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tech / sci.math / I prefer: 10i/2i = 5i/i

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* I prefer: 10i/2i = 5i/iSocratis T.n.p.
+* Re: I prefer: 10i/2i = 5i/iHeywood Jablome
|`- Re: I prefer: 10i/2i = 5i/iSocratis T.n.p.
`- Re: I prefer: 10i/2i = 5i/iSocratis T.n.p.

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I prefer: 10i/2i = 5i/i

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Subject: I prefer: 10i/2i = 5i/i
From: andreaso...@gmail.com (Socratis T.n.p.)
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 by: Socratis T.n.p. - Wed, 9 Jun 2021 02:18 UTC

Who knows why..10i/2i =5i/i ... is it preferable to 10i/20i = 0.05 / i ??
Maybe why 5i *20i = 100i^2 = 1m^2 ??
, And to think that ... what they say, the m^2 shouldn't exist?
Actually it is better to say 10i/2i =5i => 5i*2i =10i^2 =1000c^2 =0.1m^2 .??
Since he thinks about making the m^2; i * 100i = 100i^2 = 10'000c^2

These things were not understood, when the m^2 was produced by 100c* 100c.
But probably also that of the square is a hypothesis, which is valid only
for small numbers, Since 1 is also neutral like i, when I say:

i *10i *10i = 100i^3 ... but, I doubt if I must say; i *i = i, or i *i = i^2 =100c^2.
But I believe the scientists solved it by saying i * i = 0.01m^2 ---

So I have the initial doubt ... on whether 1 *1 is 1, or 10'000cm^2 = 100i^2.
It would seem that it is a question of choice. Variable according to the cases ??

Greetings from Socratis T.n.p. Rome 9.Jun.2021-
(n-d)^3 + n^3 + (n+d)^3 = 3n* (n^2 +2 *d^2)
d=2) 4^3 + 6^3 + 8^3 === 18 * (36 + 2 *2^2) = 18 *44m^2 =792m^3

Re: I prefer: 10i/2i = 5i/i

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From: Heyw...@hayward.com (Heywood Jablome)
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Subject: Re: I prefer: 10i/2i = 5i/i
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 by: Heywood Jablome - Wed, 9 Jun 2021 03:48 UTC

On 6/8/2021 7:18 PM, Socratis T.n.p. wrote:
> Who knows why..10i/2i =5i/i ... is it preferable to 10i/20i = 0.05 / i ??

You are a cretin.

Re: I prefer: 10i/2i = 5i/i

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Subject: Re: I prefer: 10i/2i = 5i/i
From: andreaso...@gmail.com (Socratis T.n.p.)
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 by: Socratis T.n.p. - Wed, 9 Jun 2021 05:37 UTC

Il giorno mercoledì 9 giugno 2021 alle 05:48:31 UTC+2 Heywood Jablome ha scritto:
> On 6/8/2021 7:18 PM, Socratis T.n.p. wrote:
> > Who knows why..10i/2i =5i/i ... is it preferable to 10i/20i = 0.05 / i ??
> You are a cretin.

It is clear that you are a genius-:))

Greetings. from, Socratis, T.n.p. Rome 9.Jun.2021-
(n - d)^3 +n^3 +(n +d)^3 = 3n*(n^2 +2*d^2)
d=2) 4^3 + 6^3 + 8^3 === 18 * (36 + 2*2^2) =18*44m^2 =792m^3

Re: I prefer: 10i/2i = 5i/i

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Subject: Re: I prefer: 10i/2i = 5i/i
From: andreaso...@gmail.com (Socratis T.n.p.)
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 by: Socratis T.n.p. - Thu, 10 Jun 2021 08:42 UTC

The Geniuses struggle to grasp the Laws of the system that they use badly.
I hope to help them get rid of the bad interpretations on the three 0.1s.
0.1 linear = 10cm ... 0.1m^2 = 1000c^2 .. 0.1m^3 = 1i * 10i * 10i = 100i^3.
=============> 10c*100c = 1000c^2 .. 10c * 100c * 100c = 100'000c^3.
So it doesn't exist; substantial difference between T.n.p. and, Vera T.d.i.
There is a formal difference that could and should be eliminated.

Line * 0.1 = n - Squares. = Q.
Areas * 0.1=n - Volumes = V.

1.A) 10 ***** 0.1 = 100i ** i = 100i^2 = 1m^2 == Q.
1.V) 10 *0.1 *0.1 = 100i *i *i =100i^3 = 0.1m^3 = V

2.A) 100 ***** 0.1 = 1000i ** i = 1000i^2 = 10m^2 = Q.
2.V) 100 *0.1 *0.1 = 1000i *i *i =1000i^3 = 1m^3 == V.

3.A) 1000 ****** 0.1 = 10'000i ** i = 10'000i^2 = 100m^2 = Q.
3.V) 1000 * 0.1 * 0.1 = 10'000i *i *i= 10'000i^3 = 10m^3 == V.

In the Areas there are 2 factors i, in the Volumes there are 3 f. the.
But actually ; open the brain; we operated on all i.- :))
the. 2i, 3i, 4i, 5i, 6i, 7i, 8i, 9i, 10i. = 1m. 1.1m = 11i. 1.2m = 12i. 2m = 20i.

You would do well to consider; √0.1m^2 = 0.31622 ... 3√0.1m^3 = 0.46415 ...
Which means 0.1m^2 = 10i^2 ..... 0.1m^3 = 100i^3.
Maybe you will be able to See beyond your current awareness-;))
And maybe you could understand: i^3 = 1000c^3 .. indicated: 0.001m^3 from the T.d.i.

Greetings from Socratis T.n.p. (a + b)^2 = 4ab + d^2.

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