Now there are two Logics..T.d.i...and T.n.p.
Let's see how to solve sia..in. m^3 than in m^2

If I use 0.1 *0.3 *3m..the volume is translated into function
of m^3 := 0.09. Where 0.09 *1000 = 90i^3
Like 0.3 *3 = 0.9m^2.which is nothing other than 90i^2.

While if I use the dm... I can directly define the Liters
saying: 1i *3i *30i = 90i^3. = 90-L-kg.

If I use cm: => for 0.1/0.01=10c and 3m/0.01 =300c
I can say: 10c * 30c *300c = 90'000g. = 90-kg-:)))

It goes without saying that there are small volumes..that I can calculate
good and better..using cm. Type: 5c *5c *5c = 125c^3 =125g.

To solve directly: m^2 and m^3..I invented The T.n.p. -:)))

Now there are two Logics..T.d.i...and T.n.p.
Let's see how to solve sia..in. m^3 than in m^2

If I use 0.1 *0.3 *3m..the volume is translated into function
of m^3 := 0.09. Where 0.09 *1000 = 90i^3
Like 0.3 *3 = 0.9m^2.which is nothing other than 90i^2.

While if I use the dm... I can directly define the Liters
saying: 1i *3i *30i = 90i^3. = 90-L-kg.

If I use cm: => for 0.1/0.01=10c and 3m/0.01 =300c
I can say: 10c * 30c *300c = 90'000g. = 90-kg-:)))

It goes without saying that there are small volumes..that I can calculate
good and better..using cm. Type: 5c *5c *5c = 125c^3 =125g.

To solve directly: m^2 and m^3..I invented The T.n.p. -:)))
10•)^3 = 1g.
1i)^3 = 10c)^3 =1kg.
10i)^3 = 1m^3.
10)^3 = 1000m^3.
1km)^3 =1'000'000'000m^3..How much does the Earth weigh?

Because: 0.1 *0.1 = 1i^2 of.. 100i^2.

1) 1/0.1 = 10i ==> 1 *1 = 10i *10i =100i^2.
2) 0.1 *0.1 *100m = 1000i^3 for 100m/0.1 = 1000i.
3) The T.d.i. says 1 of both 1000i^3 and 100i^2, as
says: 2 *2 = 4..and not.. 400i^2 = 4Times...100i^2.. like
says 1i *100i = 1..like 5i *20i = 1 and not Not 100i^2-:)))

We have the 5 Logical Reasons why this is the case. But if..
you don't want to reason and understand.. It's up to you to change jobs.
Maybe you will make the 3 Cards of the Milanese Street Jugglers who...
they make the winning cards disappear from under their noses... chickens... :)))

Greetings T.n.p. √1i^2 = 142 mm. scarce Alias 14cm abundant-:)))

Now there are two Logics..T.d.i...and T.n.p.
Let's see how to solve sia..in. m^3 than in m^2

If I use 0.1 *0.3 *3m..the volume is translated into function
of m^3 := 0.09. Where 0.09 *1000 = 90i^3
Like 0.3 *3 = 0.9m^2.which is nothing other than 90i^2.

While if I use the dm... I can directly define the Liters
saying: 1i *3i *30i = 90i^3. = 90-L-kg.

If I use cm: => for 0.1/0.01=10c and 3m/0.01 =300c
I can say: 10c * 30c *300c = 90'000g. = 90-kg-:)))

It goes without saying that there are small volumes..that I can calculate
good and better..using cm. Type: 5c *5c *5c = 125c^3 =125g.

To solve directly: m^2 and m^3..I invented The T.n.p. -:)))