correct simulation never stops running
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> unless aborted conclusively proves that
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> this correctly simulated input would
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> never reach its own final state in 1 to
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> ∞ steps of correct simulation.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> But the behavior the halting problem is
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> asking for is the behavior of the actual
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> machine.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> Only within the context that no one ever
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> bothered to think the application of a
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> simulating halt decider all the way through.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> No, the DEFINITION of a Halt Decider is to
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> decide on the behavior of the Actual Machine.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>> That definition is made obsolete by a
>>>>>>>>>>>>>>>>>>>>>>>>>>>>> simulating halt decider.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>> Nope, the definition IS the definition.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>>> You don't get to change it.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>> I created a new concept that makes earlier
>>>>>>>>>>>>>>>>>>>>>>>>>>> ideas about this obsolete:
>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>> Because the definition of a UTM specifies
>>>>>>>>>>>>>>>>>>>>>>>>>>> that the correct simulation of a machine
>>>>>>>>>>>>>>>>>>>>>>>>>>> description provides the actual behavior of
>>>>>>>>>>>>>>>>>>>>>>>>>>> the underlying machine whenever any
>>>>>>>>>>>>>>>>>>>>>>>>>>> simulating halt decider must abort its
>>>>>>>>>>>>>>>>>>>>>>>>>>> simulation to prevent infinite simulation it
>>>>>>>>>>>>>>>>>>>>>>>>>>> is necessarily correct to report that this
>>>>>>>>>>>>>>>>>>>>>>>>>>> input does not halt.
>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>> Because the above is verified as correct on
>>>>>>>>>>>>>>>>>>>>>>>>>>> the basis of the meaning of its words it is
>>>>>>>>>>>>>>>>>>>>>>>>>>> irrefutable.
>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>> Right, but H isn't a UTM, so its simulation
>>>>>>>>>>>>>>>>>>>>>>>>>> doesn't matter.
>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>>> Unless you can specify that material difference
>>>>>>>>>>>>>>>>>>>>>>>>> between the two, that would seem to prove that
>>>>>>>>>>>>>>>>>>>>>>>>> you are technically incompetent.
>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>> H doesn't correctly repoduce the behavior of a
>>>>>>>>>>>>>>>>>>>>>>>> non-halting input.
>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>> Thus, it isn't a UTM.
>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy
>>>>>>>>>>>>>>>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>> When Ĥ is applied to ⟨Ĥ⟩      // subscripts
>>>>>>>>>>>>>>>>>>>>>>> indicate unique finite strings
>>>>>>>>>>>>>>>>>>>>>>> Ĥ copies its input ⟨Ĥ0⟩ to ⟨Ĥ1⟩ then H simulates
>>>>>>>>>>>>>>>>>>>>>>> ⟨Ĥ0⟩ ⟨Ĥ1⟩
>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>> Then these steps would keep repeating: (unless
>>>>>>>>>>>>>>>>>>>>>>> their simulation is aborted)
>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>> Note, you say "unless their simulation is aborted"
>>>>>>>>>>>>>>>>>>>>>> but your defiition of H DOES abort its simulation,
>>>>>>>>>>>>>>>>>>>>>> thus this doesn't occur.
>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>> FAIL.
>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>> Ĥ0 copies its input ⟨Ĥ1⟩ to ⟨Ĥ2⟩ then H0
>>>>>>>>>>>>>>>>>>>>>>> simulates ⟨Ĥ1⟩ ⟨Ĥ2⟩
>>>>>>>>>>>>>>>>>>>>>>> Ĥ1 copies its input ⟨Ĥ2⟩ to ⟨Ĥ3⟩ then H1
>>>>>>>>>>>>>>>>>>>>>>> simulates ⟨Ĥ2⟩ ⟨Ĥ3⟩
>>>>>>>>>>>>>>>>>>>>>>> Ĥ2 copies its input ⟨Ĥ3⟩ to ⟨Ĥ4⟩ then H2
>>>>>>>>>>>>>>>>>>>>>>> simulates ⟨Ĥ3⟩ ⟨Ĥ4⟩...
>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>> This exact same behavior occurs when we replace H
>>>>>>>>>>>>>>>>>>>>>>> with a UTM.
>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>> But since H ISN'T a UTM, you can't assume that it is.
>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>>> H is designed to predict the result of 1 to ∞
>>>>>>>>>>>>>>>>>>>>> correctly simulated steps, thus predict the
>>>>>>>>>>>>>>>>>>>>> behavior of a UTM simulation.
>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>>> Except it doesn't do that.
>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>> H does correctly predict the actual behavior of 1 to
>>>>>>>>>>>>>>>>>>> ∞ simulated steps of P.
>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>> Nope, since we have shown that if H(P,P) returns 0,
>>>>>>>>>>>>>>>>>> then P(P) will Halt.
>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> *That is false and you know it so you are a liar for
>>>>>>>>>>>>>>>>> the 500th time*
>>>>>>>>>>>>>>>>> *You know that you are not referring to the behavior of
>>>>>>>>>>>>>>>>> an input to H*
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> No, I am refering to the input to H.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> The input to H(P,P) represents the computation P(P), or
>>>>>>>>>>>>>>>> your P isn't the required "impossible Program".
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> You cannot find a competent source that agrees that the
>>>>>>>>>>>>>>> actual behavior of the input is not provided by the
>>>>>>>>>>>>>>> correct simulation of this input.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> Correct AND COMPLETE simulation of the input.
>>>>>>>>>>>>>>
>>>>>>>>>>>>> So like I said you have no source, you and most other are
>>>>>>>>>>>>> only going by learned-by-rote so when a new issue comes up
>>>>>>>>>>>>> your flounder. The others here not going by learned-by-rote
>>>>>>>>>>>>> are going by total cluelessness.
>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> What about the Linz definition of a Halt Decider, the one
>>>>>>>>>>>> YOU quote.
>>>>>>>>>>>
>>>>>>>>>>> He does not say that the correct simulation of an input does
>>>>>>>>>>> not provide the actual behavior of this input. You will find
>>>>>>>>>>> no competent person that will disagree with me on this point.
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> But he DOES say that the DEFINITION of the right answer is the
>>>>>>>>>> behavior of the machine that input describes, so THAT is the
>>>>>>>>>> behavior that counts.
>>>>>>>>>>
>>>>>>>>> People that know these things more deeply than learned-by-rote
>>>>>>>>> will understand that my alternative definition is sound.
>>>>>>>>
>>>>>>>> No, it is WRONG, since it doesn't match.
>>>>>>>>
>>>>>>>> That is like saying Two is the right answer to the question of
>>>>>>>> How many cats you have, when you have one cats and one dog,
>>>>>>>> because dogs are really pretty much like a cat.
>>>>>>>>
>>>>>>>> FAIL.
>>>>>>>>
>>>>>>>>>
>>>>>>>>> We can know that it is sound by simply knowing that the correct
>>>>>>>>> simulation of the input does provide the actual behavior of
>>>>>>>>> this input. We know this on the basis of the definition of a UTM.
>>>>>>>>>
>>>>>>>>>
>>>>>>>>
>>>>>>>> The CORRECT AND COMPLETE.
>>>>>>>>
>>>>>>>> Not being complete, it CAN'T show the actual behavior.
>>>>>>>>
>>>>>>>> That is like getting off the highway at the second exit, well
>>>>>>>> before you get into the city, and announce that traffic is clear
>>>>>>>> into the city, because you didn't see any traffic.
>>>>>>>>
>>>>>>>> You are just PROVING our stupidity.
>>>>>>>
>>>>>>> Mike already corrected you on this.
>>>>>>> The correct simulation of 1 to ∞ steps of the input *is*
>>>>>>> computationally equivalent to the direct execution of 1 to ∞
>>>>>>> steps of the input.
>>>>>>>
>>>>>>> How can you disagree with this besides lying?
>>>>>>>
>>>>>>>
>>>>>>
>>>>>> So, what SINGLED EXACT INPUT have you done this for?
>>>>>>
>>>>>> Remember, exact of your members of Px are DIFFERENT!
>>>>>>
>>>>>> You only "correctly simulate" a given input once, for a single
>>>>>> number between 1 and infinity, so you never have a valuation of 1
>>>>>> to infinite steps for any input except those that are basd on an
>>>>>> Hx that never stops them, and thos Hx never abort.
>>>>>>
>>>>>
>>>>> You cannot find a competent source that agrees that the actual
>>>>> behavior of the input is not provided by the correct simulation of
>>>>> this input therefore
>>>>>
>>>>
>>>> Except that the problem is that "Correct Simulation" is generally
>>>> taken to be a Correct and Complete Simulation,
>>>
>>> *No it is not and Mike already corrected you on this*
>>> You stubbornly insistent on lying.
>>
>> The ONLY definition of "simulation" for Turing Machines that I know of
>> is the UTM, and it only does a complete simulation of its input.
>>
>> Care to provide a reliable source that defines a "Correct Simulation"
>> as to include a partial one that is applicable here?
>
> If you weren't a despicable lying bastard you would already acknowledge
> that 1 to ∞ simulated steps of a machine description is necessarily
> computationally equivalent to a corresponding 1 to ∞ steps of direct
> execution.
>

Infinite steps, or more steps than it takes to reach the final state, yes.

You "set" never simulates THIS input that far (the H(P,P) built on the P
that calls the H that returns 0 for H(P,P)), unless you are actually
going to try to claim that all the Px's in your set are the same,

That means that it doesn't matter on the behavior of P doesn't depend on
the behavior of the H that it calls.

DO you really want to be on record for making THAT claim.

Since your set never includes a simulation of this P for more than just
one single finite number of steps that didn't reach the final step, your
"claim" is proved to be incorrect and false. Your making of it, when you
should know it not to be true means either you are a total idiot, or a
pathological lying idiot.

You have killed your reputation under the pile of these falsehoods, and
are going to be remembered for that lying and idiotic attempts to prove
something that just wasn't true.

SubjectRepliesAuthor
o representing binary number naturally

By: Lew Pitcher on Mon, 26 Sep 2022

63Lew Pitcher
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