For those who think that "I would be an idiot" And there are many.

Examine, very carefully the Concept I Specify You:

Many of you think you have to delete the Volumes.? Saying ;
i * 2 * 10 = 2m.Lin. while it is 2m^3 => 1i * 20i * 100i = 2000i^3.
It's that simple; who understands it, even my Smart Horse, that he
knows very well that 2m = 20dm, and 10m = 100dm, as he knows
that theT.d.i. Always spit, integers in the form of linear m - :))

Beware that if you say 600m *0.1m, you are saying 6000i^2 =60m^2,It's this
is done by the T.d.i. He churns out squares from the lines we supply him .. If
do the math judiciously, perhaps you will understand that 100i^2 * 60 = 6000i^2 =60m^2
If you say: 0.1 * 0.1 * 600 => i * i * 6000i = 6000i^3 =6m^3. Seeing is believing-:))

Just believe that; "I would be an idiot" => that "you will remain idiots".
As a Logician, I am doing everything to Help You Eliminate Your Mistakes- :)))

Greetings from Socratis T.n.p.

On 5/19/2021 12:32 PM, Socratis T.n.p. wrote:
>
> Examine, very carefully the Concept I Specify You: I am idiot!
>

You are an idiot.

And you are a cretin.

Il giorno mercoledì 19 maggio 2021 alle 22:14:07 UTC+2 Buck Futter ha scritto:
> On 5/19/2021 12:32 PM, Socratis T.n.p. wrote:
> >
> > Examine, very carefully the Concept I Specify You: I am idiot!
> >
>
> You are an idiot.
>
> And you are a cretin.

Cretin is someone like you, who repeats indefinitely 4 words,
which he does not know how to justify, in practice a Robot.
Blah..blah..blah...blah...miao, miao, bau,, bau...iiiiiiiiohh iiiiiiiiiiiiiiohhhh...
ii * iiiii = iiiii iiiii....11 * 11111 = 11111 11111...
Thanks for being such an idiot

600m = 6000i
6000i*i = 60m^2
6000i *i *i = 6m^3

Socratis T.n.p.

For those who think that "I would be an idiot" And there are many.

Examine, very carefully the Concept I Specify You:

You are idiots and stay idiots- :)))
600m = 6000i
6000i * i = 60m ^ 2
6000i * i * i = 6m ^ 3.
Thanks for being cretins-;)))
But, it's not serious, you are useful for the Intelligent ..
1m ^ 2 = 100i ^ 2
1m ^ 3 = 1000i ^ 3.

Greetings from Socratis T.n.p.

Examine the Following Concept very carefully:
The system you use, without knowing it, is expressed by m^2 and m^3,
Therefore forming a square depends on two factors y * x ...

But only ; 1/10 is actually a true square, which is 10i * 10i = 100i^2.
The others, from y = 0.99m to y = 0.099m, are rectangles, of which only 3 quail to make
100i ^ 2 in the form of a rectangle; and I'm ; i * 100i (10m), .. 2i * 50i (5m) ... 5i * 20i (2m).

This "quailing" mechanism is repeated for every 10m, 50m, 100m ...
for which for example; 50m * 0.2m =10m^2 ..Alias ​​500i *2i =1000i^2 =10m^2 .. from
which you might understand that none of the; 0, m ... eat something, poor thing-;))

But you can understand that if I want the volume of 50m * 0.2 * 0.1 ...
I'll have the usual 1000i^2 * z = i, which is 1000i ^ 3 ..= 1m^3 instead of 10m^2. But,
while m^3 is defined in 3 dimensions, 10m^2 .. are defined in 2 dimensions.
Which of the two, it would be .. the greater, I leave it to you, knowing that before this
explanation You would surely have been wrong !! .. But now, you could, also, not be wrong ....

Who would have liked, please express it with a click T.n.p .. Thanks- :)))

Greetings from Socratis T.n.p. Rome. May 20.2021

But you can understand that if I want the volume of 50m * 0.2 * 0.1 ...
I'll have the usual 1000i^2 * z = i, which is 1000i ^ 3 ..= 1m^3 instead of 10m^2. But,
while m^3 is defined in 3 dimensions, 10m^2 .. are defined in 2 dimensions.
Which of the two, it would be .. the greater, I leave it to you, knowing that before this
explanation You would surely have been wrong !! .. But now, you could, also, not be wrong ....

This explains everything, starting with; i * i * 100i (10m) = 0.1m^3 = 100.L.100kg.
Like i * i * 100m = i * i * 1000i =1000i^3 = 1m^3- What you do and preach, is Wrong ..
Why you will have to find out..Not all 1s are the same.- :)))

Greetings from Socratis T.n.p. Rome. May 20.2021

On 5/20/2021 11:47 AM, Socratis T.n.p. wrote:
> *nothing*

You are an idiot.

And you are a cretin.

Il giorno giovedì 20 maggio 2021 alle 21:13:01 UTC+2 Mutt Buncher ha scritto:
> On 5/20/2021 11:47 AM, Socratis T.n.p. wrote:
> > *nothing*

i*i * 10i = 10i^3 ==> 10c *10c * 100c = 10'000c^3 = 10.L. 10kg.

Hi idiot, you don't even know that 1dm^3 = 1L,1kg.?
0.1^3 = 0.001m^3. = 1.L.1kg.
0.5^3 = 0.125m^3 = 125.L.125kg.
Greetings from Socratis T.n.p. Rome. 20.May.2021

The solution, to not remain cretins, is simple:
And it consists in considering, the Lesser Unity, of the Factors.

0.1 *0.1 *1 = 0.01m^3 ==> It is difficult to understand, which is worth 10 liters.
This is demonstrated by the fact that you don't even think about defining it in terms of m^3.
i * i * 10i = 10i^3 ==> Anyone Understands It. Sheep Including.

This is the first step to follow, to get out of blessed Ignorance- :))
i2^3 + i5^3 = i7 * (10i^2 + 9i^2) = i7 * 19i^2 = 133i^3.

Greetings from Socratis .. The benefactor who gives you the T.n.p. Rome 21. May 2021,

The solution, to not remain cretins, is too simple:

1) It consists in considering the small Unit in play as per T.n.p.

0.1 * 0.2 * 1 = 0.02m^3 ==> It is difficult to understand that it is worth 20.kg.
This is demonstrated by the fact that you don't think you can define it in terms of m^3.
i * 2i * 10i = 20i^3 ==> Anyone understands it. including hens.

2) divide a number using its decimals, to avoid 0, n.

These are the first 2 steps to follow, to get out of blessed Ignorance- :))
i2^3 + i6^3 = i8 * (12i^2 + 16i^2) = i8 * 28i^2 = 224i^3 = 224-liters-kg ... If you do
everything to decrease everything, then using the dm, would be the solution ...

Especially because ; 2i * 2 = 2i * 20i = 40i^2 ... so why call it 0.4 ???
If 1 * 1 was, really 1, then 0.2 * 2 should be, 4 times 1-
But if 40i^2..you call it 0.4 It means 1 * 1 = 100i^2 ..

Greetings from Socratis .. The researcher who gives you the T.n.p. Rome 21. May 2021,

Il giorno sabato 22 maggio 2021 alle 01:04:52 UTC+2 Socratis T.n.p. ha scritto:
> The solution, to not remain cretins, is too simple:
> 1) It consists in considering the small Unit in play as per T.n.p.

5i * 8i * 100i = 4000i^3 = 4m^3. Alias :
50c*80c*1000c = 4000'000c^3, Alias
5dm*8dm*100dm = 4'000dm^3 = 4'000.kg.

After all, what does 0.5 mean, if not 5dm..50cm, 500mm?
Don't forget that the true 1 * 1 = 100c * 100c = 10'000c^2.
Like 1^3 ================ (100c)^3 = 1'000'000cm^3.
Don't forget that; all less than 1 * 1 depend on m^2.
Like all small three-dimensional results, they depend on m^3.

Therefore the derivative slaughter is avoided, using the small units directly.
Doing neither of the two, You are Sbandati, Out of the Logic T.d.i.

Greetings from Socratis T.n.p.

On 5/23/2021 6:50 PM, Socratis T.n.p. wrote:
> Il giorno sabato 22 maggio 2021 alle 01:04:52 UTC+2 Socratis T.n.p. ha scritto:
>> The solution, to not remain cretins, is too simple:
>> 1) It consists in considering the small Unit in play as per T.n.p.

You are a cretin.

Il giorno lunedì 24 maggio 2021 alle 03:54:12 UTC+2 Señor Dingus ha scritto:
> On 5/23/2021 6:50 PM, Socratis T.n.p. wrote:
> > Il giorno sabato 22 maggio 2021 alle 01:04:52 UTC+2 Socratis T.n.p. ha scritto:
> >> The solution, to not remain cretins, is too simple:
> >> 1) It consists in considering the small Unit in play as per T.n.p.
> You are a cretin.

It is you, not to understand, how the T.d.i. system works
But you are not unique, you are a bunch of fools.

All volumes => depend on m^3.
0.2 * 3 *10 = 6m^3 => 2dm*30dm*100dm = 6'000.dm^3 = 6m^3-
0.2 = 2dm...3/0.1 = 30dm...10/0.1 = 100dm.

Greetings from T.n.p.

On Monday, May 24, 2021 at 3:30:14 AM UTC-4, Socratis T.n.p. wrote:
> Il giorno lunedì 24 maggio 2021 alle 03:54:12 UTC+2 Señor Dingus ha scritto:
> > On 5/23/2021 6:50 PM, Socratis T.n.p. wrote:
> > > Il giorno sabato 22 maggio 2021 alle 01:04:52 UTC+2 Socratis T.n.p. ha scritto:
> > >> The solution, to not remain cretins, is too simple:
> > >> 1) It consists in considering the small Unit in play as per T.n.p.
> > You are a cretin.
> It is you, not to understand, how the T.d.i. system works
> But you are not unique, you are a bunch of fools.
>
> All volumes => depend on m^3.
> 0.2 * 3 *10 = 6m^3 => 2dm*30dm*100dm = 6'000.dm^3 = 6m^3-
> 0.2 = 2dm...3/0.1 = 30dm...10/0.1 = 100dm.
>
> Greetings from T.n.p.

This thinking also requires orthogonality. Coordinate systems work fine skewed, but areas will diminish at small angle. Haven't really done the analysis recently, but maybe there is something there for you.

Il giorno giovedì 20 maggio 2021 alle 21:13:01 UTC+2 Mutt Buncher ha scritto:
> On 5/20/2021 11:47 AM, Socratis T.n.p. wrote:
> > *nothing*
> You are an idiot.

Are you a gang of fools? Or, don't you understand the T.d.i.? :

The T.d.i. I can try to explain it to you ... in my own way:
All squares depend on m^2, => 100i^2-
All volumes depend on m^3, ==> 1000i^3:

0.2 * (30i * 100i) => 2i * 3000i = 6'000i^2 = 60 (100i^2) = 60m^2.
0.2 * 3 * 10 ==> 2i * 30i * 100i = 6'000i^3 = 6 (1000i^3) = 6m^3.
As you see, the number of dm, does not change but, it changes: from i^2 to i^3.
So how do you compare 60m^2 to 6m^3 ... Unfortunately ... We don't know--
The only truth that turns out is that you are wrong to consider 60m^2 > 6m^3- :)))

I don't know how to save you ... Better, I don't know how to prove it ... I'm sorry ...
But, the rest depends on your ability to see the logic- :)))

Greetings from T.n.p.

Are you a gang of fools ? Or, don't you understand the T.d.i.? :

The T.d.i. I can try to explain it to you . in my own way :
All squares depend on m^2, ==> 100i^2--
All volumes depend on m^3, ==> 1000i^3:

0.2 * (30i *100i) ==> 2i * 3000i = 6'000i^2 = 60 (100i^2) = 60m^2.
0.2 * 3 * 10 ===> 2i * 30i * 100i = 6'000i^3 = 6 (1000i^3) = 6m^3.
As you see, the number of dm, does not change but, it changes ; from i^2 to i^3.
So how do you compare 60m^2 to 6m^3 ..... Unfortunately ..... We don't know.
The only truth that turns out is that you are wrong ; to consider 60m^2 > 6m^3- :)

I don't know how to save you ..Better, I don't know how to prove it ..I'm sorry ...
But, the rest depends on your ability to see the logic T.d.i-
Important is. Understand Why, volumes are 10 times < of squares- :))

Greetings from T.n.p.

On 5/24/2021 4:35 AM, Socratis T.n.p. wrote:
> Are you a gang of fools ? Or, don't you understand the T.d.i.? :

You are a cretin.

Il giorno lunedì 24 maggio 2021 alle 15:31:44 UTC+2 Señor Dingus ha scritto:
> On 5/24/2021 4:35 AM, Socratis T.n.p. wrote:
> > Are you a gang of fools ? Or, don't you understand the T.d.i.? :
> You are a cretin.

Why have generations of scientists never understood this arcane?
Luckily Socratis Solved it, at the suggestion of the T.n.p.
She has guessed it since he created the square in 10i *10i =100i^2. And
froma long time explaining how to find small volumes, by dm, even if
You have refused his teaching, which you are now forced to Accept, a
unless, you don't want to, still ignore the glaring demonstrations- :))

Line * 0.1 = n- Squares.
Ex. 1) 10 * 0.1 = 100i * i = 100i^2 = 1m^2
2) 100 * 0.1 == 1000i * i = 1000i^2 = 10m^2
3) 1000 * 0.1 =10'000i * i =10'000i^2 = 100m^2
4) 1000 * 0.2 = 10'000i * 2i = 20'000i^2 = 200m^2

Squares * 0.1 = n-Volumes:
Ex. 1) 5 * 10 * 0.1 = 50i * 100i * i = 5000i^3 = 5m^3
2) 10 * 10 * 0.1 = 100i * 100i * i = 10'000i^3 =10m^3
3) 20 * 20 * 0.1 = 200i * 200i * i = 40'000i^3 = 40m^3
4) 20 * 20 * 0.2 = 200i * 200i *2i = 80'000i^3 = 80m^3

Now .. You shouldn't have any doubts, also because you can and you must
check..especially using the cube roots in: n^3, and in n_i^3.

3√5 == 1.7099 ... 3√5000i^3 == i17.099 ...
3√10 = 2.1544 ... 3√10'000i^3 = i21.544 ...
3√40 = 3.4199 ... 3√40'000i^3 = i34.199 ...
3√80 = 4.3088 ... 3√80'000i^3 = i43.088 ...

If desired, note that the Roots must not be greater than the Radicandi,
if they are, it means that you are rooted in reverse .. Also check ...
3√0.1m^3 = 0.46415 ..= i4.6415. If you are smart, you just need 3√100i = i4.6415- :))
If that's not enough, you need a computer that has units; 1, i. c, •.

Kind regards from Socratis T.n.p. Rome.24.mag.201

> > Greetings from T.n.p.
> This thinking also requires orthogonality.

The computer always works with orthogonal lines.

> Coordinate systems work fine skewed, but areas will diminish at small angle. Haven't really
> done the analysis recently, but maybe there is something there for you.

I don't need anything, anyway thanks for the offer.-:)))

Why have generations of scientists never understood this arcane?
Luckily Socratis Solved it, at the suggestion of the T.n.p.
She has guessed it since he created the square in 10i *10i =100i^2. And
froma long time explaining how to find small volumes, by dm, even if
You have refused his teaching, which you are now forced to Accept, a
unless, you don't want to, still ignore the glaring demonstrations- :))

Line * 0.1 = n- Squares.
Ex. 1) 10 * 0.1 = 100i * i = 100i^2 = 1m^2
2) 100 * 0.1 == 1000i * i = 1000i^2 = 10m^2
3) 1000 * 0.1 =10'000i * i =10'000i^2 = 100m^2
4) 1000 * 0.2 = 10'000i * 2i = 20'000i^2 = 200m^2

Squares * 0.1 = n-Volumes:
Ex. 1) 5 * 10 * 0.1 = 50i * 100i * i = 5000i^3 = 5m^3
2) 10 * 10 * 0.1 = 100i * 100i * i = 10'000i^3 =10m^3
3) 20 * 20 * 0.1 = 200i * 200i * i = 40'000i^3 = 40m^3
4) 20 * 20 * 0.2 = 200i * 200i *2i = 80'000i^3 = 80m^3

Now .. You shouldn't have any doubts, also because you can and you must
check..especially using the cube roots in: n^3, and in n_i^3.

3√5 == 1.7099 ... 3√5000i^3 == i17.099 ...
3√10 = 2.1544 ... 3√10'000i^3 = i21.544 ...
3√40 = 3.4199 ... 3√40'000i^3 = i34.199 ...
3√80 = 4.3088 ... 3√80'000i^3 = i43.088 ...

If desired, note that the Roots must not be greater than the Radicandi,
if they are, it means that you are rooted in reverse .. Also check ...
3√0.1m^3 = 0.46415 ..= i4.6415. If you are smart, you just need 3√100i = i4.6415- :))
If that's not enough, you need a computer that has units; 1, i. c, •.

Kind regards from Socratis T.n.p. Rome.24.mag.201