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Theorem: n *2n *4n = n2^3.

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Subject: Theorem: n *2n *4n = n2^3.
From: andreaso...@gmail.com (Socratis T.n.p.)
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by: Socratis T.n.p. - Fri, 2 Feb 2024 17:00 UTC

Theorem: n *2n *4n = n2^3.

20c *40c *80c =c40^3 =64'000c^3 =64i^3.

2i *4i *8i = i4^3 ===64i^3
3i *6i *12i = i6^3 =216i^3
4i *8i *16i = i8^3 =512i^3

5i *10i *20i = i10^3 = 1000i^3 ==== 1m^3
6i *12i *24i = i12^3 = 1'720i^3 =1.728m^3
7i *14i *28i = i14^3 = 2'744i^3 = 2.744m^3

8i *16i *32i = i16^3 = 4096i^3 = 4.096m^3
9i *18i *36i = i18^3 = 5'832i^3 = 5.832m^3
10i *20i *40i= i20^3 =8'000i^3 =====8m^3
1m *2m *4m = m2^3 == 8m^3

Happy 2024 => i5^3 +i5^3 = 5i *5i *10i =250i^3-:)))
===========> 5^3 + 5^3 = 5 *5 *10 = 250m^3-:)))
The T.n.p. allows me not to say 0.5 *0.5 *1=0.25m^3.
I invented it having understood that 1m=10i=100c=1000•.

1• *1000m = 1m^2 => 1• *1 *1000m= 1m^3
1c *100m = 1m^2 ==> 1c *1 *100m = 1m^3.
1i *100i = 1m^2 ====> 1i *10i *100i = 1m^3.

Re: Theorem: n *2n *4n = n2^3.

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Subject: Re: Theorem: n *2n *4n = n2^3.
From: andreaso...@gmail.com (Socratis T.n.p.)
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by: Socratis T.n.p. - Sat, 3 Feb 2024 00:53 UTC

Theorem: n *2 *4 = 2^3. = 8m^3

If 2i *4i *8i === i4^3 = 64i^3
2m *4m *8m = m4^3 =64m^3.

If 3i *6i *12i === i6^3 = 216i^3
3m *6m *12m = m6^3 = 216m^3

If 5i *10i *20i === i10^3 =1000i^3 = 1m^3
5m *10m *20m = m10^3 =1000m^3.

If 6i *12i *24i === i12^3 = 1'720i^3
6m *12m *24m = m12^3 = 1'720m^3.

If 1m =10dm..100cm..1000mm. it's right
that 1m^3 =1000 times 1i^3. The important is
that they are integers.. dm^3.. cm^3 and.. mm^3-:)))

This allows you to do any calculation well
Defined..without throwing away volumes < 1m^3 and
without having to decipher all the commas you use-:)))

Happy 2024 => 8^3 + 8^3 = 8 *8 *16 = 1'024m^3-:)))

Elegance and truth are inversely related. -- Becker's Razor

tech / sci.math / Theorem: n 2n 4n = n2^3.

Subject	Author
*Theorem: n 2n 4n = n2^3.*	Socratis T.n.p.
Re: Theorem: n 2n 4n = n2^3.	Socratis T.n.p.

Elegance and truth are inversely related. -- Becker's Razor

tech / sci.math / Theorem: n *2n *4n = n2^3.

tech / sci.math / Theorem: n 2n 4n = n2^3.