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tech / sci.math / The logic of the T.d.i. it is deduced from the T.n.p.

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* The logic of the T.d.i. it is deduced from the T.n.p.Achille S
+- Re: The logic of the T.d.i. it is deduced from the T.n.p.Revo Metanurm
`* Re: The logic of the T.d.i. it is deduced from the T.n.p.Achille S
 `* Re: The logic of the T.d.i. it is deduced from the T.n.p.Achille S
  `* Re: The logic of the T.d.i. it is deduced from the T.n.p.Achille S
   `* Re: The logic of the T.d.i. it is deduced from the T.n.p.Achille S
    `* Re: The logic of the T.d.i. it is deduced from the T.n.p.Achille S
     `- Re: The logic of the T.d.i. it is deduced from the T.n.p.Achille S

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The logic of the T.d.i. it is deduced from the T.n.p.

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Subject: The logic of the T.d.i. it is deduced from the T.n.p.
From: achilles...@gmail.com (Achille S)
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 by: Achille S - Thu, 10 Nov 2022 23:51 UTC

0.02 * 1 = 0.02m^2 =200c^2 => per 0.02 = 2c
Alias : 2c * 100c = 200cm^2 => per 2c = 0.02

10c*100c =0.1m^2 = 1000c^2 => per 10c =1i
1i * 10i = 0.1m^2 ===== 10i^2
30c*100c = 0.3m^2 ==300c^2 => per 30c = 3i.
3i * 10i = 0.3m^2 ===== 30i^2 => per 3i = 30c.
5i * 10i = 0.5m^2 ===== 50i^2
7i * 10i = 0.7m^2 ===== 70i^2
10i *10i = 1m^2 ===== 100i^2 => fine delle Aree.

The volumes ... have a factor of 10i + of the Areas. for which we have::
1i *10i * 10i = 0.1m^3 = 100i^3 => da 10i^2 *10i si ha 100i^3.
3i *10i * 10i = 0.3m^3 = 300i^3 => da 30i^2 *10i si ha 300i^3
5i *10i * 10i = 0.5m^3 = 500i^3 => da 50i^2 *10i si ha 500i^3.
7i *10i * 10i = 0.7m^3 = 700i^3
9i *10i * 10i = 0.9m^3 = 900i^3
10i *10i *10i ==1m^3 = 1000i^3 => da 100i^2 *10i si ha 1000i^3.

If you want you can rewrite them in: 0.1m and 1m .. that does not change anything ..
If not to fool you a bit, since .. 0.1 is done on purpose- :)))
In fact: 0.01 = 1c ==> 0.1 = 1i = 10c ==> 1 = 1000 • = 100c .. = 10i

Greetings from Socratis => If you don't understand ... Try again .. suffice ..
to know that three Factors Cannot .. nor should they give .. an Area.
So saying 3m is fine but don't forget that 3m = 30i.
So if..30i *30i = 900i^2 = 9m^2 => 30i *30i *30i = 27'000i^3 - :)))

Re: The logic of the T.d.i. it is deduced from the T.n.p.

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Subject: Re: The logic of the T.d.i. it is deduced from the T.n.p.
From: man077...@hotmail.com (Revo Metanurm)
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 by: Revo Metanurm - Fri, 11 Nov 2022 12:15 UTC

There is no logic, because of the fact, that Your spirit has existed maximally for the half of the age of universe and it can exist more that time, but this is logically the end of the universe, but the feeling says that it cannot be the end. That indicates, that there is no logic.

Call me if You want to answer and do it quicker: + 372 5 6 3 3 0 6 8 7

Re: The logic of the T.d.i. it is deduced from the T.n.p.

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Subject: Re: The logic of the T.d.i. it is deduced from the T.n.p.
From: achilles...@gmail.com (Achille S)
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 by: Achille S - Fri, 11 Nov 2022 23:54 UTC

Il giorno venerdì 11 novembre 2022 alle 00:51:21 UTC+1 Achille S ha scritto:
You are like the Zombies .. if you don't understand: 1i *10i *10i =100i^3 =100 liters.
Even less you could understand: =============> 0.1 * 1 * 1 = 0.1 m^3 =100 liters
After all, you didn't know how to solve : 0.5 *0.5 *2 = 5i *5i *20i = 500i^3 = 0.5m^3.

Like.. maybe...you don't know yet that 0.1 *1 * 10=1000i^3 > 1 *10 =1000i^2.
I should have... patience... to convince you to start with any small number..
After all, it would be enough to eliminate your loved one. Neutral 10dm. 100cm..1000mm.

But know that if I say 1i *1...the T.d.i. it only says 0.1y and takes 0.1m^2 for granted.
In fact - not knowing means .. having to change jobs .. since it does not exist
a product that gives a linear result. Unless you use my ex Tunze.

0.2 *2 = 0.4m^2 ==> 2i *20i = 40i^2
0.5 *5 = 2.5m^2 ==> 5i *50i = 250i^2
1 * 10 =10m^2 ==>10i *100i =1000i^2
0.1*1*10 =1m^3=>1i*10i*100i=1000i^3

I don't expect you to write it... but you know it... and... if asked,..you admit it.
Because, only in this way..Science, progresses, Improving people and nature- :))

Greetings from Socratis => 0.05 *0.5 *5 ==> 5c *50c *500c = 125'000c^3 = 125.litri
While you would currently say: 0.125 and that's it not knowing how to say 0..125m^3
To know ..just a little ...calculate everything in .. cm^3 .. but it is also clear that
0.125m^3 ... This in itself is ... 125 liters. I hope I have been useful .... for many- :))

Re: The logic of the T.d.i. it is deduced from the T.n.p.

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Subject: Re: The logic of the T.d.i. it is deduced from the T.n.p.
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 by: Achille S - Wed, 16 Nov 2022 14:43 UTC

Why..0.1*0.1 *100 = 1m^3..?

1) because..0.1*0.1 =1dm^2..which is the basis of dm^3 =1000c^3 =1.litre
2) because 100m =1000dm, and therefore we have..100i^2 *1000i =1000i^3
which in their verticality...or..horizontality...contain 1000.litres.

3) because ..0.1 being 1dm..you don't eat its co.factors..things
forbidden and prohibited.. by the correct function... of multiplication... that
exist in the brains of some morons, unworthy of being true Mathematicians.

Those idiots..they never understood that 0.1 *0.1 means 100c^2..
as..hundredth of the m*2. It would be enough to know that 1dm^3 = 1.litre.
And how is the liter made if not using (10c)^3 = 1000c^3 for 1c^3 = 1g.

What completes ignorance is: ignoring.. that units are always indicated, with 1.
whether it is 1mm, 1cm, 1dm, 1m, 1decametre, 1hectometre, 1.km..etc. So of.. 1*1.. yes..
should say.. 10i *10i = 100i..like 10c*10c = 100c..and since they are also surfaces,
or, Cubes.. when they are.. it is good to add the relative 100i^2..100i^3..100c^2...100c^3.

Greetings from T.n.p. i10^3 + i20^3 = i30 * (i10*i20 +i10^2) = i30 *i300 = 9000i^3 = 9m^3.
Aliases 1m^3 +2m^3 =1000i^3 +8000i^3 =9m^3. How many m^2*h=1i..it takes to have
9000i^3 ? But you don't pay attention to it .. having always been ignorant .. you wouldn't understand me-:)))

It would take 90m^2..from..100i^2..since 10i *100i = 1000i^2 = 10m^2..9 are enough.
Therefore 10m^2 * 1i = 1000i^3 = 1m^3. The only one who understands me is Bruno Campanini-:))))
But, unfortunately..the herd of the ignorant..prefers to remain in its ancient ignorance.

Re: The logic of the T.d.i. it is deduced from the T.n.p.

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Subject: Re: The logic of the T.d.i. it is deduced from the T.n.p.
From: achilles...@gmail.com (Achille S)
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 by: Achille S - Wed, 16 Nov 2022 18:33 UTC

Il giorno mercoledì 16 novembre 2022 alle 15:43:55 UTC+1 Achille S ha scritto:
> Why..0.1*0.1 *100 = 1m^3..?
>
> 1) because..0.1*0.1 =1dm^2..which is the basis of dm^3 =1000c^3 =1.litre
> 2) because 100m =1000dm, and therefore we have..100i^2 *1000i =1000i^3
> which in their verticality...or..horizontality...contain 1000.litres.
>
> 3) because ..0.1 being 1dm..you don't eat its co.factors..things
> forbidden and prohibited.. by the correct function... of multiplication.... that
> exist in the brains of some morons, unworthy of being true Mathematicians..
>
> Those idiots..they never understood that 0.1 *0.1 means 100c^2..
> as..hundredth of the m*2. It would be enough to know that 1dm^3 = 1.litre.
> And how is the liter made if not using (10c)^3 = 1000c^3 for 1c^3 = 1g.
>
> What completes ignorance is: ignoring.. that units are always indicated, with 1.
> whether it is 1mm, 1cm, 1dm, 1m, 1decametre, 1hectometre, 1.km..etc. So of.. 1*1.. yes..
> should say.. 10i *10i = 100i..like 10c*10c = 100c..and since they are also surfaces,
> or, Cubes.. when they are.. it is good to add the relative 100i^2..100i^3...100c^2...100c^3.
>
> Greetings from T.n.p. i10^3 + i20^3 = i30 * (i10*i20 +i10^2) = i30 *i300 = 9000i^3 = 9m^3.
> Aliases 1m^3 +2m^3 =1000i^3 +8000i^3 =9m^3. How many m^2*h=1i..it takes to have
> 9000i^3 ? But you don't pay attention to it .. having always been ignorant .. you wouldn't understand me-:)))
>
> It would take 90m^2..from..100i^2..since 10i *100i = 1000i^2 = 10m^2...9 are enough.
> Therefore 10m^2 * 1i = 1000i^3 = 1m^3. The only one who understands me is Bruno Campanini-:))))
> But, unfortunately..the herd of the ignorant..prefers to remain in its ancient ignorance.

0.i *1i *1i =1hg = 0.0001m^3
1c*10c*10c = 1hg == 100c^3

>1i *1i *1i == 1i^3 == 0.001m^3
10c*10c*10c =1000c^3=1dm^3

>1i * 1i *10i == 10i^3 == 0.01m^3
10c*10c*100c =10.000c^3 =10kg

>1i *10i *10i === 100i^3 === 0.1m^3
10c *100c*100c=100'000c^3=100kg

The T.n.p. it's very simple, it already has small numbers, and it uses them..
It is not clear why Scientists should use dx. -:)))
How can you not understand that 1dm = 10c . and 1c. = 10mm. ?

Did you.. think that 10c*10c=1i^2=100c^2= 0.01 of 10'000c^2=1m^2 ?
So do it now, if you want to understand what you've always been wrong.
believing that 0,01m^2..refers to 1m.Linear, so it would be 1cm .

Greetings from T.n.p. True Math 10i *20i =200i^2 =2m^2.
The big mistake is to use 1m... which is... unity instead of 10i...
Indeed :10i*10i*10i =1000i^3. that could not be argued-:)))

Re: The logic of the T.d.i. it is deduced from the T.n.p.

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Subject: Re: The logic of the T.d.i. it is deduced from the T.n.p.
From: achilles...@gmail.com (Achille S)
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 by: Achille S - Sat, 19 Nov 2022 17:09 UTC

On Saturday 19 November 2022 at 12:19:23 UTC+1 Achille S wrote:
> Too bad that 0.02m^3 = 20i^3..assuming that.. some..
> ignorant If you wanted to understand..enough..0.02*1000 = 20 -:)))

0.1 *10i = 0.1m^2
0.1 *20i = 0.2m^2
0.1 *30i = 0.3m^2
0.1 *40i = 0.4m^2
0.1 *50i = 0.5m^2
0.1 *60i = 0.6m^2
0.1 *70i = 0.7m^2
0.1 *80i = 0.8m^2
0.1 *90i = 0.9m^2
0.1 *100i = 1.m^2

In fact, the T.d.i. from..0.1 as 10i.20i.30i..100i..are taken for granted on X.
If you don't believe it, divide 1/0.1 =10i...2/0.1 = 20i....3/0.1 =30i....10/0.1 =100i -:)))
Not accepting it means not respecting the derivative system and taking advantage of it.
to..say that the T.d.i. both Linear. Absurd thing, and unacceptable..

This is demonstrated by the smaller volumes of 1.m^3, which you should always name as :
0.1*0.1*1 = 0.01.m^3 ​​=10i^3
0.1 *1 *1 = 0.1.m^3 ​​= 100i^3
0.1 *2 *2 = 0.4.m^3 = 400i^3..etc.

1 *1 *1 = 1.m^3 ​​= 1000i^3
1 *2 *2 = 4.m^3 = 4000i^3
2 *2 *2 = 8.m^3 = 8000i^3...etc.

More than Explaining it.. I can't do it.. but, I do it to have a clear conscience.
If..for this..you would like to burn me..it's your business that will ruin your existence.
Since I know that you know it very well, but, you don't have the courage to admit it.

Greetings from T.n.p. = 7i *14i *28i = i14^3 ==== 2'744i^3. = 2.744m^3
===========> 70i *140i *280i = i140^2 =2'744'000i^3 = 2'744m^3
After all, it is enough to know that 3.factors..must only generate..Volumes..-:)))

Re: The logic of the T.d.i. it is deduced from the T.n.p.

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Subject: Re: The logic of the T.d.i. it is deduced from the T.n.p.
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 by: Achille S - Sun, 20 Nov 2022 05:24 UTC

0.1 * 10i = 0.1m^2
0.1 * 20i = 0.2m^2 ==> for 20i = 2m
0.1 * 30i = 0.3m^2
0.1 * 40i = 0.4m^2
0.1 * 50i = 0.5m^2
0.1 * 60i = 0.6m^2 ==> for 60i = 6m
0.1 * 70i = 0.7m^2
0.1 * 80i = 0.8m^2
0.1 * 90i = 0.9m^2
0.1 * 100i = 1.m^2 => for 100i=10m.

So.. the T.d.i. would give. 0.n.. from 0.1* 10i.20i.30i.100i. which are taken for granted on X.
Therefore it must be understood that these 0.n.. He considers them as derived from m^2.. 1.inclusive..
Because it is evident that 1i *10 equals 1dm*10m =1dm *100dm=100dm^2 =1m^2.
If you don't believe it.. just divide 1/0.1=10i...2/0.1=20i...3/0.1=30i...10/0.1=100i -:))

At this point it is evident that the error depends on Peano who called 0.1. the dm..and.. not
he thought he could call it 1i..where 1i represents 1dm, taking up less space than 0.1.
Unfortunately this makes you think.. wrong that 1dm. eat its co-factors ..... but it's false
if :1*10 =10i*100i =1000i^2 =10m^2..by adding 0.1=z we have 1dm*10dm *100dm = 1000i^3.

However always Error is .. since nobody writes that 1dm*10dm*100dm=1000dm^3=1m^3
So it is as useful as necessary to eliminate 0.1, using 1i instead of 0.1..and letting 1..
whatever it is..10i..= 10dm...Only in this way can we return to True Logic and gain space...
so Nobody could be wrong...1i*10m =1i *100i =100i^2..like 1i*10i*10i=100i^3.
I would point out that the two are the same number of 1i units being 10i*10i=100i=10m.

As far as the Linear functions are concerned, they are made starting from the neutral: 1..small from which you start..
so you can start from any number..small..that is present and you need for the calculation
small..And this implies to use 1m for what it is ..that is 10i...in the presence of 1i..while 1m is
Neutral if you start from 1m. Because..they are all 1 it is clear..Since we only have one of 1...
So we have to say 1m...as 1dm..as 1c...as 1•. The same goes for the various 10...20...etc.-:))

Greetings from T.n.p. Starting from 1i we would have:
1i *20i = 20i^2.. and...1i *1i *20i = 20i^3 ..while :
1 * 20 = 20m^2. and... 1 *1 *20 = 20m^3.
Correct me if I'm wrong: it's complicated.. condensing everything well -:)))

Re: The logic of the T.d.i. it is deduced from the T.n.p.

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 by: Achille S - Mon, 21 Nov 2022 08:26 UTC

If.. it is true that 2m =20dm => 2/0.1 = 20dm

===> 20i *20i== 400i^2 => 0.1=1dm.
=> 2i *20i *20i = 800i^3.....So :
2dm *2m *2m = 0.8m^3 = 800.dm^3

So why don't you scientists report it as 0.8m^3 ?
Use 2i, instead of 0.2. He wouldn't let you.. make a mistake.
It's..maybe you would become Scientists evolved as well as correct-:)))

Greetings from Socratis =>10i *10i *10i =1000i^3.=> 5i*5i*5i= 125.dm^3.
=======================> 50c *50c *50c = 125'000c^3 = 125.dm^3.
===============> 500• *500• *500• =125'000'000mm^3 = 125.dm^3.

===============> It would appear that any (half.m)^3 = 125.dm^3.
also says the T.d.i... derivative, with 0.5^3 = 0.125m^3 = 125.dm^3.
It would appear that you... Scientists....don't see 0.5 as....half.m.

Maybe... you see 0.5m.. as a number.. with no. dimension so that..
0.5 *0.5 = 0.25 of 1m.Linear...and not like 25i^2 = 1/4 of m^2 True ?
Do you think the same of 0.1*0.1 = 0.01m.Linear and not as 0.01m^2 ?

Unfortunately think wrong, it is a serious mistake to think that 10c*10c = 1c.
if I can tell you.. know that no product.. is <= of its factors :
0.1*0.1*1000dm =1000dm^3.. Alias ​​1i *1i *100 =1m^3.=>1000i=100m.

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