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interests / rec.puzzles / Re: find one factor for 1280000401

SubjectAuthor
* find one factor for 1280000401henh...@gmail.com
+* Re: find one factor for 1280000401Stephen Perry
|`* Re: find one factor for 1280000401Richard Heathfield
| `* Re: find one factor for 1280000401Ilan Mayer
|  +- Re: find one factor for 1280000401henh...@gmail.com
|  `* Re: find one factor for 1280000401Richard Heathfield
|   `- Re: find one factor for 1280000401Richard Tobin
`* Re: find one factor for 1280000401Pancho
 `- Re: find one factor for 1280000401Pancho

1
find one factor for 1280000401

<8f206ee6-4d1a-465e-bc31-555006a133adn@googlegroups.com>

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Subject: find one factor for 1280000401
From: henha...@gmail.com (henh...@gmail.com)
Injection-Date: Fri, 01 Jul 2022 17:56:55 +0000
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 by: henh...@gmail.com - Fri, 1 Jul 2022 17:56 UTC

1. Factorize: 2009

2. Factorize: ( 81 ^ 3 + 4 )

3. find one factor for 1280000401 ---------- pls wait a few days before posting answers or hints.

pls wait a few days before posting answers or hints.

Re: find one factor for 1280000401

<3ceb08fe-fd3d-437e-9b89-c7ef3ae81252n@googlegroups.com>

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Subject: Re: find one factor for 1280000401
From: stephen....@gmail.com (Stephen Perry)
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 by: Stephen Perry - Sat, 2 Jul 2022 00:06 UTC

On Friday, July 1, 2022 at 1:56:56 PM UTC-4, henh...@gmail.com wrote:
> 1. Factorize: 2009
>
> 2. Factorize: ( 81 ^ 3 + 4 )
>
>
> 3. find one factor for 1280000401 ---------- pls wait a few days before posting answers or hints.
>
>
>
> pls wait a few days before posting answers or hints.

interesting, the last one only has 2 prime factors

swp

Re: find one factor for 1280000401

<t9o96f$2gjfr$1@dont-email.me>

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From: rjh...@cpax.org.uk (Richard Heathfield)
Newsgroups: rec.puzzles
Subject: Re: find one factor for 1280000401
Date: Sat, 2 Jul 2022 03:06:06 +0100
Organization: Fix this later
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 by: Richard Heathfield - Sat, 2 Jul 2022 02:06 UTC

On 02/07/2022 1:06 am, Stephen Perry wrote:
> On Friday, July 1, 2022 at 1:56:56 PM UTC-4, henh...@gmail.com wrote:
>> 1. Factorize: 2009
>>
>> 2. Factorize: ( 81 ^ 3 + 4 )
>>
>>
>> 3. find one factor for 1280000401 ---------- pls wait a few days before posting answers or hints.
>>
>>
>>
>> pls wait a few days before posting answers or hints.
>
> interesting, the last one only has 2 prime factors

Interesting, one of those two prime factors is strongly related to:

49670943841842804710155545472491674508546533688809\
00974054678181809222613988422954258068225897148337\
95213495222240007671066490851554749892134937936656\
28299463790905194739834052614993480810633009669295\
35999447677162583428914287273190484804247505062548\
45534889774433360425470710774683290442555783815659\
95587526442752892957567593156343721469275848230250\
31242105280010233598043558996619044969346638973101\
50700949162282909151225143677669059060838583122439\
58597751816029723282726401683087622594082178263812\
60302214424111544898559326399838404889278853003358\
33913419474049335611983897922046477193331977853760\
79498859329368329674820971921713672892086786229753\
14947040444848309008177329032019450499069829806554\
81012268737891556187874734833673235166827039350174\
86350158134726246547741534038937359543777932214369\
44462684662996874035200000000000000000000000000000\
00000000000000000000000000000000000000000000000000\
000000000000000000000000.

Finding the relationship is left as an exercise ---------- pls
don't wait as much as a millisecond before posting answers or hints.

--
Richard Heathfield
Email: rjh at cpax dot org dot uk
"Usenet is a strange place" - dmr 29 July 1999
Sig line 4 vacant - apply within

Re: find one factor for 1280000401

<960212c3-a443-44fa-a696-88f749fca269n@googlegroups.com>

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Subject: Re: find one factor for 1280000401
From: ilan_no_...@hotmail.com (Ilan Mayer)
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 by: Ilan Mayer - Sat, 2 Jul 2022 13:44 UTC

On Friday, July 1, 2022 at 10:06:09 PM UTC-4, Richard Heathfield wrote:
> On 02/07/2022 1:06 am, Stephen Perry wrote:
> > On Friday, July 1, 2022 at 1:56:56 PM UTC-4, henh...@gmail.com wrote:
> >> 1. Factorize: 2009
> >>
> >> 2. Factorize: ( 81 ^ 3 + 4 )
> >>
> >>
> >> 3. find one factor for 1280000401 ---------- pls wait a few days before posting answers or hints.
> >>
> >>
> >>
> >> pls wait a few days before posting answers or hints.
> >
> > interesting, the last one only has 2 prime factors
> Interesting, one of those two prime factors is strongly related to:
>
> 49670943841842804710155545472491674508546533688809\
> 00974054678181809222613988422954258068225897148337\
> 95213495222240007671066490851554749892134937936656\
> 28299463790905194739834052614993480810633009669295\
> 35999447677162583428914287273190484804247505062548\
> 45534889774433360425470710774683290442555783815659\
> 95587526442752892957567593156343721469275848230250\
> 31242105280010233598043558996619044969346638973101\
> 50700949162282909151225143677669059060838583122439\
> 58597751816029723282726401683087622594082178263812\
> 60302214424111544898559326399838404889278853003358\
> 33913419474049335611983897922046477193331977853760\
> 79498859329368329674820971921713672892086786229753\
> 14947040444848309008177329032019450499069829806554\
> 81012268737891556187874734833673235166827039350174\
> 86350158134726246547741534038937359543777932214369\
> 44462684662996874035200000000000000000000000000000\
> 00000000000000000000000000000000000000000000000000\
> 000000000000000000000000.
>
> Finding the relationship is left as an exercise ---------- pls
> don't wait as much as a millisecond before posting answers or hints.
>
> --
> Richard Heathfield
> Email: rjh at cpax dot org dot uk
> "Usenet is a strange place" - dmr 29 July 1999
> Sig line 4 vacant - apply within

421 is a factor of 1280000401; the above number is 421! (factorial of 421).

Please reply to ilanlmayer at gmail dot com

__/\__
\ /
__/\\ //\__ Ilan Mayer
\ /
/__ __\ Toronto, Canada
/__ __\
||

Re: find one factor for 1280000401

<32a4084f-7ec5-4377-bc61-ace9fe1813edn@googlegroups.com>

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Subject: Re: find one factor for 1280000401
From: henha...@gmail.com (henh...@gmail.com)
Injection-Date: Sat, 02 Jul 2022 14:21:39 +0000
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 by: henh...@gmail.com - Sat, 2 Jul 2022 14:21 UTC

On Saturday, July 2, 2022 at 6:45:00 AM UTC-7, Ilan Mayer wrote:
> On Friday, July 1, 2022 at 10:06:09 PM UTC-4, Richard Heathfield wrote:
> > On 02/07/2022 1:06 am, Stephen Perry wrote:
> > > On Friday, July 1, 2022 at 1:56:56 PM UTC-4, henh...@gmail.com wrote:
> > >> 1. Factorize: 2009
> > >>
> > >> 2. Factorize: ( 81 ^ 3 + 4 )
> > >>
> > >>
> > >> 3. find one factor for 1280000401 ---------- pls wait a few days before posting answers or hints.
> > >>
> > >>
> > >>
> > >> pls wait a few days before posting answers or hints.
> > >
> > > interesting, the last one only has 2 prime factors
> > Interesting, one of those two prime factors is strongly related to:
> >
> > 49670943841842804710155545472491674508546533688809\
> > 00974054678181809222613988422954258068225897148337\
> > 95213495222240007671066490851554749892134937936656\
> > 28299463790905194739834052614993480810633009669295\
> > 35999447677162583428914287273190484804247505062548\
> > 45534889774433360425470710774683290442555783815659\
> > 95587526442752892957567593156343721469275848230250\
> > 31242105280010233598043558996619044969346638973101\
> > 50700949162282909151225143677669059060838583122439\
> > 58597751816029723282726401683087622594082178263812\
> > 60302214424111544898559326399838404889278853003358\
> > 33913419474049335611983897922046477193331977853760\
> > 79498859329368329674820971921713672892086786229753\
> > 14947040444848309008177329032019450499069829806554\
> > 81012268737891556187874734833673235166827039350174\
> > 86350158134726246547741534038937359543777932214369\
> > 44462684662996874035200000000000000000000000000000\
> > 00000000000000000000000000000000000000000000000000\
> > 000000000000000000000000.
> >
> > Finding the relationship is left as an exercise ---------- pls
> > don't wait as much as a millisecond before posting answers or hints.
> >
> > --
> > Richard Heathfield
> > Email: rjh at cpax dot org dot uk
> > "Usenet is a strange place" - dmr 29 July 1999
> > Sig line 4 vacant - apply within
> 421 is a factor of 1280000401; the above number is 421! (factorial of 421).
>

i should have emphasized... that ....
all these problems are...

What formula do you use (as shortcuts) in doing these factorizations by hand (or in your head) ?

> 1. Factorize: 2009 ----------- ans: the formula for (x^2 - y^2) = ...............

>
> > >> 2. Factorize: ( 81 ^ 3 + 4 ) .........

> > >> 3. find one factor for 1280000401 ---------- pls wait a few days before posting answers or hints.

Re: find one factor for 1280000401

<t9pp1k$2l9tj$1@dont-email.me>

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From: rjh...@cpax.org.uk (Richard Heathfield)
Newsgroups: rec.puzzles
Subject: Re: find one factor for 1280000401
Date: Sat, 2 Jul 2022 16:42:44 +0100
Organization: Fix this later
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 by: Richard Heathfield - Sat, 2 Jul 2022 15:42 UTC

On 02/07/2022 2:44 pm, Ilan Mayer wrote:
> On Friday, July 1, 2022 at 10:06:09 PM UTC-4, Richard Heathfield wrote:
>> On 02/07/2022 1:06 am, Stephen Perry wrote:
>>> On Friday, July 1, 2022 at 1:56:56 PM UTC-4, henh...@gmail.com wrote:
>>>> 1. Factorize: 2009
>>>>
>>>> 2. Factorize: ( 81 ^ 3 + 4 )
>>>>
>>>>
>>>> 3. find one factor for 1280000401 ---------- pls wait a few days before posting answers or hints.
>>>>
>>>>
>>>>
>>>> pls wait a few days before posting answers or hints.
>>>
>>> interesting, the last one only has 2 prime factors
>> Interesting, one of those two prime factors is strongly related to:
>>
>> 49670943841842804710155545472491674508546533688809\
>> 00974054678181809222613988422954258068225897148337\
>> 95213495222240007671066490851554749892134937936656\
>> 28299463790905194739834052614993480810633009669295\
>> 35999447677162583428914287273190484804247505062548\
>> 45534889774433360425470710774683290442555783815659\
>> 95587526442752892957567593156343721469275848230250\
>> 31242105280010233598043558996619044969346638973101\
>> 50700949162282909151225143677669059060838583122439\
>> 58597751816029723282726401683087622594082178263812\
>> 60302214424111544898559326399838404889278853003358\
>> 33913419474049335611983897922046477193331977853760\
>> 79498859329368329674820971921713672892086786229753\
>> 14947040444848309008177329032019450499069829806554\
>> 81012268737891556187874734833673235166827039350174\
>> 86350158134726246547741534038937359543777932214369\
>> 44462684662996874035200000000000000000000000000000\
>> 00000000000000000000000000000000000000000000000000\
>> 000000000000000000000000.
>>
>> Finding the relationship is left as an exercise ---------- pls
>> don't wait as much as a millisecond before posting answers or hints.
>>
> 421 is a factor of 1280000401; the above number is 421! (factorial of 421).

All those 0s at the end are a dead giveaway, aren't they?

--
Richard Heathfield
Email: rjh at cpax dot org dot uk
"Usenet is a strange place" - dmr 29 July 1999
Sig line 4 vacant - apply within

Re: find one factor for 1280000401

<t9pq9l$b34$1@macpro.inf.ed.ac.uk>

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From: rich...@cogsci.ed.ac.uk (Richard Tobin)
Newsgroups: rec.puzzles
Subject: Re: find one factor for 1280000401
Date: Sat, 2 Jul 2022 16:04:05 +0000 (UTC)
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Originator: richard@cogsci.ed.ac.uk (Richard Tobin)
 by: Richard Tobin - Sat, 2 Jul 2022 16:04 UTC

In article <t9pp1k$2l9tj$1@dont-email.me>,
Richard Heathfield <rjh@cpax.org.uk> wrote:

>>> ...
>>> 44462684662996874035200000000000000000000000000000\
>>> 00000000000000000000000000000000000000000000000000\
>>> 000000000000000000000000.

>> 421 is a factor of 1280000401; the above number is 421! (factorial of 421).

>All those 0s at the end are a dead giveaway, aren't they?

And - assuming it is a factorial - the number of 0s (103) quickly
tells you it's between 420 and 424 factorial.

-- Richard

Re: find one factor for 1280000401

<t9sd3q$32vqr$1@dont-email.me>

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From: Pancho.J...@proton.me (Pancho)
Newsgroups: rec.puzzles
Subject: Re: find one factor for 1280000401
Date: Sun, 3 Jul 2022 16:37:29 +0100
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 by: Pancho - Sun, 3 Jul 2022 15:37 UTC

On 01/07/2022 18:56, henh...@gmail.com wrote:
> 1. Factorize: 2009
>
> 2. Factorize: ( 81 ^ 3 + 4 )
>
>
> 3. find one factor for 1280000401 ---------- pls wait a few days before posting answers or hints.
>
>
>
> pls wait a few days before posting answers or hints.
>

1. Is Fermat factorization 45^2-4^2 = (45+4)(45-4) = 49*41

2. Is Fermat's little theorem

3. Dunno

Re: find one factor for 1280000401

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From: Pancho.J...@proton.me (Pancho)
Newsgroups: rec.puzzles
Subject: Re: find one factor for 1280000401
Date: Sun, 3 Jul 2022 18:21:31 +0100
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 by: Pancho - Sun, 3 Jul 2022 17:21 UTC

On 03/07/2022 16:37, Pancho wrote:

>
> 2. Is Fermat's little theorem
>
Sorry ignore that. I don't know what I was thinking :-(

1
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