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tech / sci.math / Re: Why does Fermat's last theorem invalidate all alleged real arithmetical numbers of this form (q^{1/p})?

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o Re: Why does Fermat's last theorem invalidate all alleged realbassam karzeddin

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Re: Why does Fermat's last theorem invalidate all alleged real arithmetical numbers of this form (q^{1/p})?

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Subject: Re: Why does Fermat's last theorem invalidate all alleged real
arithmetical numbers of this form (q^{1/p})?
From: b.karzed...@yahoo.com (bassam karzeddin)
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 by: bassam karzeddin - Fri, 22 Sep 2023 10:49 UTC

On Saturday, December 23, 2017 at 3:54:42 PM UTC+2, bassam king karzeddin wrote:
> On Saturday, December 9, 2017 at 5:45:59 PM UTC+3, bassam king karzeddin wrote:
> > Where, (p > 2, q) are prime numbers
> >
> > Of course, this was proven to you over and over in my posts at the sci.math, the Math forum, and Quora, plus Stalk Exchange (where they had hidden my proofs earlier)
> >
> > So, I thought those people might understand by the time, but it seems so hopeless case with the vast majorities of them, so I repeated the Question for them thinking that the smart professionals would finally get my hints, but immediately was downvoted and closed, refusing to even have a little chance to understand their dogmatic old beliefs about real numbers were completely non-sense and so meaningless
> >
> > link:
> > https://mathoverflow.net/questions/288089/why-does-fermats-last-theorem-invalidate-the-existence-of-many-real-algebraic-n?noredirect=1#comment713057_288089
> >
> > So, can a smart clever professional who correctly understands my simplest proofs save those dogmatic people from their own minds, please?
> >
> > or must I teach every professional mathematician alone about those very simple facts that do require only a drop of humanity first and a drop of intelligence second? wonder!
> >
> > Presently, I'm not allowed to post at MSE nor at HSE
> > And since this was the last place for me to post at Overflow Mathematics at SE SO, Please rescue those astray people before they go mad, for sure
> >
> > Regards
> > Bassam King Karzeddin
> > Dec. 9th, 2017
> A very rigorous proof (that nobody on earth can deny) would be a solution to a cubic polynomial of this form and for sure
>
> So, what is the real root for this odd degree polynomial:
>
> (x^9 - x^3 - 1 = 0)
>
> Please, feel free to represent your real root to any degree of accuracy you would like to, and see how easy it contradicts the PROVEN Fermat's last theorem
>
> And if you are convensend now (after hundreds of FREE lectures) that no real root actually exists, then confess it so openly and loudly (if you have a very little drop of humanity first, and second,a very little drop of intelligence too)
> But if you still want to talk nonsense as usual, then better keep it for yourself, since it is not at all helpful, for sure
>
> Regards
> Bassam Karzeddin
> Dec. 23ed, 2017

Here, one can simply realize the illegal intellectuality of so many alleged historical Genious humans, where their fake intellectuality was based upon the unbelievable stupidity of the vast majorities of mainstream sheeples

As simple as it is just before your eyes & minds FOR SURE

BKK

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