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tech / sci.physics.relativity / E=mc^2 approximation and electron’s electric field energy.

SubjectAuthor
* E=mc^2 approximation and electron’s electric fieldRichard Hertz
`- Re: E=mc^2 approximation and electron’sOdd Bodkin

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E=mc^2 approximation and electron’s electric field energy.

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Subject: E=mc^2_approximation_and_electron’s_electric_field
_energy.
From: hertz...@gmail.com (Richard Hertz)
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 by: Richard Hertz - Thu, 5 Aug 2021 05:33 UTC

Using E=mc^2 approximation to calculate energy at rest for an electron,
it gives 0.511 MeV or 8.10^-14 Joules.

But, with the formula E=e^2/(8.PI.Epsilon0.R), a radius of 10^-18 mt,
Epsilon0 valued in 8.854.10^-12 Farads/mt and a charge of 1.6.10^-19 Coul,
the electron would have an energy of 1.2.10^-10 Joules stored in its
electric field.

This energy is about 1400 times larger than the energy of its rest mass, that is proved in electron annihilation.

The question is: Why this is not considered in Einstein's SR? The same
question is valid for any other charged particle, like protons and muons.

In the case of the proton, the energy of it’s external electric field is about 10^13 Joules, being only about 0.1% of the proton’s energy of its rest mass
(938 MeV).

Any ideas about this topic?

Consider that the electric field of charged particles is essential in the study of accelerated charges and that their stored electric energy may have a role in the limitations to increment their speeds when are close to that of the light.

Can be possible that such particles store the energy given to accelerate in their electric field and that is what rises toward infinity, instead of its moment? Or that the electric energy used to accelerate them fail to catch the "reservoir of energy" within the particles?

I'm curious about this topic.

Re: E=mc^2 approximation and electron’s electric field energy.

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From: bodkin...@gmail.com (Odd Bodkin)
Newsgroups: sci.physics.relativity
Subject: Re: E=mc^2 approximation and electron’s
electric field energy.
Date: Thu, 5 Aug 2021 14:16:55 -0000 (UTC)
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 by: Odd Bodkin - Thu, 5 Aug 2021 14:16 UTC

Richard Hertz <hertz778@gmail.com> wrote:
> Using E=mc^2 approximation to calculate energy at rest for an electron,
> it gives 0.511 MeV or 8.10^-14 Joules.
>
> But, with the formula E=e^2/(8.PI.Epsilon0.R), a radius of 10^-18 mt,
> Epsilon0 valued in 8.854.10^-12 Farads/mt and a charge of 1.6.10^-19 Coul,
> the electron would have an energy of 1.2.10^-10 Joules stored in its
> electric field.
>
> This energy is about 1400 times larger than the energy of its rest mass,
> that is proved in electron annihilation.
>
> The question is: Why this is not considered in Einstein's SR? The same
> question is valid for any other charged particle, like protons and muons.
>
> In the case of the proton, the energy of it’s external electric field is
> about 10^13 Joules, being only about 0.1% of the proton’s energy of its rest mass
> (938 MeV).
>
> Any ideas about this topic?

What drove the choice of the value of R?

>
> Consider that the electric field of charged particles is essential in the
> study of accelerated charges and that their stored electric energy may
> have a role in the limitations to increment their speeds when are close
> to that of the light.
>
> Can be possible that such particles store the energy given to accelerate
> in their electric field and that is what rises toward infinity, instead
> of its moment? Or that the electric energy used to accelerate them fail
> to catch the "reservoir of energy" within the particles?
>
> I'm curious about this topic.
>

--
Odd Bodkin -- maker of fine toys, tools, tables


tech / sci.physics.relativity / E=mc^2 approximation and electron’s electric field energy.

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