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tech / sci.math / Re: Refutation of Able - Ruffini, and Galois Theorems

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o Re: Refutation of Able - Ruffini, and Galois Theoremsbassam karzeddin

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Re: Refutation of Able - Ruffini, and Galois Theorems

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Subject: Re: Refutation of Able - Ruffini, and Galois Theorems
From: b.karzed...@yahoo.com (bassam karzeddin)
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 by: bassam karzeddin - Mon, 4 Sep 2023 22:00 UTC

On Wednesday, April 19, 2017 at 6:00:10 PM UTC+3, bassam king karzeddin wrote:
> > Based on my recent posts including irrefutable proofs
> > and new definition for the real existing numbers,
> > , one simply can refute many well established
> > theorems in old mathematics, using those new simple
> > proven concepts, for sure
> >
> > I had some rigorous many examples that are indeed
> > d can invalidate all those old fake theorems that
> > were built upon clear wrong understanding of what is
> > the truth of the real existing numbers
> >
> > Any talented a mature or professional mathematicians
> > s is welcomed to participate in this very sensitive
> > issue gladly
> >
> > So, this is an announcement of the horrible death of
> > f the fundamental theorem of algebra, for sure
> >
> > Regards
> > Bassam King Karzeddin
> > 17 th, April, 2017
> There are many polynomials that have not any single root for sure
>
> For very simple example that had been proven here quite many times and at Quora
>
> Famous example: the polynomial (x^3 - 2 = 0), I know that mathematics simply say one real root being as 2^{1/3}, and then they find other two complex roots
>
> But all this juggling would fall immediately once you adopt the INTEGER analysis I introduced, so let us analyses it more carefully
>
> Of course (x) can not be any integer since this would contradict Fermat's last theorem, because if (x = n) where (n) is integer, then you have
> (n^3 = 1^3 + 1^3), which of course impossible, but what do they do they express it in abstract notation as (x = 2^{1/3}), where then it is impossible to construct (x), except by clear cheating using all developed tools for actually approximation of that symbol in mind, and the approximation is generally constructible in rational numbers, that is to say they keep searching for the largest rational number in decimal forms for ever, that is less than 2^{1/3}, where simply it impossible existence,
>
> So let (x = n/m), then you have (n^3 = m^3 + m^3 = 2m^3), which is the impossibility of doubling the cube (one of the three oldest Greek impossible problems), that had been proved thousands of years back in just few minutes, and half a page only where any clever secondary school student can comprehend it immediately
>
> But this very simple problem stands as a long puzzle for the top professional mathematicians, and they insist blindly, foolishly and stubbornly that it has a solution, so wonder!
>
> Their solutions are actually in mind only as meaning less notation, because how a problem which is refuted by NUMBER THEORY can simply have a solution, wonder!
>
> And helplessly they hide behind meaningless, unreal and non existing concept call infinity that represent the Paradise for them to keep adding so many meaningless numbers for ever
>
> So, the whole issue here is the business of infinity, otherwise what else can they do?
>
> They are so lazy to have a real meaningful work and deluding themselves as a good thinkers, and they were so lazy and so incompetent generally to get admission in other Engineering and Scientific branches, that require higher IQ, plus more talented in mathematics in particular
>
> So, from this only so simple point of view, the Cubic root operation or any other higher odd root operation for a non cube numbers or generally non p-th power number is completely flawed operation, so unlike the square root operation that is supported by the Pythagoras greatest theorem for sure
>
> At this point all the works done by those old mathematicians to solve polynomial equations was based five operations as (+, -, *, /, and p-th root)
>
> So, one operation is simply and very easily Refutable, hence all their results are also Refuted for sure
>
> But still polynomial may have some times only real constructible roots, where
>
> Polynomial equations are simply the same as Diophantine equations
>
> Regards
> Bassam King Karzeddin
> 19th, April, 2017

See how the absolute impossibility of Doubling the cube problem is still incomprehensible by the vast majorities of mainstream academic mathematicians & alikes

Now, how can one trust with human academic mathematickers if they were truly & completely so delusional about a too elementary problems since thousands of years? Wonder!

Why don't they arrange a world conference to rediscuss & rediscover the missing truth about this long standing problem 🤔?

No matter if the truth is so ugly & very disappointing to ALL humans on earth & the sky as well!

An ugly truth is still far better than many sweet fallacies FOR SURE

BKK

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