sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...

Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi

Where the sqrt of -1 is the second half of the equation above --
(((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
Where -y =-.05 and x=0 starts the plot into the third quadrant.
A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
going in the positive and the mirror image going into the negative.
Just enter the above equation into Wolfram Alpha using any number.
pi(in this case),e , golden ratio, the primes etc. giving the same results.

Just having some fun. ;-)!!!

Dan

On Saturday, June 25, 2022 at 4:34:15 PM UTC-4, Dan joyce wrote:
> sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
>
> Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
>
> Where the sqrt of -1 is the second half of the equation above --
> (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> Where -y =-.05 and x=0 starts the plot into the third quadrant.
> A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> going in the positive and the mirror image going into the negative.
> Just enter the above equation into Wolfram Alpha using any number.
> pi(in this case),e , golden ratio, the primes etc. giving the same results.
>
> Just having some fun. ;-)!!!
>
> Dan

This here --
> going in the positive and the mirror image going into the negative.

It Should read ---
going into the positive and the reverse mirror image going into the negative.

On Saturday, June 25, 2022 at 4:34:32 PM UTC-7, Dan joyce wrote:
> On Saturday, June 25, 2022 at 4:34:15 PM UTC-4, Dan joyce wrote:
> > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> >
> > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> >
> > Where the sqrt of -1 is the second half of the equation above --
> > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > going in the positive and the mirror image going into the negative.
> > Just enter the above equation into Wolfram Alpha using any number.
> > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> >
> > Just having some fun. ;-)!!!
> >
> > Dan
> This here --
> > going in the positive and the mirror image going into the negative.
> It Should read ---
> going into the positive and the reverse mirror image going into the negative.

PI isn't imaginary.

Mitchell Raemsch

On Saturday, June 25, 2022 at 11:26:15 PM UTC-4, mitchr...@gmail.com wrote:
> On Saturday, June 25, 2022 at 4:34:32 PM UTC-7, Dan joyce wrote:
> > On Saturday, June 25, 2022 at 4:34:15 PM UTC-4, Dan joyce wrote:
> > > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> > >
> > > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> > >
> > > Where the sqrt of -1 is the second half of the equation above --
> > > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > > going in the positive and the mirror image going into the negative.
> > > Just enter the above equation into Wolfram Alpha using any number.
> > > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> > >
> > > Just having some fun. ;-)!!!
> > >
> > > Dan
> > This here --
> > > going in the positive and the mirror image going into the negative.
> > It Should read ---
> > going into the positive and the reverse mirror image going into the negative.
> PI isn't imaginary.
>
> Mitchell Raemsch

Yes but is tied to -1 where e^pi(i) =-1

On Saturday, June 25, 2022 at 8:34:27 PM UTC-7, Dan joyce wrote:
> On Saturday, June 25, 2022 at 11:26:15 PM UTC-4, mitchr...@gmail.com wrote:
> > On Saturday, June 25, 2022 at 4:34:32 PM UTC-7, Dan joyce wrote:
> > > On Saturday, June 25, 2022 at 4:34:15 PM UTC-4, Dan joyce wrote:
> > > > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> > > >
> > > > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> > > >
> > > > Where the sqrt of -1 is the second half of the equation above --
> > > > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > > > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > > > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > > > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > > > going in the positive and the mirror image going into the negative.
> > > > Just enter the above equation into Wolfram Alpha using any number.
> > > > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> > > >
> > > > Just having some fun. ;-)!!!
> > > >
> > > > Dan
> > > This here --
> > > > going in the positive and the mirror image going into the negative.
> > > It Should read ---
> > > going into the positive and the reverse mirror image going into the negative.
> > PI isn't imaginary.
> >
> > Mitchell Raemsch
> Yes but is tied to -1 where e^pi(i) =-1

That is still based on the imaginary.

On 6/25/2022 1:34 PM, Dan joyce wrote:
>
> sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
>
> Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
>
> Where the sqrt of -1 is the second half of the equation above --
> (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> Where -y =-.05 and x=0 starts the plot into the third quadrant.
> A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> going in the positive and the mirror image going into the negative.
> Just enter the above equation into Wolfram Alpha using any number.
> pi(in this case),e , golden ratio, the primes etc. giving the same results.
>
> Just having some fun. ;-)!!!

Check this out:

https://youtu.be/d0vY0CKYhPY

;^)

mitchr...@gmail.com wrote:

>> Yes but is tied to -1 where e^pi(i) =-1
>
> That is still based on the imaginary.

Ukraine's neo-Nazi Azov battalion has built a 'state within a state,' and
it despises both Russia and the liberal West
The Ukrainian regiment adheres to its own brand of ‘National Idea,’
loosely modelled on Mussolini's Italy

just let them wank.

On Sunday, June 26, 2022 at 8:47:57 AM UTC-4, Keith Terajima wrote:
> mitchr...@gmail.com wrote:
>
> >> Yes but is tied to -1 where e^pi(i) =-1
> >
> > That is still based on the imaginary.
> Ukraine's neo-Nazi Azov battalion has built a 'state within a state,' and
> it despises both Russia and the liberal West
> The Ukrainian regiment adheres to its own brand of ‘National Idea,’
> loosely modelled on Mussolini's Italy
>
> just let them wank.

According to Scott Ritter the political parties that have been disallowed in Ukraine were the non-nazi parties.
In other words, politically, you are correct.
https://www.youtube.com/watch?v=C5zwwIUKOsM
Of course the logic of the Ukranian nazi is mainly to simply kill Russians.
To their West they seem to look the other way... for now...
Engaging them down the road in the EU seems detrimental to Europe as a civilization.
This suits U.$. interests perfectly. How do we feel about Syrian refugees in Europe?
We feel great about it. Anything that holds others down is what we seek now..
This is our foreign policy; sleazy as it is. This is the net result of capitalism.
It doesn't even want to see semi-socialist European countries care for their people.
Certainly the EU must be held down.
If confusion won't do it, contagion will.

On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
> On 6/25/2022 1:34 PM, Dan joyce wrote:
> >
> > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> >
> > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> >
> > Where the sqrt of -1 is the second half of the equation above --
> > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > going in the positive and the mirror image going into the negative.
> > Just enter the above equation into Wolfram Alpha using any number.
> > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> >
> > Just having some fun. ;-)!!!
> Check this out:
>
> https://youtu.be/d0vY0CKYhPY
>
> ;^)

Interesting.
The many different crazy places pi will appear.
I just used pi as one of the ---> oo numbers that work in this equation.

I did this plot in the third quadrant where each new frame was a continuation of
the last frame. So the parabolic curve keeps slightly increasing the distance from the
-y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
and y=0. Where x+y=x^2
A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
x + y=x^2 from the first quadrant.
That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
Duplicating the same part of the parabola in the first quadrant --
x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
but only equal too -1 in the third quadrant.
Negative integer points of -x\-y in the parabola in the third quadrant --
-x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5

On Sunday, June 26, 2022 at 9:05:25 AM UTC-7, Dan joyce wrote:
> On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
> > On 6/25/2022 1:34 PM, Dan joyce wrote:
> > >
> > > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> > >
> > > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> > >
> > > Where the sqrt of -1 is the second half of the equation above --
> > > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > > going in the positive and the mirror image going into the negative.
> > > Just enter the above equation into Wolfram Alpha using any number.
> > > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> > >
> > > Just having some fun. ;-)!!!
> > Check this out:
> >
> > https://youtu.be/d0vY0CKYhPY
> >
> > ;^)
> Interesting.
> The many different crazy places pi will appear.
> I just used pi as one of the ---> oo numbers that work in this equation.
>
> I did this plot in the third quadrant where each new frame was a continuation of
> the last frame. So the parabolic curve keeps slightly increasing the distance from the
> -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
> reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
> and y=0. Where x+y=x^2
> A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
> x + y=x^2 from the first quadrant.
> That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
> Duplicating the same part of the parabola in the first quadrant --
> x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
> but only equal too -1 in the third quadrant.
> Negative integer points of -x\-y in the parabola in the third quadrant --
> -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5

The square root of negative one is known to be imaginary.
And rightly so. It is not reality.

Mitchell Raemsch

On Sunday, June 26, 2022 at 2:00:00 PM UTC-4, mitchr...@gmail.com wrote:
> On Sunday, June 26, 2022 at 9:05:25 AM UTC-7, Dan joyce wrote:
> > On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
> > > On 6/25/2022 1:34 PM, Dan joyce wrote:
> > > >
> > > > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> > > >
> > > > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> > > >
> > > > Where the sqrt of -1 is the second half of the equation above --
> > > > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > > > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > > > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > > > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > > > going in the positive and the mirror image going into the negative.
> > > > Just enter the above equation into Wolfram Alpha using any number.
> > > > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> > > >
> > > > Just having some fun. ;-)!!!
> > > Check this out:
> > >
> > > https://youtu.be/d0vY0CKYhPY
> > >
> > > ;^)
> > Interesting.
> > The many different crazy places pi will appear.
> > I just used pi as one of the ---> oo numbers that work in this equation.
> >
> > I did this plot in the third quadrant where each new frame was a continuation of
> > the last frame. So the parabolic curve keeps slightly increasing the distance from the
> > -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
> > reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
> > and y=0. Where x+y=x^2
> > A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
> > x + y=x^2 from the first quadrant.
> > That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
> > Duplicating the same part of the parabola in the first quadrant --
> > x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
> > but only equal too -1 in the third quadrant.
> > Negative integer points of -x\-y in the parabola in the third quadrant --
> > -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5
> The square root of negative one is known to be imaginary.
> And rightly so. It is not reality.
>
>
> Mitchell Raemsch

Well, if you believe that the Cartesian coordinate system is valid then negative numbers are valid.
x+-y=x^2 in a simple math equation .05+ -.0.25 where x=0.5 and -y= -0.25 explains it all.
This is true for all numbers from -y as an infinitesimal and x as an infinitesimal too x=1 and y=0
That number of incidents --->oo proving negative numbers (-y) x+-y = x^2 a positive number.

On Sunday, June 26, 2022 at 12:20:54 PM UTC-7, Dan joyce wrote:
> On Sunday, June 26, 2022 at 2:00:00 PM UTC-4, mitchr...@gmail.com wrote:
> > On Sunday, June 26, 2022 at 9:05:25 AM UTC-7, Dan joyce wrote:
> > > On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
> > > > On 6/25/2022 1:34 PM, Dan joyce wrote:
> > > > >
> > > > > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> > > > >
> > > > > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> > > > >
> > > > > Where the sqrt of -1 is the second half of the equation above --
> > > > > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > > > > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > > > > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > > > > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > > > > going in the positive and the mirror image going into the negative.
> > > > > Just enter the above equation into Wolfram Alpha using any number.
> > > > > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> > > > >
> > > > > Just having some fun. ;-)!!!
> > > > Check this out:
> > > >
> > > > https://youtu.be/d0vY0CKYhPY
> > > >
> > > > ;^)
> > > Interesting.
> > > The many different crazy places pi will appear.
> > > I just used pi as one of the ---> oo numbers that work in this equation.
> > >
> > > I did this plot in the third quadrant where each new frame was a continuation of
> > > the last frame. So the parabolic curve keeps slightly increasing the distance from the
> > > -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
> > > reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
> > > and y=0. Where x+y=x^2
> > > A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
> > > x + y=x^2 from the first quadrant.
> > > That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
> > > Duplicating the same part of the parabola in the first quadrant --
> > > x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
> > > but only equal too -1 in the third quadrant.
> > > Negative integer points of -x\-y in the parabola in the third quadrant --
> > > -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5
> > The square root of negative one is known to be imaginary.
> > And rightly so. It is not reality.
> >
> >
> > Mitchell Raemsch
> Well, if you believe that the Cartesian coordinate system is valid then negative numbers are valid.
> x+-y=x^2 in a simple math equation .05+ -.0.25 where x=0.5 and -y= -0.25 explains it all.
> This is true for all numbers from -y as an infinitesimal and x as an infinitesimal too x=1 and y=0
> That number of incidents --->oo proving negative numbers (-y) x+-y = x^2 a positive number.

Negative numbers are just subtraction of positive in any equation.

Mitchell Raemsch

On Sat Jun 25 13:34:06 2022 Dan joyce wrote:
>
> sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
>
> Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
>
> Where the sqrt of -1 is the second half of the equation above --
> (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> Where -y =-.05 and x=0 starts the plot into the third quadrant.
> A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> going in the positive and the mirror image going into the negative.
> Just enter the above equation into Wolfram Alpha using any number.
> pi(in this case),e , golden ratio, the primes etc. giving the same results.
>
> Just having some fun. ;-)!!!
>
> Dan
>

*
Actually pi is equal to the ratio of log(-1) to sqrt(-1). (Principal value of the log)

Interesting, since both log(-1) and sqrt(-1) are imaginary!

sqrt(-1) = i
Log(-1) = i pi

This was shown by Augustus de Morgan in about 1850 (?).

earle
*

On Sunday, June 26, 2022 at 12:05:25 PM UTC-4, Dan joyce wrote:
> On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
> > On 6/25/2022 1:34 PM, Dan joyce wrote:
> > >
> > > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> > >
> > > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> > >
> > > Where the sqrt of -1 is the second half of the equation above --
> > > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > > going in the positive and the mirror image going into the negative.
> > > Just enter the above equation into Wolfram Alpha using any number.
> > > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> > >
> > > Just having some fun. ;-)!!!
> > Check this out:
> >
> > https://youtu.be/d0vY0CKYhPY
> >
> > ;^)
> Interesting.
> The many different crazy places pi will appear.
> I just used pi as one of the ---> oo numbers that work in this equation.
>
> I did this plot in the third quadrant where each new frame was a continuation of
> the last frame. So the parabolic curve keeps slightly increasing the distance from the
> -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
> reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
> and y=0. Where x+y=x^2
> A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
> x + y=x^2 from the first quadrant.
> That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
> Duplicating the same part of the parabola in the first quadrant --
> x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
> but only equal too -1 in the third quadrant.
> Negative integer points of -x\-y in the parabola in the third quadrant --
> -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5

Explaining this plot in the third quadrant---
The third quadrant of the Cartesian coordinate system = -x\-y is the minus quadrant
opposed to the first quadrant where x\y is the plus quadrant.

These points on the parabola in the third quadrant of the Cartesian coordinate
system start @ y=-0.5 and x=0
So the first y=-0.5 is not in the -y calculations below but that part of the
parabola that falls only in the third quadrant.
Seeing this as a flip mirror image of the standard x+y= x^2 in the first quadrant
and in it's mirror image flipped state reflex's only that part of the parabola
falling in the 3rd quadrant .

(((sqrt(1*4+2))-2)/2) *-1 =-x=-0.2247448713...then -y=-0.7752551287... -x here represents
the square root of -1 where -x+-y= -1
(((sqrt(2*4+2))-2)/2)*-1 = -x=-0.58113883...then -y= -1.41886117...
(((sqrt(e*4+2))-2)/2) *-1 = -x=-0.7939570308...then -y= -1.9243247976...
(((sqrt(3*4+2))-2)/2)*-1 = -x=-0.8708286933...then -y= -2.1291713067...
(((sqrt(pi*4+2))-2)/2)*-1 = -x=-0.9082957458...then -y= -2.2332969077...
(((sqrt(3.5*4+2))-2)/2)*-1 = -x=-1 then -y= -2.5
(((sqrt(4*4+2))-2)/2)*-1 = -x= -1.1213203435... then -y= -2.8786796565...
(((sqrt(5*4+2))-2)/2)*-1 = -x= -1.3452078799... then -y= -3.6547921201...
(((sqrt(6*4+2))-2)/2)*-1 = -x= -1.5495097567 then -y= -4.4504902433
(((sqrt(7*4+2))-2)/2)*-1 = -x= -1.7386127875...then -y= -5.2613872124...
(((sqrt(8*4+2))-2)/2)*-1 = -x= -1.9154759474...then -y= -6.0845240525... .
(((sqrt(8.5*4+2))-2)/2)*-1= -x=-2 then -y=6.5 | .
....

A certain way to do the squaring and square root function in the third negative
quadrant where -x+-y= (-x^2) only by a special formula ((((sqrt(n*4+2))-2)/2)*-1 .
Where n can be any number that will represent the two plotted points
on the reversed mirror image of the parabola -x+-y.

Just a novel way to express negative values.

On 6/26/2022 10:59 AM, mitchr...@gmail.com wrote:
> On Sunday, June 26, 2022 at 9:05:25 AM UTC-7, Dan joyce wrote:
>> On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
>>> On 6/25/2022 1:34 PM, Dan joyce wrote:
>>>>
>>>> sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
>>>>
>>>> Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
>>>>
>>>> Where the sqrt of -1 is the second half of the equation above --
>>>> (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
>>>> Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
>>>> Where -y =-.05 and x=0 starts the plot into the third quadrant.
>>>> A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
>>>> going in the positive and the mirror image going into the negative.
>>>> Just enter the above equation into Wolfram Alpha using any number.
>>>> pi(in this case),e , golden ratio, the primes etc. giving the same results.
>>>>
>>>> Just having some fun. ;-)!!!
>>> Check this out:
>>>
>>> https://youtu.be/d0vY0CKYhPY
>>>
>>> ;^)
>> Interesting.
>> The many different crazy places pi will appear.
>> I just used pi as one of the ---> oo numbers that work in this equation.
>>
>> I did this plot in the third quadrant where each new frame was a continuation of
>> the last frame. So the parabolic curve keeps slightly increasing the distance from the
>> -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
>> reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
>> and y=0. Where x+y=x^2
>> A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
>> x + y=x^2 from the first quadrant.
>> That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
>> Duplicating the same part of the parabola in the first quadrant --
>> x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
>> but only equal too -1 in the third quadrant.
>> Negative integer points of -x\-y in the parabola in the third quadrant --
>> -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5
>
> The square root of negative one is known to be imaginary.
> And rightly so. It is not reality.

Have you ever plotted the point (0, 1) using some graph paper? That is
the imaginary unit i.

On Wednesday, June 29, 2022 at 6:15:36 PM UTC-4, Chris M. Thomasson wrote:
> On 6/26/2022 10:59 AM, mitchr...@gmail.com wrote:
> > On Sunday, June 26, 2022 at 9:05:25 AM UTC-7, Dan joyce wrote:
> >> On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
> >>> On 6/25/2022 1:34 PM, Dan joyce wrote:
> >>>>
> >>>> sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> >>>>
> >>>> Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> >>>>
> >>>> Where the sqrt of -1 is the second half of the equation above --
> >>>> (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> >>>> Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> >>>> Where -y =-.05 and x=0 starts the plot into the third quadrant.
> >>>> A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> >>>> going in the positive and the mirror image going into the negative.
> >>>> Just enter the above equation into Wolfram Alpha using any number.
> >>>> pi(in this case),e , golden ratio, the primes etc. giving the same results.
> >>>>
> >>>> Just having some fun. ;-)!!!
> >>> Check this out:
> >>>
> >>> https://youtu.be/d0vY0CKYhPY
> >>>
> >>> ;^)
> >> Interesting.
> >> The many different crazy places pi will appear.
> >> I just used pi as one of the ---> oo numbers that work in this equation.
> >>
> >> I did this plot in the third quadrant where each new frame was a continuation of
> >> the last frame. So the parabolic curve keeps slightly increasing the distance from the
> >> -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
> >> reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
> >> and y=0. Where x+y=x^2
> >> A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
> >> x + y=x^2 from the first quadrant.
> >> That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
> >> Duplicating the same part of the parabola in the first quadrant --
> >> x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
> >> but only equal too -1 in the third quadrant.
> >> Negative integer points of -x\-y in the parabola in the third quadrant --
> >> -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5
> >
> > The square root of negative one is known to be imaginary.
> > And rightly so. It is not reality.
> Have you ever plotted the point (0, 1) using some graph paper? That is
> the imaginary unit i.

Meaning, x=0 and y=1?

On 6/29/2022 4:55 PM, Dan joyce wrote:
> On Wednesday, June 29, 2022 at 6:15:36 PM UTC-4, Chris M. Thomasson wrote:
>> On 6/26/2022 10:59 AM, mitchr...@gmail.com wrote:
>>> On Sunday, June 26, 2022 at 9:05:25 AM UTC-7, Dan joyce wrote:
>>>> On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
>>>>> On 6/25/2022 1:34 PM, Dan joyce wrote:
>>>>>>
>>>>>> sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
>>>>>>
>>>>>> Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
>>>>>>
>>>>>> Where the sqrt of -1 is the second half of the equation above --
>>>>>> (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
>>>>>> Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
>>>>>> Where -y =-.05 and x=0 starts the plot into the third quadrant.
>>>>>> A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
>>>>>> going in the positive and the mirror image going into the negative.
>>>>>> Just enter the above equation into Wolfram Alpha using any number.
>>>>>> pi(in this case),e , golden ratio, the primes etc. giving the same results.
>>>>>>
>>>>>> Just having some fun. ;-)!!!
>>>>> Check this out:
>>>>>
>>>>> https://youtu.be/d0vY0CKYhPY
>>>>>
>>>>> ;^)
>>>> Interesting.
>>>> The many different crazy places pi will appear.
>>>> I just used pi as one of the ---> oo numbers that work in this equation.
>>>>
>>>> I did this plot in the third quadrant where each new frame was a continuation of
>>>> the last frame. So the parabolic curve keeps slightly increasing the distance from the
>>>> -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
>>>> reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
>>>> and y=0. Where x+y=x^2
>>>> A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
>>>> x + y=x^2 from the first quadrant.
>>>> That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
>>>> Duplicating the same part of the parabola in the first quadrant --
>>>> x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
>>>> but only equal too -1 in the third quadrant.
>>>> Negative integer points of -x\-y in the parabola in the third quadrant --
>>>> -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5
>>>
>>> The square root of negative one is known to be imaginary.
>>> And rightly so. It is not reality.
>> Have you ever plotted the point (0, 1) using some graph paper? That is
>> the imaginary unit i.
>
> Meaning, x=0 and y=1?

Yes. The 2d point (x, y), (0, 1) is at the same point as the imaginary
unit 0+1i

On Wednesday, June 29, 2022 at 8:09:06 PM UTC-4, Chris M. Thomasson wrote:
> On 6/29/2022 4:55 PM, Dan joyce wrote:
> > On Wednesday, June 29, 2022 at 6:15:36 PM UTC-4, Chris M. Thomasson wrote:
> >> On 6/26/2022 10:59 AM, mitchr...@gmail.com wrote:
> >>> On Sunday, June 26, 2022 at 9:05:25 AM UTC-7, Dan joyce wrote:
> >>>> On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
> >>>>> On 6/25/2022 1:34 PM, Dan joyce wrote:
> >>>>>>
> >>>>>> sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> >>>>>>
> >>>>>> Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> >>>>>>
> >>>>>> Where the sqrt of -1 is the second half of the equation above --
> >>>>>> (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> >>>>>> Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> >>>>>> Where -y =-.05 and x=0 starts the plot into the third quadrant.
> >>>>>> A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> >>>>>> going in the positive and the mirror image going into the negative.
> >>>>>> Just enter the above equation into Wolfram Alpha using any number.
> >>>>>> pi(in this case),e , golden ratio, the primes etc. giving the same results.
> >>>>>>
> >>>>>> Just having some fun. ;-)!!!
> >>>>> Check this out:
> >>>>>
> >>>>> https://youtu.be/d0vY0CKYhPY
> >>>>>
> >>>>> ;^)
> >>>> Interesting.
> >>>> The many different crazy places pi will appear.
> >>>> I just used pi as one of the ---> oo numbers that work in this equation.
> >>>>
> >>>> I did this plot in the third quadrant where each new frame was a continuation of
> >>>> the last frame. So the parabolic curve keeps slightly increasing the distance from the
> >>>> -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
> >>>> reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
> >>>> and y=0. Where x+y=x^2
> >>>> A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
> >>>> x + y=x^2 from the first quadrant.
> >>>> That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
> >>>> Duplicating the same part of the parabola in the first quadrant --
> >>>> x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
> >>>> but only equal too -1 in the third quadrant.
> >>>> Negative integer points of -x\-y in the parabola in the third quadrant --
> >>>> -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5
> >>>
> >>> The square root of negative one is known to be imaginary.
> >>> And rightly so. It is not reality.
> >> Have you ever plotted the point (0, 1) using some graph paper? That is
> >> the imaginary unit i.
> >
> > Meaning, x=0 and y=1?
> Yes. The 2d point (x, y), (0, 1) is at the same point as the imaginary
> unit 0+1i

So this entails the first and second quadrant where y is always a positive value?
So what quadrant does it actually fall into or is it shared by both 1st and second quadrant?
Or is the Cartesian coordinate system not designed for imaginary (i) because it is a 2d plain rather
than a 3d plain? Isn't (i) actually in the 3d plain?

"Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> writes:

> On 6/26/2022 10:59 AM, mitchr...@gmail.com wrote:

>> The square root of negative one is known to be imaginary.
>> And rightly so. It is not reality.
>
> Have you ever plotted the point (0, 1) using some graph paper? That is
> the imaginary unit i.

Hmm... That's just a mark on a piece of paper. What makes i what it is
are its arithmetic properties. These can be represented geometrically,
but its the arithmetic that matters, not the point on a graph.

--
Ben.

On 6/29/2022 5:52 PM, Ben Bacarisse wrote:
> "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> writes:
>
>> On 6/26/2022 10:59 AM, mitchr...@gmail.com wrote:
>
>>> The square root of negative one is known to be imaginary.
>>> And rightly so. It is not reality.
>>
>> Have you ever plotted the point (0, 1) using some graph paper? That is
>> the imaginary unit i.
>
> Hmm... That's just a mark on a piece of paper. What makes i what it is
> are its arithmetic properties. These can be represented geometrically,
> but its the arithmetic that matters, not the point on a graph.
>

Ivho, plotting the point on a graph can be useful for a visual
representation. For instance, plotting 0+1i and 0-1i can visually show
the result of adding pi to 0+1i in polar form. the 1 means we are using
the unit circle.

On 6/29/2022 11:31 PM, Chris M. Thomasson wrote:
> On 6/29/2022 5:52 PM, Ben Bacarisse wrote:
>> "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> writes:
>>
>>> On 6/26/2022 10:59 AM, mitchr...@gmail.com wrote:
>>
>>>> The square root of negative one is known to be imaginary.
>>>> And rightly so. It is not reality.
>>>
>>> Have you ever plotted the point (0, 1) using some graph paper? That is
>>> the imaginary unit i.
>>
>> Hmm... That's just a mark on a piece of paper.  What makes i what it is
>> are its arithmetic properties.  These can be represented geometrically,
>> but its the arithmetic that matters, not the point on a graph.
>>
>
> Ivho, plotting the point on a graph can be useful for a visual
> representation. For instance, plotting 0+1i and 0-1i can visually show
> the result of adding pi to 0+1i in polar form. the 1 means we are using
> the unit circle.

When I say unit circle I mean the radius of the imaginary unit is one.

Dan joyce formulated on Wednesday :
> On Wednesday, June 29, 2022 at 8:09:06 PM UTC-4, Chris M. Thomasson wrote:
>> On 6/29/2022 4:55 PM, Dan joyce wrote:
>>> On Wednesday, June 29, 2022 at 6:15:36 PM UTC-4, Chris M. Thomasson wrote:
>>>> On 6/26/2022 10:59 AM, mitchr...@gmail.com wrote:
>>>>> On Sunday, June 26, 2022 at 9:05:25 AM UTC-7, Dan joyce wrote:
>>>>>> On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
>>>>>>> On 6/25/2022 1:34 PM, Dan joyce wrote:
>>>>>>>>
>>>>>>>> sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
>>>>>>>>
>>>>>>>> Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
>>>>>>>>
>>>>>>>> Where the sqrt of -1 is the second half of the equation above --
>>>>>>>> (((sqrt6)-2)/2)*-1 =
>>>>>>>> -0.22474487139158904909864203735294569598297374032833... Where -x+-y
>>>>>>>> = -1 in the third quadrant of the Cartesian coordinate system Where
>>>>>>>> -y =-.05 and x=0 starts the plot into the third quadrant. A mirror
>>>>>>>> image of the x + y= x^2 plot starting at y=-.25 part of the parabola
>>>>>>>> going in the positive and the mirror image going into the negative.
>>>>>>>> Just enter the above equation into Wolfram Alpha using any number.
>>>>>>>> pi(in this case),e , golden ratio, the primes etc. giving the same
>>>>>>>> results.
>>>>>>>>
>>>>>>>> Just having some fun. ;-)!!!
>>>>>>> Check this out:
>>>>>>>
>>>>>>> https://youtu.be/d0vY0CKYhPY
>>>>>>>
>>>>>>> ;^)
>>>>>> Interesting.
>>>>>> The many different crazy places pi will appear.
>>>>>> I just used pi as one of the ---> oo numbers that work in this equation.
>>>>>>
>>>>>> I did this plot in the third quadrant where each new frame was a
>>>>>> continuation of the last frame. So the parabolic curve keeps slightly
>>>>>> increasing the distance from the -y axis. This part of the curve starts
>>>>>> @ x=0 and -y= -0.5. An exact duplicate of its' reverse mirror image of
>>>>>> the side of the parabola in the first quadrant starting @ x=1 and y=0.
>>>>>> Where x+y=x^2 A whole different calculation is required in the third
>>>>>> quadrant for x + y=x^2 to duplicate x + y=x^2 from the first quadrant.
>>>>>> That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
>>>>>> Duplicating the same part of the parabola in the first quadrant --
>>>>>> x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in
>>>>>> the first quadrant. but only equal too -1 in the third quadrant.
>>>>>> Negative integer points of -x\-y in the parabola in the third quadrant
>>>>>> -- -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x =
>>>>>> -4\-y = -20.5 , -x = -5\-y = -30.5
>>>>>
>>>>> The square root of negative one is known to be imaginary.
>>>>> And rightly so. It is not reality.
>>>> Have you ever plotted the point (0, 1) using some graph paper? That is
>>>> the imaginary unit i.
>>>
>>> Meaning, x=0 and y=1?
>> Yes. The 2d point (x, y), (0, 1) is at the same point as the imaginary
>> unit 0+1i
>
> So this entails the first and second quadrant where y is always a positive
> value? So what quadrant does it actually fall into or is it shared by both
> 1st and second quadrant? Or is the Cartesian coordinate system not designed
> for imaginary (i) because it is a 2d plain rather than a 3d plain? Isn't (i)
> actually in the 3d plain?

No, it really differs in that it cannot be visualized as a line (one
dimension) like some other sets since it has binomials as elements.

On Wednesday, June 29, 2022 at 6:03:36 PM UTC-4, Dan joyce wrote:
> On Sunday, June 26, 2022 at 12:05:25 PM UTC-4, Dan joyce wrote:
> > On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
> > > On 6/25/2022 1:34 PM, Dan joyce wrote:
> > > >
> > > > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> > > >
> > > > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> > > >
> > > > Where the sqrt of -1 is the second half of the equation above --
> > > > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > > > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > > > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > > > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > > > going in the positive and the mirror image going into the negative.
> > > > Just enter the above equation into Wolfram Alpha using any number.
> > > > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> > > >
> > > > Just having some fun. ;-)!!!
> > > Check this out:
> > >
> > > https://youtu.be/d0vY0CKYhPY
> > >
> > > ;^)
> > Interesting.
> > The many different crazy places pi will appear.
> > I just used pi as one of the ---> oo numbers that work in this equation.
> >
> > I did this plot in the third quadrant where each new frame was a continuation of
> > the last frame. So the parabolic curve keeps slightly increasing the distance from the
> > -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
> > reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
> > and y=0. Where x+y=x^2
> > A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
> > x + y=x^2 from the first quadrant.
> > That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
> > Duplicating the same part of the parabola in the first quadrant --
> > x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
> > but only equal too -1 in the third quadrant.
> > Negative integer points of -x\-y in the parabola in the third quadrant --
> > -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5
> Explaining this plot in the third quadrant---
> The third quadrant of the Cartesian coordinate system = -x\-y is the minus quadrant
> opposed to the first quadrant where x\y is the plus quadrant.
>
> These points on the parabola in the third quadrant of the Cartesian coordinate
> system start @ y=-0.5 and x=0
> So the first y=-0.5 is not in the -y calculations below but that part of the
> parabola that falls only in the third quadrant.
> Seeing this as a flip mirror image of the standard x+y= x^2 in the first quadrant
> and in it's mirror image flipped state reflex's only that part of the parabola
> falling in the 3rd quadrant .
>
> (((sqrt(1*4+2))-2)/2) *-1 =-x=-0.2247448713...then -y=-0.7752551287... -x here represents
> the square root of -1 where -x+-y= -1
> (((sqrt(2*4+2))-2)/2)*-1 = -x=-0.58113883...then -y= -1.41886117...
> (((sqrt(e*4+2))-2)/2) *-1 = -x=-0.7939570308...then -y= -1.9243247976...
> (((sqrt(3*4+2))-2)/2)*-1 = -x=-0.8708286933...then -y= -2.1291713067...
> (((sqrt(pi*4+2))-2)/2)*-1 = -x=-0.9082957458...then -y= -2.2332969077...
> (((sqrt(3.5*4+2))-2)/2)*-1 = -x=-1 then -y= -2.5
> (((sqrt(4*4+2))-2)/2)*-1 = -x= -1.1213203435... then -y= -2.8786796565...
> (((sqrt(5*4+2))-2)/2)*-1 = -x= -1.3452078799... then -y= -3.6547921201...
> (((sqrt(6*4+2))-2)/2)*-1 = -x= -1.5495097567 then -y= -4.4504902433
> (((sqrt(7*4+2))-2)/2)*-1 = -x= -1.7386127875...then -y= -5.2613872124...
> (((sqrt(8*4+2))-2)/2)*-1 = -x= -1.9154759474...then -y= -6.0845240525... .
> (((sqrt(8.5*4+2))-2)/2)*-1= -x=-2 then -y=6.5 | .
> ...
>
> A certain way to do the squaring and square root function in the third negative
> quadrant where -x+-y= (-x^2) only by a special formula ((((sqrt(n*4+2))-2)/2)*-1 .
> Where n can be any number that will represent the two plotted points
> on the reversed mirror image of the parabola -x+-y.
>
> Just a novel way to express negative values.

What is interesting is that----
(((sqrt(pi*4+2))-2)/2)*-1 = -x=-0.9082957458...then -y= -2.2332969077... summed =pi
The ratio of -y/-x = 2.4587772407... above is where both summed = pi but the ratio applied to
the first quadrant where x+y =x^2 then add 1 to the above ratio 2.458777240...+1= 3.4587772407...
and you have x= 3.4587772407... and y= 7.2209119859 giving the same ratio between -x/-y and x/y.
This is probably true for all numbers.

On Thursday, June 30, 2022 at 8:26:43 AM UTC-4, Dan joyce wrote:
> On Wednesday, June 29, 2022 at 6:03:36 PM UTC-4, Dan joyce wrote:
> > On Sunday, June 26, 2022 at 12:05:25 PM UTC-4, Dan joyce wrote:
> > > On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
> > > > On 6/25/2022 1:34 PM, Dan joyce wrote:
> > > > >
> > > > > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> > > > >
> > > > > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> > > > >
> > > > > Where the sqrt of -1 is the second half of the equation above --
> > > > > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > > > > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > > > > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > > > > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > > > > going in the positive and the mirror image going into the negative.
> > > > > Just enter the above equation into Wolfram Alpha using any number.
> > > > > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> > > > >
> > > > > Just having some fun. ;-)!!!
> > > > Check this out:
> > > >
> > > > https://youtu.be/d0vY0CKYhPY
> > > >
> > > > ;^)
> > > Interesting.
> > > The many different crazy places pi will appear.
> > > I just used pi as one of the ---> oo numbers that work in this equation.
> > >
> > > I did this plot in the third quadrant where each new frame was a continuation of
> > > the last frame. So the parabolic curve keeps slightly increasing the distance from the
> > > -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
> > > reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
> > > and y=0. Where x+y=x^2
> > > A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
> > > x + y=x^2 from the first quadrant.
> > > That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
> > > Duplicating the same part of the parabola in the first quadrant --
> > > x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
> > > but only equal too -1 in the third quadrant.
> > > Negative integer points of -x\-y in the parabola in the third quadrant --
> > > -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5
> > Explaining this plot in the third quadrant---
> > The third quadrant of the Cartesian coordinate system = -x\-y is the minus quadrant
> > opposed to the first quadrant where x\y is the plus quadrant.
> >
> > These points on the parabola in the third quadrant of the Cartesian coordinate
> > system start @ y=-0.5 and x=0
> > So the first y=-0.5 is not in the -y calculations below but that part of the
> > parabola that falls only in the third quadrant.
> > Seeing this as a flip mirror image of the standard x+y= x^2 in the first quadrant
> > and in it's mirror image flipped state reflex's only that part of the parabola
> > falling in the 3rd quadrant .
> >
> > (((sqrt(1*4+2))-2)/2) *-1 =-x=-0.2247448713...then -y=-0.7752551287... -x here represents
> > the square root of -1 where -x+-y= -1
> > (((sqrt(2*4+2))-2)/2)*-1 = -x=-0.58113883...then -y= -1.41886117...
> > (((sqrt(e*4+2))-2)/2) *-1 = -x=-0.7939570308...then -y= -1.9243247976...
> > (((sqrt(3*4+2))-2)/2)*-1 = -x=-0.8708286933...then -y= -2.1291713067...
> > (((sqrt(pi*4+2))-2)/2)*-1 = -x=-0.9082957458...then -y= -2.2332969077...
> > (((sqrt(3.5*4+2))-2)/2)*-1 = -x=-1 then -y= -2.5
> > (((sqrt(4*4+2))-2)/2)*-1 = -x= -1.1213203435... then -y= -2.8786796565...
> > (((sqrt(5*4+2))-2)/2)*-1 = -x= -1.3452078799... then -y= -3.6547921201...
> > (((sqrt(6*4+2))-2)/2)*-1 = -x= -1.5495097567 then -y= -4.4504902433
> > (((sqrt(7*4+2))-2)/2)*-1 = -x= -1.7386127875...then -y= -5.2613872124...
> > (((sqrt(8*4+2))-2)/2)*-1 = -x= -1.9154759474...then -y= -6.0845240525... .
> > (((sqrt(8.5*4+2))-2)/2)*-1= -x=-2 then -y=6.5 | .
> > ...
> >
> > A certain way to do the squaring and square root function in the third negative
> > quadrant where -x+-y= (-x^2) only by a special formula ((((sqrt(n*4+2))-2)/2)*-1 .
> > Where n can be any number that will represent the two plotted points
> > on the reversed mirror image of the parabola -x+-y.
> >
> > Just a novel way to express negative values.
> What is interesting is that----
> (((sqrt(pi*4+2))-2)/2)*-1 = -x=-0.9082957458...then -y= -2.2332969077... summed =pi
> The ratio of -y/-x = 2.4587772407... above is where both summed = pi but the ratio applied to
> the first quadrant where x+y =x^2 then add 1 to the above ratio 2.458777240...+1= 3.4587772407...
> and you have x= 3.4587772407... and y= 7.2209119859 giving the same ratio between -x/-y and x/y.
> This is probably true for all numbers.

I should have stated, add 1 to the above ratio 2.458777240...+1= 3.4587772407... and this ratio
becomes the new x value in the first quadrant. Giving the same ratio of -x/-y from the third quadrant that
when summed -x+-y = -pi .

The same with e and any other number.

On Thursday, June 30, 2022 at 11:59:58 AM UTC-4, Dan joyce wrote:
> On Thursday, June 30, 2022 at 8:26:43 AM UTC-4, Dan joyce wrote:
> > On Wednesday, June 29, 2022 at 6:03:36 PM UTC-4, Dan joyce wrote:
> > > On Sunday, June 26, 2022 at 12:05:25 PM UTC-4, Dan joyce wrote:
> > > > On Sunday, June 26, 2022 at 12:50:12 AM UTC-4, Chris M. Thomasson wrote:
> > > > > On 6/25/2022 1:34 PM, Dan joyce wrote:
> > > > > >
> > > > > > sqrt(-1) = -0.22474487139158904909864203735294569598297374032833...
> > > > > >
> > > > > > Pi * ((sqrt6)+2)*(((sqrt6)-2)/2)*-1 = -pi
> > > > > >
> > > > > > Where the sqrt of -1 is the second half of the equation above --
> > > > > > (((sqrt6)-2)/2)*-1 = -0.22474487139158904909864203735294569598297374032833...
> > > > > > Where -x+-y = -1 in the third quadrant of the Cartesian coordinate system
> > > > > > Where -y =-.05 and x=0 starts the plot into the third quadrant.
> > > > > > A mirror image of the x + y= x^2 plot starting at y=-.25 part of the parabola
> > > > > > going in the positive and the mirror image going into the negative.
> > > > > > Just enter the above equation into Wolfram Alpha using any number.
> > > > > > pi(in this case),e , golden ratio, the primes etc. giving the same results.
> > > > > >
> > > > > > Just having some fun. ;-)!!!
> > > > > Check this out:
> > > > >
> > > > > https://youtu.be/d0vY0CKYhPY
> > > > >
> > > > > ;^)
> > > > Interesting.
> > > > The many different crazy places pi will appear.
> > > > I just used pi as one of the ---> oo numbers that work in this equation.
> > > >
> > > > I did this plot in the third quadrant where each new frame was a continuation of
> > > > the last frame. So the parabolic curve keeps slightly increasing the distance from the
> > > > -y axis. This part of the curve starts @ x=0 and -y= -0.5. An exact duplicate of its'
> > > > reverse mirror image of the side of the parabola in the first quadrant starting @ x=1
> > > > and y=0. Where x+y=x^2
> > > > A whole different calculation is required in the third quadrant for x + y=x^2 to duplicate
> > > > x + y=x^2 from the first quadrant.
> > > > That is where the third quadrant value of the sqrt -1 = ((sqrt6)-2)/2
> > > > Duplicating the same part of the parabola in the first quadrant --
> > > > x= (((sqrt6)-2)/2)+1 and y = 1- (((sqrt6)-2)/2) then x+y = x^2 = 2 in the first quadrant.
> > > > but only equal too -1 in the third quadrant.
> > > > Negative integer points of -x\-y in the parabola in the third quadrant --
> > > > -x = -1 \-y = -2.5 , -x = -2 \-y = -6.5 , -x = -3\-y = -12.5 , -x = -4\-y = -20.5 , -x = -5\-y = -30.5
> > > Explaining this plot in the third quadrant---
> > > The third quadrant of the Cartesian coordinate system = -x\-y is the minus quadrant
> > > opposed to the first quadrant where x\y is the plus quadrant.
> > >
> > > These points on the parabola in the third quadrant of the Cartesian coordinate
> > > system start @ y=-0.5 and x=0
> > > So the first y=-0.5 is not in the -y calculations below but that part of the
> > > parabola that falls only in the third quadrant.
> > > Seeing this as a flip mirror image of the standard x+y= x^2 in the first quadrant
> > > and in it's mirror image flipped state reflex's only that part of the parabola
> > > falling in the 3rd quadrant .
> > >
> > > (((sqrt(1*4+2))-2)/2) *-1 =-x=-0.2247448713...then -y=-0.7752551287... -x here represents
> > > the square root of -1 where -x+-y= -1
> > > (((sqrt(2*4+2))-2)/2)*-1 = -x=-0.58113883...then -y= -1.41886117...
> > > (((sqrt(e*4+2))-2)/2) *-1 = -x=-0.7939570308...then -y= -1.9243247976...
> > > (((sqrt(3*4+2))-2)/2)*-1 = -x=-0.8708286933...then -y= -2.1291713067...
> > > (((sqrt(pi*4+2))-2)/2)*-1 = -x=-0.9082957458...then -y= -2.2332969077...
> > > (((sqrt(3.5*4+2))-2)/2)*-1 = -x=-1 then -y= -2.5
> > > (((sqrt(4*4+2))-2)/2)*-1 = -x= -1.1213203435... then -y= -2.8786796565...
> > > (((sqrt(5*4+2))-2)/2)*-1 = -x= -1.3452078799... then -y= -3.6547921201...
> > > (((sqrt(6*4+2))-2)/2)*-1 = -x= -1.5495097567 then -y= -4.4504902433
> > > (((sqrt(7*4+2))-2)/2)*-1 = -x= -1.7386127875...then -y= -5.2613872124...
> > > (((sqrt(8*4+2))-2)/2)*-1 = -x= -1.9154759474...then -y= -6.0845240525... .
> > > (((sqrt(8.5*4+2))-2)/2)*-1= -x=-2 then -y=6.5 | .
> > > ...
> > >
> > > A certain way to do the squaring and square root function in the third negative
> > > quadrant where -x+-y= (-x^2) only by a special formula ((((sqrt(n*4+2))-2)/2)*-1 .
> > > Where n can be any number that will represent the two plotted points
> > > on the reversed mirror image of the parabola -x+-y.
> > >
> > > Just a novel way to express negative values.
> > What is interesting is that----
> > (((sqrt(pi*4+2))-2)/2)*-1 = -x=-0.9082957458...then -y= -2.2332969077... summed =pi
> > The ratio of -y/-x = 2.4587772407... above is where both summed = pi but the ratio applied to
> > the first quadrant where x+y =x^2 then add 1 to the above ratio 2.458777240...+1= 3.4587772407...
> > and you have x= 3.4587772407... and y= 7.2209119859 giving the same ratio between -x/-y and x/y.
> > This is probably true for all numbers.
> I should have stated, add 1 to the above ratio 2.458777240...+1= 3.4587772407... and this ratio
> becomes the new x value in the first quadrant. Giving the same ratio of -x/-y from the third quadrant that
> when summed -x+-y = -pi .
>
> The same with e and any other number.

There is a direct correlation between the first quadrant x\y where x^2 = x + y = x^2 and the third quadrant
where -x\-y where -x+-y = -1 then -1+ x= -y . -x= (((sqrt6)-2)/2)*-1 = -0.2247448713...-( -1) = 0.7752551286*-1 = -0.7752551286... The ratio of -y/-x = 3.4494897427... Now add 1 to the ratio =4.4494897427... and this becomes the new x in the first quadrant where x+y=x^2 and the ratio y/x 3.4494897427... the same ratio from the third quadrant -x/-y. Also subtract 2 from x in the first quadrant
4.4494897427 -2 = (sqrt6). That is how -x is produced in the third quadrant.
So not too far fetched to say--- (sqrt-1) = -0.2247448713... ;-)

Dan