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tech / sci.math / Re: AP's 256th book of science// Correcting the Units of Physics-- Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium

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AP's 256th book of science// Correcting the Units of Physics-- Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium

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Subject: AP's 256th book of science// Correcting the Units of Physics--
Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium
From: plutoniu...@gmail.com (Archimedes Plutonium)
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 by: Archimedes Plutonium - Sun, 11 Jun 2023 19:12 UTC

AP's 256th book of science// Correcting the Units of Physics-- Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium

Units of Force = mass (acceleration) = mass_0 (distance/time^2)
Units of Angular Momentum = mass_1 (distance^2/time)

If we multiply the two together we have mass_2 (distance^3/ time^3)

And Old Physics has no concept of these units. This is a gap and fault of Old Physics.

This book aims to explore and detail the meaning of Mass (distance^3/time^3)

AP, King of Science, especially Physics & Logic

Re: AP's 256th book of science// Correcting the Units of Physics-- Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium

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Subject: Re: AP's 256th book of science// Correcting the Units of Physics--
Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium
From: plutoniu...@gmail.com (Archimedes Plutonium)
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 by: Archimedes Plutonium - Mon, 12 Jun 2023 06:11 UTC

On Sunday, June 11, 2023 at 2:12:56 PM UTC-5, Archimedes Plutonium wrote:
> AP's 256th book of science// Correcting the Units of Physics-- Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium
>
> Units of Force = mass (acceleration) = mass_0 (distance/time^2)
> Units of Angular Momentum = mass_1 (distance^2/time)
>
> If we multiply the two together we have mass_2 (distance^3/ time^3)
>
> And Old Physics has no concept of these units. This is a gap and fault of Old Physics.
>
> This book aims to explore and detail the meaning of Mass (distance^3/time^3)

Now one thing that has bothered me immensely for the past 2 decades, ever since I realized All is Atom and Atoms are nothing but electricity and magnetism-- being the primal axiom over all sciences.

And if you know a lot about electricity and magnetism-- it seems to be a 2 dimensional phenomenon for the most part. Current stays on the surface, not inside. The Lines of Force are 2 dimensional. Perpendicular is 2 dimensional.

So electricity and magnetism are 2D in large part.

Yet we all know the Cosmos, Space, Universe is 3rd dimensional.

So in this book I want to hopefully finally bring clarity to the fact that Electricity and Magnetism are 2D while the whole of the Universe is 3D. And maybe that is the clue to conquering Mass (distance^3/time^3).

And whether we have Kinetic Energy as 1/2 mass v^2 or EM energy as mass (speed of light)^2 where we have just exponent 2 and not 3, this book needs to clarify why physics is in exponent 2 and not exponent 3.

AP

Re: AP's 256th book of science// Correcting the Units of Physics-- Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium

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Subject: Re: AP's 256th book of science// Correcting the Units of Physics--
Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium
From: plutoniu...@gmail.com (Archimedes Plutonium)
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 by: Archimedes Plutonium - Mon, 12 Jun 2023 07:01 UTC

Now we normally think of Energy in Physics as the ultimate all encompassing concept, yet we are sort of surprised, those who love physics, surprised that it comes in a mere exponent 2, either Kinetic Energy or Relativistic Energy E = mass(speed of light)^2.

In mathematics we are not so befuddled, for there we have in geometry, we have Volume to be the all encompassing geometry, of exponent 3.

So why the disparity? And we know electricity and magnetism are often 2 dimensional. Could it be the Wave Nature of electricity and magnetism is causing this disparity?

If we look at Halliday & Resnick PHYSICS, Part 2, Extended Version, 1986 units:

Voltage = kg*m^2/(A*s^3)

Current = A*s

Electric Resistance = kg*m^2/(A^2*s^3) and already Halliday & Resnick made a mistake for that does not give V = iR with a error in seconds.

Magnetic Field = kg/(A*s^2)

Electric Field = kg*m/(A*s^3)

And so, what would straighten out and correct Halliday & Resnick units for that of V= iR as Old Physics Ohm's law is this. Make Current be A*meters rather than A*seconds.

Then we have V = iR and equal to (A*m)( kg*m^2/(A^2*s^3)) = kg*m^3/(A*s^3) and of course Halliday & Resnick's Voltage should be kg*m^3/(A*s^3).

Now AP has New Ohm's Law, where Ohm's law is not stuck on high current or high voltage. And New Ohm's law is Voltage = Coulomb*Magnetic field*Electric field. This makes Ohm's law a universal law of physics, whereas Old Physics Ohm's law is a "rule" not a law.

So, what AP is shooting for is Voltage = kg*m^3/(A*s^3) and so, how can I get that from magnetic field, electric field and current?

AP makes this adjustment:

B = Magnetic Field = kg*m/(A*s^2)
E = Electric Field = kg*m/(A*s^2)

Current = A*meter*second

When I multiply V = C*B*E = kg^2 * m^3/ (A*s^3) with a caution note on kilograms is scalar and so kg^2 is seen as kg.

Old Physics had the error filled Maxwell Equations saying no magnetic monopole exists. Well, it does exist and is the 0.5MeV particle that JJ Thomson discovered in 1897, mistaking it for the Atom's electron. The muon is the true electron of atoms stuck inside a 840MeV proton torus doing the Faraday law.

With the fact of the existence of Magnetic Monopoles. Then the units of Magnetic Field must equal the units of Electric Field.

AP

Re: AP's 256th book of science// Correcting the Units of Physics-- Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium

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Subject: Re: AP's 256th book of science// Correcting the Units of Physics--
Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium
From: plutoniu...@gmail.com (Archimedes Plutonium)
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 by: Archimedes Plutonium - Mon, 12 Jun 2023 07:16 UTC

On Monday, June 12, 2023 at 2:00:00 AM UTC-5, Archimedes Plutonium wrote:
>
> AP makes this adjustment:
>
> B = Magnetic Field = kg*m/(A*s^2)
> E = Electric Field = kg*m/(A*s^2)
>
> Current = A*meter*second
>
> When I multiply V = C*B*E = kg^2 * m^3/ (A*s^3) with a caution note on kilograms is scalar and so kg^2 is seen as kg.
>
> Old Physics had the error filled Maxwell Equations saying no magnetic monopole exists. Well, it does exist and is the 0.5MeV particle that JJ Thomson discovered in 1897, mistaking it for the Atom's electron. The muon is the true electron of atoms stuck inside a 840MeV proton torus doing the Faraday law.
>
> With the fact of the existence of Magnetic Monopoles. Then the units of Magnetic Field must equal the units of Electric Field.
>

However, there is one more problem with this. For years I have argued that Electric Field is the same units as Angular Momentum. Angular momentum is kg * meters^2/seconds

So once again I need to adjust magnetic and electric fields in order to end up with kg * m^3/ (A*s^3) for Voltage .

E = Electric Field = kg*m^2/(A*s^2)
B = Magnetic Field = kg*m/(A*s^2)
Current = A*second

There, that delivers to me the Voltage as a exponent 3, 3rd dimension.

Voltage = C*B*E = kg * m^3/ (A*s^3) where kg is scalar and thus kg^2 is denoted as kg.

AP

Re: AP's 256th book of science// Correcting the Units of Physics-- Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium

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Subject: Re: AP's 256th book of science// Correcting the Units of Physics--
Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium
From: plutoniu...@gmail.com (Archimedes Plutonium)
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 by: Archimedes Plutonium - Mon, 12 Jun 2023 07:35 UTC

Now in mathematics, volume is exponent 3 and is Volume = L*W*H for rectangular box. And is unmistakeable as to its meaning.

In Physics, Voltage is often seen as a form of pressure.

Halliday & Resnick, 1986 PHYSICS has pressure units.

Pressure = kg/(m*s^2)

Force = kg*m/s^2

Energy = kg*m^2/s^2

Through the decades I have been wavering as to whether Voltage is pressure. And have thought of Voltage more as like Volume of mathematics, all encompassing.

I am going to attempt to translate the concept of pressure into mathematics.

AP

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Subject: Re: AP's 256th book of science// Correcting the Units of Physics--
Magnetic Field-Electric Field-Current// Theoretical Physics, by Archimedes Plutonium
From: plutoniu...@gmail.com (Archimedes Plutonium)
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 by: Archimedes Plutonium - Mon, 12 Jun 2023 19:21 UTC

On Monday, June 12, 2023 at 2:01:52 AM UTC-5, Archimedes Plutonium wrote:
> Now we normally think of Energy in Physics as the ultimate all encompassing concept, yet we are sort of surprised, those who love physics, surprised that it comes in a mere exponent 2, either Kinetic Energy or Relativistic Energy E = mass(speed of light)^2.
>
> In mathematics we are not so befuddled, for there we have in geometry, we have Volume to be the all encompassing geometry, of exponent 3.
>
> So why the disparity? And we know electricity and magnetism are often 2 dimensional. Could it be the Wave Nature of electricity and magnetism is causing this disparity?
>
> If we look at Halliday & Resnick PHYSICS, Part 2, Extended Version, 1986 units:
>
> Voltage = kg*m^2/(A*s^3)
>
> Current = A*s
>
> Electric Resistance = kg*m^2/(A^2*s^3) and already Halliday & Resnick made a mistake for that does not give V = iR with a error in seconds.
>

Alright, I am forgetting that Halliday & Resnick are Old Physics, a physics that had no magnetic monopole, a physics that was asymmetrical in its Maxwell Equations, and worst of all a physics that was missing a true electron-- the muon, and current to them is simply A, amperes and not A*s.
For Halliday & Resnick did not have the Magnetic Monopole which charge is the magnetic monopole.

Current = A in Old Physics

So that A times kg*m^2/(A^2*s^3) does yield the voltage kg*m^2/(A*s^3)

> Magnetic Field = kg/(A*s^2)
>

The Old Physics Magnetic Field tells me exactly what the confusing Pressure units are. For we think in terms of pressure and force are really one and the same.

Halliday & Resnick, 1986 PHYSICS has pressure units.

Pressure = kg/(m*s^2)

Force = kg*m/s^2

Energy = kg*m^2/s^2

In Force, the numerator has two entities-- mass and distance divided by seconds. In Pressure the numerator has just one entity, a scalar mass, and something is not correct here.

The Fix.

The fix involves the idea that All is Atom and Atoms are nothing but electricity and magnetism. Force is half of a EM wave circuit and Pressure is the other half of this EM wave circuit. Gravity is the Push and Pull of a electric current pushing Earth by the Sun's half EM wave and that is a force of push. The pull of Earth by the Sun is the other half of EM wave circuit. So the Push by the Sun on Earth in its revolution is a force of kg*m/s^2. The other half is a direction of Pull, what is called Electromagnetic Potential and is opposite direction so the meters becomes part of the denominator, taking it out of the numerator as in force. So pressure in New Physics is 1/2 of a EM wave circuit, while force is the other 1/2 of a EM wave circuit.. And the reason the meters is in the denominator in pressure is indication that it is backwards from force.

> Electric Field = kg*m/(A*s^3)
>
> And so, what would straighten out and correct Halliday & Resnick units for that of V= iR as Old Physics Ohm's law is this. Make Current be A*meters rather than A*seconds.
>
> Then we have V = iR and equal to (A*m)( kg*m^2/(A^2*s^3)) = kg*m^3/(A*s^3) and of course Halliday & Resnick's Voltage should be kg*m^3/(A*s^3).
>
> Now AP has New Ohm's Law, where Ohm's law is not stuck on high current or high voltage. And New Ohm's law is Voltage = Coulomb*Magnetic field*Electric field. This makes Ohm's law a universal law of physics, whereas Old Physics Ohm's law is a "rule" not a law.
>
> So, what AP is shooting for is Voltage = kg*m^3/(A*s^3) and so, how can I get that from magnetic field, electric field and current?
>
> AP makes this adjustment:
>
> B = Magnetic Field = kg*m/(A*s^2)
> E = Electric Field = kg*m/(A*s^2)
>
> Current = A*meter*second

I think that is correct for a current needs time and substance-- a distance to move on.

>
> When I multiply V = C*B*E = kg^2 * m^3/ (A*s^3) with a caution note on kilograms is scalar and so kg^2 is seen as kg.
>
> Old Physics had the error filled Maxwell Equations saying no magnetic monopole exists. Well, it does exist and is the 0.5MeV particle that JJ Thomson discovered in 1897, mistaking it for the Atom's electron. The muon is the true electron of atoms stuck inside a 840MeV proton torus doing the Faraday law.
>
> With the fact of the existence of Magnetic Monopoles. Then the units of Magnetic Field must equal the units of Electric Field.
>
1> AP, King of Science, especially Physics and Logic

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