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tech / sci.math / How would you calculate.. 15 Liters with the T.d.i. ?

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* How would you calculate.. 15 Liters with the T.d.i. ?Socratis T.n.p.
`- Re: How would you calculate.. 15 Liters with the T.d.i. ?Socratis T.n.p.

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How would you calculate.. 15 Liters with the T.d.i. ?

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Subject: How would you calculate.. 15 Liters with the T.d.i. ?
From: andreaso...@gmail.com (Socratis T.n.p.)
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 by: Socratis T.n.p. - Sun, 18 Sep 2022 17:34 UTC

How would you calculate.. 15 Liters with the T.d.i. ?
Thanks..

Greetings from Socratis T.n.p. 6^3 +7^3 =13*43m^2 = 559m^3

Re: How would you calculate.. 15 Liters with the T.d.i. ?

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Subject: Re: How would you calculate.. 15 Liters with the T.d.i. ?
From: andreaso...@gmail.com (Socratis T.n.p.)
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 by: Socratis T.n.p. - Mon, 19 Sep 2022 16:12 UTC

How would you calculate.. 15 Liters with the T.d.i. ?
Thanks...
How would you calculate .. 25 Liters with the T.d.i. ?
Thanks...

It would seem that the T.d.i. cannot calculate the product of 2 masses..
But he actually finds them as derivatives of m^3...0.1^3 = 0.001 m^3 = 1 liter.
0.1*0.3*0.5=0.015m^3=15.kg.as; 0.1*0.5*0.5=0.025m^3=25kg.

You can use the T.n.p. Which means: 1i * 3i * 5i =15i^3...e..1i * 5i * 5i = 25i^3
So 1i * 15i * 25i = 375i^3 = 375kg... better than perfect... it's impossible...
So sooner or later... The world will have the T.n.p. from 1mm.

But what about the T.d.i.? Not...sure: 0.01m^3 * 0.1m^3 = 0.001m^3 = 1 litre... True?
You should say 1i * 10i * 100i = 1000i^3. These are difficult calculations to use with the T.d.i.
as disabled to be derived from m^2 and m^3. having ..0.1.= 1dm..0.01.etc.

Greetings from Socratis T.n.p. => 6^3 +8^3 = 14 *52m^2 = 728m^3

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