On 6/9/2022 1:12 PM, Richard Damon wrote:
> On 6/9/22 1:55 PM, olcott wrote:
>> On 6/9/2022 12:46 PM, Mr Flibble wrote:
>>> On Thu, 9 Jun 2022 12:39:32 -0500
>>> olcott <NoOne@NoWhere.com> wrote:
>>>
>>>> On 6/9/2022 12:28 PM, Mr Flibble wrote:
>>>>> On Thu, 9 Jun 2022 12:15:24 -0500
>>>>> olcott <NoOne@NoWhere.com> wrote:
>>>>>> On 6/9/2022 12:06 PM, Richard Damon wrote:
>>>>>>> On 6/9/22 12:54 PM, olcott wrote:
>>>>>>>> On 6/9/2022 11:34 AM, Richard Damon wrote:
>>>>>>>>> On 6/9/22 11:47 AM, olcott wrote:
>>>>>>>>>> void P(u32 x)
>>>>>>>>>> {
>>>>>>>>>>      if (H(x, x))
>>>>>>>>>>        HERE: goto HERE;
>>>>>>>>>>      return;
>>>>>>>>>> }
>>>>>>>>>>
>>>>>>>>>> int main()
>>>>>>>>>> {
>>>>>>>>>>      P(P);
>>>>>>>>>> }
>>>>>>>>>>
>>>>>>>>>> _P()
>>>>>>>>>> [000012e7](01)  55              push ebp
>>>>>>>>>> [000012e8](02)  8bec            mov ebp,esp
>>>>>>>>>> [000012ea](03)  8b4508          mov eax,[ebp+08]
>>>>>>>>>> [000012ed](01)  50              push eax
>>>>>>>>>> [000012ee](03)  8b4d08          mov ecx,[ebp+08]
>>>>>>>>>> [000012f1](01)  51              push ecx
>>>>>>>>>> [000012f2](05)  e880feffff      call 00001177 // call H
>>>>>>>>>> [000012f7](03)  83c408          add esp,+08
>>>>>>>>>> [000012fa](02)  85c0            test eax,eax
>>>>>>>>>> [000012fc](02)  7402            jz 00001300
>>>>>>>>>> [000012fe](02)  ebfe            jmp 000012fe
>>>>>>>>>> [00001300](01)  5d              pop ebp
>>>>>>>>>> [00001301](01)  c3              ret
>>>>>>>>>> Size in bytes:(0027) [00001301]
>>>>>>>>>>
>>>>>>>>>> _main()
>>>>>>>>>> [00001307](01)  55              push ebp
>>>>>>>>>> [00001308](02)  8bec            mov ebp,esp
>>>>>>>>>> [0000130a](05)  68e7120000      push 000012e7 // push P
>>>>>>>>>> [0000130f](05)  e8d3ffffff      call 000012e7 // call P
>>>>>>>>>> [00001314](03)  83c404          add esp,+04
>>>>>>>>>> [00001317](02)  33c0            xor eax,eax
>>>>>>>>>> [00001319](01)  5d              pop ebp
>>>>>>>>>> [0000131a](01)  c3              ret
>>>>>>>>>> Size in bytes:(0020) [0000131a]
>>>>>>>>>>
>>>>>>>>>>     machine   stack     stack     machine    assembly
>>>>>>>>>>     address   address   data      code       language
>>>>>>>>>>     ========  ========  ========  =========  =============
>>>>>>>>>> [00001307][00102190][00000000] 55         push ebp
>>>>>>>>>> [00001308][00102190][00000000] 8bec       mov ebp,esp
>>>>>>>>>> [0000130a][0010218c][000012e7] 68e7120000 push 000012e7 //
>>>>>>>>>> push P [0000130f][00102188][00001314] e8d3ffffff call 000012e7
>>>>>>>>>> // call P [000012e7][00102184][00102190] 55         push ebp
>>>>>>>>>>     // enter executed P
>>>>>>>>>> [000012e8][00102184][00102190] 8bec       mov ebp,esp
>>>>>>>>>> [000012ea][00102184][00102190] 8b4508     mov eax,[ebp+08]
>>>>>>>>>> [000012ed][00102180][000012e7] 50         push eax      //
>>>>>>>>>> push P [000012ee][00102180][000012e7] 8b4d08     mov
>>>>>>>>>> ecx,[ebp+08] [000012f1][0010217c][000012e7] 51         push
>>>>>>>>>> ecx      // push P [000012f2][00102178][000012f7] e880feffff
>>>>>>>>>> call 00001177 // call H
>>>>>>>>>>
>>>>>>>>>> Begin Local Halt Decider Simulation   Execution Trace Stored
>>>>>>>>>> at:212244 [000012e7][00212230][00212234] 55          push ebp
>>>>>>>>>>     // enter emulated P
>>>>>>>>>> [000012e8][00212230][00212234] 8bec        mov ebp,esp
>>>>>>>>>> [000012ea][00212230][00212234] 8b4508      mov eax,[ebp+08]
>>>>>>>>>> [000012ed][0021222c][000012e7] 50          push eax      //
>>>>>>>>>> push P [000012ee][0021222c][000012e7] 8b4d08      mov
>>>>>>>>>> ecx,[ebp+08] [000012f1][00212228][000012e7] 51          push
>>>>>>>>>> ecx      // push P [000012f2][00212224][000012f7] e880feffff
>>>>>>>>>> call 00001177 // call H
>>>>>>>>>
>>>>>>>>> So, by what instruction reference manual is a call 00001177
>>>>>>>>> followedby the execution of the instruction at 000012e7.
>>>>>>>>>
>>>>>>>>> Your "CPU" is broken, or emulation incorrect.
>>>>>>>>>
>>>>>>>>> FAIL.
>>>>>>>>>> [000012e7][0025cc58][0025cc5c] 55          push ebp      //
>>>>>>>>>> enter emulated P
>>>>>>>>>> [000012e8][0025cc58][0025cc5c] 8bec        mov ebp,esp
>>>>>>>>>> [000012ea][0025cc58][0025cc5c] 8b4508      mov eax,[ebp+08]
>>>>>>>>>> [000012ed][0025cc54][000012e7] 50          push eax      //
>>>>>>>>>> push P [000012ee][0025cc54][000012e7] 8b4d08      mov
>>>>>>>>>> ecx,[ebp+08] [000012f1][0025cc50][000012e7] 51          push
>>>>>>>>>> ecx      // push P [000012f2][0025cc4c][000012f7] e880feffff
>>>>>>>>>> call 00001177 // call H Local Halt Decider: Infinite Recursion
>>>>>>>>>> Detected Simulation Stopped
>>>>>>>>>>
>>>>>>>>>> It is completely obvious that when H(P,P) correctly emulates
>>>>>>>>>> its input that it must emulate the first seven instructions of
>>>>>>>>>> P. Because the seventh instruction of P repeats this process we
>>>>>>>>>> know with complete certainty that the correct and complete
>>>>>>>>>> emulation of P by H would never reach its final “ret”
>>>>>>>>>> instruction, thus never halts.
>>>>>>>>>
>>>>>>>>> Problem, the 7th intruction DOESN't "Just repeat the procedure",
>>>>>>>>> because that H always has the option to abort its simulation,
>>>>>>>>> just like this onne did, and return to its P and see it halt.
>>>>>>>> THAT YOU ARE SIMPLY TOO STUPID TO UNDERSTAND THIS IS NO ACTUAL
>>>>>>>> REBUTTAL AT ALL:
>>>>>>>>
>>>>>>>> The partial correct x86 emulation of the input to H(P,P)
>>>>>>>> conclusively proves that the complete and correct x86 emulation
>>>>>>>> would never stop running.
>>>>>>>>
>>>>>>>
>>>>>>> You SAY that, but you don't answer the actual questions about HOW.
>>>>>>
>>>>>> THAT YOU ARE SIMPLY TOO STUPID TO UNDERSTAND THIS IS NO EVIDENCE
>>>>>> WHAT-SO-EVER THAT I DID NOT COMPLETELY PROVE THAT THE CORRECT
>>>>>> PARTIAL EMULATION OF THE INPUT TO H(P,P) CONCLUSIVELY PROVES THAT
>>>>>> THE CORRECT AND COMPLETE X86 EMULATION OF THE INPUT TO H(P,P)
>>>>>> WOULD NEVER STOP RUNNING.
>>>>>>
>>>>>> It is completely obvious that when H(P,P) correctly emulates its
>>>>>> input that it must emulate the first seven instructions of P.
>>>>>> Because the seventh instruction of P repeats this process we know
>>>>>> with complete certainty that the correct and complete emulation of
>>>>>> P by H would never reach its final “ret” instruction, thus never
>>>>>> halts.
>>>>>
>>>>> If P should have halted (i.e. no infinite loop) then your simulation
>>>>> detector, S (not H), gets the answer wrong.  You S is NOT a halting
>>>>> decider.
>>>>>
>>>>> /Flibble
>>>>
>>>> THAT YOU ARE SIMPLY TOO STUPID TO UNDERSTAND THIS IS NO ACTUAL
>>>> REBUTTAL AT ALL.
>>>>
>>>> _P()
>>>> [00001352](01)  55              push ebp
>>>> [00001353](02)  8bec            mov ebp,esp
>>>> [00001355](03)  8b4508          mov eax,[ebp+08]
>>>> [00001358](01)  50              push eax      // push P
>>>> [00001359](03)  8b4d08          mov ecx,[ebp+08]
>>>> [0000135c](01)  51              push ecx      // push P
>>>> [0000135d](05)  e840feffff      call 000011a2 // call H
>>>> [00001362](03)  83c408          add esp,+08
>>>> [00001365](02)  85c0            test eax,eax
>>>> [00001367](02)  7402            jz 0000136b
>>>> [00001369](02)  ebfe            jmp 00001369
>>>> [0000136b](01)  5d              pop ebp
>>>> [0000136c](01)  c3              ret
>>>> Size in bytes:(0027) [0000136c]
>>>>
>>>> It is completely obvious that when H(P,P) correctly emulates its
>>>> input that it must emulate the first seven instructions of P. Because
>>>> the seventh instruction of P repeats this process we know with
>>>> complete certainty that the correct and complete emulation of P by H
>>>> would never reach its final “ret” instruction, thus never halts.
>>>
>>> We are going around and around and around in circles. I will try again:
>>>
>>> If you replace the opcodes "EB FE" at 00001369 with the opcodes "90 90"
>>> then your H gets the answer wrong: P should have halted.
>>>
>>> /Flibble
>>>
>>
>> As I already said before this is merely your cluelessness that when
>> H(P,P) is invoked the correct x86 emulation of the input to H(P,P)
>> makes and code after [0000135d] unreachable.
>
> Wrong, because when that H return the value 0, it will get there.
Like I said people that are dumber than a box of rocks won't be able to
correctly understand this.

When H(P,P) is invoked the correctly emulated input to H(P,P) cannot
possibly reach any instruction beyond [0000135d].

People that are very stupid might believe that once the emulation of the
input to H(P,P) has been aborted that this dead process will magically
leap to [0000136c] even though it is a dead process.

--
Copyright 2022 Pete Olcott

"Talent hits a target no one else can hit;
Genius hits a target no one else can see."
Arthur Schopenhauer