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devel / comp.lang.python / extend behaviour of assignment operator

extend behaviour of assignment operator

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From: guenther...@gmail.com (Guenther Sohler)
Newsgroups: comp.lang.python
Subject: extend behaviour of assignment operator
Date: Tue, 9 Jan 2024 08:14:31 +0100
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by: Guenther Sohler - Tue, 9 Jan 2024 07:14 UTC

Hi,

when i run this code

a = cube([10,1,1])
b = a

i'd like to extend the behaviour of the assignment operator
a shall not only contain the cube, but the cube shall also know which
variable name it
was assigned to, lately. I'd like to use that for improved user interaction.

effective code should be:

a=cube([10,1,1])
a.name='a'

b=a
b.name='b' # i am aware that a.name also changes

can decorators also be used with assignment operators ?

thank you for your hints

Re: extend behaviour of assignment operator

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From: ram...@zedat.fu-berlin.de (Stefan Ram)
Newsgroups: comp.lang.python
Subject: Re: extend behaviour of assignment operator
Date: 10 Jan 2024 19:40:49 GMT
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by: Stefan Ram - Wed, 10 Jan 2024 19:40 UTC

Guenther Sohler <guenther.sohler@gmail.com> writes:
>i'd like to extend the behaviour of the assignment operator

The following attempt is just a proof of concept, as it will
not handle properly all possible code. To do something similar
in a more general way, use "import ast", parse the code into
an AST and then search the AST for assignements and insert
code to change the name attribute after them.

import re

class thing: pass # all things pass

code = r'''
a = thing()
print( a.name )
b = a
print( b.name )
'''

code = \
re.sub\
( r'((?:^|\n)(\s*)([\w_]+)\s*=.*(\n|$))', r'\1\2\3.name="\3"\n', code )
exec( code )

Subject	Author
extend behaviour of assignment operator	Guenther Sohler
Re: extend behaviour of assignment operator	Stefan Ram