Why start with 1i?

Since 1m = 10i..I can say that:
5i *10i = 50i^2 ==> 1i *5i *10i = 50i^3
5i *20i = 100i^2 => 1i *5i *20i = 100i^3.
5i *100i = 500i^2 =>1i *5i *100i = 500i^3

You do not see this correctness by doing everything wrong:
0.5*1 = 0.5m^2 ==> 0.1*0.5 *1 = 0.05m^3 =50i^3
0.5 *2 = 1m^2 ===> 0.1 *0.5 *2 = 0.1m^3 = 100i^3
0.5 *10 = 5m^2 ==> 0.1 *0.5 *10 = 0.5m^3 =500i^3

10i *10i = 100i^2 => 10i *10i *10i = 1000i^3 =for you 1
10i *20i = 200i^2 => 10i *10i *20i = 2000i^3 =for you 2
10i *30i = 300i^2 => 10i *10i *30i = 3000i^3.=for you 3

Regards T.n.p.=> 1^3 +2^3 +3^3 =1 *6 *6 = 36m^3.-:)))
=======> 1^3 +2^2 +3^3 +4^3 =1 *10*10=100m^3-:)))

Il giorno venerdì 10 novembre 2023 alle 16:05:02 UTC+1 Socratis T.n.p. ha scritto:
> Why start with 1i?
>
> Since 1m = 10i..I can say that:
> 5i *10i = 50i^2 ==> 1i *5i *10i = 50i^3
> 5i *20i = 100i^2 => 1i *5i *20i = 100i^3.
> 5i *100i = 500i^2 =>1i *5i *100i = 500i^3
>
> You do not see this correctness by doing everything wrong:
> 0.5*1 = 0.5m^2 ==> 0.1*0.5 *1 = 0.05m^3 =50i^3
> 0.5 *2 = 1m^2 ===> 0.1 *0.5 *2 = 0.1m^3 = 100i^3
> 0.5 *10 = 5m^2 ==> 0.1 *0.5 *10 = 0.5m^3 =500i^3
>
> 10i *10i = 100i^2 => 10i *10i *10i = 1000i^3 =for you 1
> 10i *20i = 200i^2 => 10i *10i *20i = 2000i^3 =for you 2
> 10i *30i = 300i^2 => 10i *10i *30i = 3000i^3.=for you 3
>
> Regards T.n.p.=> 1^3 +2^3 +3^3 =1 *6 *6 = 36m^3.-:)))
> =======> 1^3 +2^2 +3^3 +4^3 =1 *10*10=100m^3-:)))

2i *20i = 40i^2 ==> 1i *2i *20i = 40i^3.

Il giorno venerdì 10 novembre 2023 alle 18:39:11 UTC+1 Socratis T.n.p. ha scritto:
> Il giorno venerdì 10 novembre 2023 alle 16:05:02 UTC+1 Socratis T.n.p. ha scritto:
> > Why start with 1i?
> >
> > Since 1m = 10i..I can say that:
> > 5i *10i = 50i^2 ==> 1i *5i *10i = 50i^3
> > 5i *20i = 100i^2 => 1i *5i *20i = 100i^3.
> > 5i *100i = 500i^2 =>1i *5i *100i = 500i^3
> >
> > You do not see this correctness by doing everything wrong:
> > 0.5*1 = 0.5m^2 ==> 0.1*0.5 *1 = 0.05m^3 =50i^3
> > 0.5 *2 = 1m^2 ===> 0.1 *0.5 *2 = 0.1m^3 = 100i^3
> > 0.5 *10 = 5m^2 ==> 0.1 *0.5 *10 = 0.5m^3 =500i^3
> >
> > 10i *10i = 100i^2 => 10i *10i *10i = 1000i^3 =for you 1
> > 10i *20i = 200i^2 => 10i *10i *20i = 2000i^3 =for you 2
> > 10i *30i = 300i^2 => 10i *10i *30i = 3000i^3.=for you 3
> >
> > Regards T.n.p.=> 1^3 +2^3 +3^3 =1 *6 *6 = 36m^3.-:)))
> > =======> 1^3 +2^2 +3^3 +4^3 =1 *10*10=100m^3-:)))
> 2i *20i = 40i^2 ==> 1i *2i *20i = 40i^3.

If I use integers and say 0.5 *1.5 *2 = 1.5m^3
If I use the dm and say.... 5i *15i *20i = 1'500i^3

The ..2 products..are the same thing but the second is better defined as a function of litres.
The fact that they are always 2 Volumes...is understandable considering that 1.5 *2 = 3m^2...but,
Since.. 0.5 belongs to the Z axis....it means that the volume is... reduced to 1.5m^3.

In fact, if I said 1 *1.5 *2 = 3m^3, to understand it, draw the 2 graphs....for Z =5i and Z =10i.
The maximum utility that the dm give occurs for small volumes and < 1000i^3 = 1m^3, e.g.:
0.2 *0.5 = 0.2m^3. = 200i^3...While => 2i *5i *20i = 200i^3. It's a direct result -:)))

Greetings from Socratis T.n.p. Who hopes he has explained himself enough, and without errors -:)))

Why start with 1i?

On Saturday 11 November 2023 at 10:45:49 UTC+1 Socratis T.n.p. he wrote:

If I use.. the integers and say 0.5 *1.5 *2 = 1.5m^3
If I use.. the dm.. and say...5i *15i *20i = 1'500i^3

I want and must point out that from these measurements (4m) the square = 1.5 could not come
At most it is a rectangle of 2.5 *1.5 = 3.75m^3 in addition to the square... 2*2 = 4m^2.
Therefore 1.5m^3 = 1500i^3 is a volume worth 15 quintals. for 1 quintal = 100i^3.

Greetings T.n.p. Which invites you to look for a hyper.square of 2 *2 *2..meanwhile => 3√8 = 2m^3-:)))

On Saturday, November 11, 2023 at 8:04:22 AM UTC-8, Socratis T.n.p. wrote:
> Why start with 1i?
>

Because it doesn't exist.

On Saturday 11 November 2023 at 16:44:33 UTC+1 Socratis T.n.p. he wrote:
> On Saturday 11 November 2023 at 10:45:49 UTC+1 Socratis T.n.p. he wrote:

Using.. the integers I say 0.5 *1.5 *2 = 1.5m^3
Using. i dm.. I say...........5i *15i *20i = 1'500i^3

I must point out that the sum of these measurements (4m) could not give the square = 1.5
at most there is a rectangle of 2.5 *1.5 = 3.75m^2 in addition to the square.. 2*2 = 4m^2...
so 1.5m^3 = 1500i^3 is a volume worth 15 quintals. for 1 quintal = 100i^3.

Greetings T.n.p. Which invites you to look for a hyper.square of 3 *3 *3.. meanwhile => 3√27 = 3m^3-:)))
Unfortunately they taught you that 1 *2 = 2. when you just need to understand that 1i *10i *20i = 200i^3.
Mathematics only produces... m^2 from two factors and..... m^3 from 3 Factors: 0.1 *1 *2 = 0.2m^3-:)))

Il giorno sabato 11 novembre 2023 alle 18:43:43 UTC+1 mitchr...@gmail.com ha scritto:
> On Saturday, November 11, 2023 at 8:04:22 AM UTC-8, Socratis T.n.p. wrote:
> > Why start with 1i?
> >
>
> Because it doesn't exist.

0.1 = 1dm = 10cm = 1i -:)))