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tech / sci.math / Re: How to distinguish the counting of algebraic numbers from a supertask?

SubjectAuthor
* How to distinguish the counting of algebraic numbers from aWM
`* Re: How to distinguish the counting of algebraic numbers from a supertask?Eram semper recta
 `- Re: How to distinguish the counting of algebraic numbers from a supertask?Eram semper recta

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How to distinguish the counting of algebraic numbers from a supertask?

<uisohc$ib6c$5@dont-email.me>

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From: wolfgang...@tha.de (WM)
Newsgroups: sci.math
Subject: How to distinguish the counting of algebraic numbers from a
supertask?
Date: Mon, 13 Nov 2023 09:59:24 +0100
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 by: WM - Mon, 13 Nov 2023 08:59 UTC

The proof of equinumerosity by bijection between infinite sets, M and N,
is justified by mathematical induction: If every element of set M can be
related to one and only one corresponding element of set N and vice
versa, and if there is never an obstacle or halt in this process of
assignment, then both infinite sets are in bijection. "with respect to
this order we can talk about the nth algebraic number where not a single
one of this epitome (ω) has been forgotten." [E. Zermelo: "Georg Cantor
– Gesammelte Abhandlungen mathematischen und philosophischen Inhalts",
Springer, Berlin (1932) p. 116]

A supertask is a countably infinite sequence of operations that occur
sequentially within a finite interval of time.

Can you demonstrate a difference?

Regards, WM

Re: How to distinguish the counting of algebraic numbers from a supertask?

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Subject: Re: How to distinguish the counting of algebraic numbers from a supertask?
From: thenewca...@gmail.com (Eram semper recta)
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 by: Eram semper recta - Mon, 13 Nov 2023 12:33 UTC

On Monday, 13 November 2023 at 03:59:34 UTC-5, WM wrote:
> The proof of equinumerosity by bijection between infinite sets, M and N,
> is justified by mathematical induction: If every element of set M can be
> related to one and only one corresponding element of set N and vice
> versa, and if there is never an obstacle or halt in this process of
> assignment, then both infinite sets are in bijection. "with respect to
> this order we can talk about the nth algebraic number where not a single
> one of this epitome (ω) has been forgotten." [E. Zermelo: "Georg Cantor
> – Gesammelte Abhandlungen mathematischen und philosophischen Inhalts",
> Springer, Berlin (1932) p. 116]
>
> A supertask is a countably infinite sequence of operations that occur
> sequentially within a finite interval of time.
>
> Can you demonstrate a difference?

NO, because there isn't any difference.

https://www.academia.edu/108900719/Cantor_delirans_Bijective_cardinality_and_the_anti_mathematical_drivel_that_infected_mathematics

>
> Regards, WM

Re: How to distinguish the counting of algebraic numbers from a supertask?

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Subject: Re: How to distinguish the counting of algebraic numbers from a supertask?
From: thenewca...@gmail.com (Eram semper recta)
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 by: Eram semper recta - Mon, 13 Nov 2023 12:35 UTC

On Monday, 13 November 2023 at 07:33:23 UTC-5, Eram semper recta wrote:
> On Monday, 13 November 2023 at 03:59:34 UTC-5, WM wrote:
> > The proof of equinumerosity by bijection between infinite sets, M and N,
> > is justified by mathematical induction: If every element of set M can be
> > related to one and only one corresponding element of set N and vice
> > versa, and if there is never an obstacle or halt in this process of
> > assignment, then both infinite sets are in bijection. "with respect to
> > this order we can talk about the nth algebraic number where not a single
> > one of this epitome (ω) has been forgotten." [E. Zermelo: "Georg Cantor
> > – Gesammelte Abhandlungen mathematischen und philosophischen Inhalts",
> > Springer, Berlin (1932) p. 116]
> >
> > A supertask is a countably infinite sequence of operations that occur
> > sequentially within a finite interval of time.
> >
> > Can you demonstrate a difference?
> NO, because there isn't any difference.
>
> https://www.academia.edu/108900719/Cantor_delirans_Bijective_cardinality_and_the_anti_mathematical_drivel_that_infected_mathematics

The main problem with your mainstream colleagues is that their heads are so far up Cantor's colon and common sense does not reside there.

>
> >
> > Regards, WM

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