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interests / rec.gambling.lottery / Re: Prize Winners played by Fibonacci series

SubjectAuthor
* Re: Prize Winners played by Fibonacci seriesMarmaduke Jinks
+* Re: Prize Winners played by Fibonacci series王乾懿 Wang Qianyi (Nan)
|`* Re: Prize Winners played by Fibonacci series王乾懿 Wang Qianyi (Nan)
| `- Re: Prize Winners played by Fibonacci series王乾懿 Wang Qianyi (Nan)
`* Re: Prize Winners played by Fibonacci series王乾懿 Wang Qianyi (Nan)
 `* Re: Prize Winners played by Fibonacci seriesMarmaduke Jinks
  `- Re: Prize Winners played by Fibonacci series王乾懿 Wang Qianyi (Nan)

1
Re: Prize Winners played by Fibonacci series

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Subject: Re: Prize Winners played by Fibonacci series
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 by: Marmaduke Jinks - Sat, 12 Feb 2022 14:14 UTC

"??? Wang Qianyi (Nan)" <lotteryprediction@gmail.com> wrote in message
news:a1b07248-a4d6-412a-b44a-5e7eba1c3ce3n@googlegroups.com...
> MJ is the winner, winning 8445 euro, followed by three players, Leela
> (AI), Random, and Nigel.
>
> 1. MJ 8445 euro
> 2. Leela 2020 euro
> 2. Random 2020 euro
> 2. Nigel 2020 euro
>
> 1,1,2,3,5,8,13,21,34,55,89,144,233,377
>
> 14 ROUNDS
>
> PLAY UK LOTTO HOT PICKS
>
> Leela
> 37* 3 14* 40 21 12 9 27 35 26 39* 4 11 18 20 30 41 50 43 46 2 1 8 22
> =24+22+14=60
> Random
> 9 12 15 37* 21 3 30 39* 31* 26 6 10 17 38 34 48 46 1 2 4 11 20 19 22
> =21+17+16=54
>
> MJ had a 4 in top 11 in round 6
> 03* 29 46 56* 13* 5 14 57* 43 28 31 41* 58 52 39 59 42 36 17 33 37 8 25 21
> =24+21+20+17+13=95
> https://groups.google.com/g/rec.gambling.lottery/c/tuWwmIE2FmQ
> According to the calculation, he would have won
> (3*4*800)-{165*(1+1+2+3)=9600-1155=8445 euro
>
> Nigel
> 14*,28,56,17,51,52,30,24,13*,15,31*,35,42,58,1,33,45,6,20,34,59,32,25*,7,
> =24+16+14+2=56
> Nigel has a 3 in top 11 in round 5,
> https://groups.google.com/g/rec.gambling.lottery/c/3A7MJiZJ754
>
> According to the calculation, he would have won
> (5*800)-{165*(1+1+2+3+5)}=4000-1980=2020 euro
>
> Leela, Random had a 3 in top 11 in round 5,
> https://groups.google.com/g/rec.gambling.lottery/c/3A7MJiZJ754
>
> According to the calculation, they would have won
> (5*800)-{165*(1+1+2+3+5)}=4000-1980=2020 euro

You might not have noticed this but Jerome's numbers are all the Fibonacci
and Primes under 59, supplemented by 2 others. ;-)

MJ

Re: Prize Winners played by Fibonacci series

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Subject: Re: Prize Winners played by Fibonacci series
From: lotteryp...@gmail.com (王乾懿 Wang Qianyi (Nan))
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 by: 王乾懿 Wang Qiany - Mon, 14 Feb 2022 02:36 UTC

Prize ranking if a winner halts.
1. MJ 22300
2. Nigel 2020
2. Leela 2020
2. Random 2020

Re: Prize Winners played by Fibonacci series

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Subject: Re: Prize Winners played by Fibonacci series
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 by: 王乾懿 Wang Qiany - Mon, 14 Feb 2022 02:42 UTC

Prize ranking if a winner didn't halt and play till round 13.
The only winner is MJ. In 13 rounds (probably one month's time), he has won 27255 euro as pure profit.
1. MJ 22300+4955=27255

Nigel, Leela, and Random would have all lost 6890 euro if they kept playing after winning all at round 5.
2. Nigel 2020-165*(1+1+2+3+5+8+13+21)=-6890
2. Leela 2020-165*(1+1+2+3+5+8+13+21)=-6890
2. Random 2020-165*(1+1+2+3+5+8+13+21)=-6890

Re: Prize Winners played by Fibonacci series

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Subject: Re: Prize Winners played by Fibonacci series
From: lotteryp...@gmail.com (王乾懿 Wang Qianyi (Nan))
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 by: 王乾懿 Wang Qiany - Mon, 14 Feb 2022 02:50 UTC

Other players would have lost 62040 euro after round 13.

Way of play: play top 11 numbers' match3 full combo matches by times of 1,1,2,3,5,8,13,21,34,55,89,144 for each round.

165*(1+1+2+3+5+8+13+21+34+55+89+144)=62040 euro.

In conclusion, to guarantee most players make profits and win money playing UK hot picks, a wise idea is to stop playing after winning more money.

It would help to lose more to stop playing after round 5 if no 3 in the top 11, as three players got a 3 in the top 11 all in round 5.

In that case, if you could afford to lose 165*(1+1+2+3+5)=1980 in 5 rounds, you can give a shoot, and win at least 2020 euro back, and if lucky, with a 4 in the top 11, you could win (4*5*800)-{165*(1+1+2+3+5)}=16000-1980=14020 euro, which is so far the best strategy with a maximum guarantee.

Nan

Re: Prize Winners played by Fibonacci series

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Subject: Re: Prize Winners played by Fibonacci series
From: lotteryp...@gmail.com (王乾懿 Wang Qianyi (Nan))
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 by: 王乾懿 Wang Qiany - Mon, 14 Feb 2022 03:06 UTC

RE:
> You might not have noticed this but Jerome's numbers are all the Fibonacci
> and Primes under 59, supplemented by 2 others. ;-)
>
> MJ
That would be an interesting idea to test all those interesting numbers!

Have you tried adding the sum of statistical mode?
Take an arbitrary number, such as 48965, then add the individual digits to obtain 4+8+9+6+5=32, and then add the results to get 3+2=5. This form of summing is known as the sum of statistical mode.

If A*B=C, then multiplying the number whose sum is A by the number whose sum is B yields a sum equal to the sum of C. 3*4=12, for example. 3*4=12, for example.

Take a number with a sum of  sum of statistical mode of three, such as 201, and multiply it by a number with a sum of  sum of statistical mode of four, such as 112, to get 201*112=22512, and the plurality of 22512 is 3 (2+2+5+1+2=12, 1+2=3), therefore 3*4=12, and the sum of  sum of statistical mode of the number 12 is likewise three.

Round 11 Saturday, February 5, 2022.
Winning Numbers: 08, 24, 36, 39, 46, and 56.
The sum of  sum of statistical mode are as follows: 8, 6, 9, 3, 0, 2.

Wed, Feb 9, 2022, Round 12 UK LOTTO 659
12 16 17 43 53 57 are the winning numbers.
The sum of  sum of statistical mode  are 3, 7, 8, 7, 8, 3

Both periods' sum of  sum of statistical mode contain the same numerals, 3 and 8.

Nan

Re: Prize Winners played by Fibonacci series

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 by: Marmaduke Jinks - Mon, 14 Feb 2022 12:16 UTC

"??? Wang Qianyi (Nan)" <lotteryprediction@gmail.com> wrote in message
news:e122e86b-5028-49ba-ac5e-954bfad4c04cn@googlegroups.com...
RE:
> You might not have noticed this but Jerome's numbers are all the Fibonacci
> and Primes under 59, supplemented by 2 others. ;-)
>
> MJ
That would be an interesting idea to test all those interesting numbers!

Have you tried adding the sum of statistical mode?
Take an arbitrary number, such as 48965, then add the individual digits to
obtain 4+8+9+6+5=32, and then add the results to get 3+2=5. This form of
summing is known as the sum of statistical mode.

If A*B=C, then multiplying the number whose sum is A by the number whose sum
is B yields a sum equal to the sum of C. 3*4=12, for example. 3*4=12, for
example.

Take a number with a sum of sum of statistical mode of three, such as 201,
and multiply it by a number with a sum of sum of statistical mode of four,
such as 112, to get 201*112=22512, and the plurality of 22512 is 3
(2+2+5+1+2=12, 1+2=3), therefore 3*4=12, and the sum of sum of statistical
mode of the number 12 is likewise three.

Round 11 Saturday, February 5, 2022.
Winning Numbers: 08, 24, 36, 39, 46, and 56.
The sum of sum of statistical mode are as follows: 8, 6, 9, 3, 0, 2.

Wed, Feb 9, 2022, Round 12 UK LOTTO 659
12 16 17 43 53 57 are the winning numbers.
The sum of sum of statistical mode are 3, 7, 8, 7, 8, 3

Both periods' sum of sum of statistical mode contain the same numerals, 3
and 8.

Nan

~~

That statistical sum thingy goes whoosh over my head. ;-)

I think Jerome is happy to just run the Prime Fibs (Primes and Fibonacci's
under 59 + 2 extras) to see how they do over this 20 draw series. At the
moment his average hit is 2.5 per draw, whereas Jink's Hit ratio is 3.2.
Looking at the Lotto 6/59 game a set of 1, 2 or 3 prime fibs in your 6
number selections gives an 82% strike rate with a mode of 2. The suggestion
there is that it's not that reliable.

MJ

Re: Prize Winners played by Fibonacci series

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 by: 王乾懿 Wang Qiany - Mon, 14 Feb 2022 13:07 UTC

在 2022年2月14日星期一 UTC+8 20:18:04,<Marmaduke Jinks> 写道:
> "??? Wang Qianyi (Nan)" <lotteryp...@gmail.com> wrote in message
> news:e122e86b-5028-49ba...@googlegroups.com...
> RE:
> > You might not have noticed this but Jerome's numbers are all the Fibonacci
> > and Primes under 59, supplemented by 2 others. ;-)
> >
> > MJ
> That would be an interesting idea to test all those interesting numbers!
>
> Have you tried adding the sum of statistical mode?
> Take an arbitrary number, such as 48965, then add the individual digits to
> obtain 4+8+9+6+5=32, and then add the results to get 3+2=5. This form of
> summing is known as the sum of statistical mode.
>
> If A*B=C, then multiplying the number whose sum is A by the number whose sum
> is B yields a sum equal to the sum of C. 3*4=12, for example. 3*4=12, for
> example.
>
> Take a number with a sum of sum of statistical mode of three, such as 201,
> and multiply it by a number with a sum of sum of statistical mode of four,
> such as 112, to get 201*112=22512, and the plurality of 22512 is 3
> (2+2+5+1+2=12, 1+2=3), therefore 3*4=12, and the sum of sum of statistical
> mode of the number 12 is likewise three.
>
>
> Round 11 Saturday, February 5, 2022.
> Winning Numbers: 08, 24, 36, 39, 46, and 56.
> The sum of sum of statistical mode are as follows: 8, 6, 9, 3, 0, 2.
>
> Wed, Feb 9, 2022, Round 12 UK LOTTO 659
> 12 16 17 43 53 57 are the winning numbers.
> The sum of sum of statistical mode are 3, 7, 8, 7, 8, 3
>
>
> Both periods' sum of sum of statistical mode contain the same numerals, 3
> and 8.
>
> Nan
> ~~
>
> That statistical sum thingy goes whoosh over my head. ;-)
>
> I think Jerome is happy to just run the Prime Fibs (Primes and Fibonacci's
> under 59 + 2 extras) to see how they do over this 20 draw series. At the
> moment his average hit is 2.5 per draw, whereas Jink's Hit ratio is 3.2.
> Looking at the Lotto 6/59 game a set of 1, 2 or 3 prime fibs in your 6
> number selections gives an 82% strike rate with a mode of 2. The suggestion
> there is that it's not that reliable.
>
> MJ
True. In fact, I don't think any method of picking numbers guarantees a high probability of winning consistently, but the key point is that you can create the highest possible score in the shortest possible time.

Nan

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