novaBBS - sci.math - .999 repeating add zero

.999 repeating add zero

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Subject: .999 repeating add zero
From: mitchrae...@gmail.com (mitchr...@gmail.com)
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by: mitchr...@gmail.com - Wed, 1 Dec 2021 20:46 UTC

you get .999 repeating again not 1 instead...

Re: .999 repeating add zero

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From: moro...@world.std.spaamtrap.com (Michael Moroney)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Wed, 1 Dec 2021 18:07:39 -0500
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by: Michael Moroney - Wed, 1 Dec 2021 23:07 UTC

On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
> you get .999 repeating again not 1 instead...
>
I get 1.

Re: .999 repeating add zero

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Subject: Re: .999 repeating add zero
From: mitchrae...@gmail.com (mitchr...@gmail.com)
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by: mitchr...@gmail.com - Wed, 1 Dec 2021 23:57 UTC

On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney wrote:
> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
> > you get .999 repeating again not 1 instead...
> >
> I get 1.

You don't get it...

Re: .999 repeating add zero

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From: inva...@invalid.com (Serg io)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Wed, 1 Dec 2021 22:06:02 -0600
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by: Serg io - Thu, 2 Dec 2021 04:06 UTC

On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney wrote:
>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>> you get .999 repeating again not 1 instead...
>>>
>> I get 1.
>
> You don't get it...
>

just use 1 base(.999 repeating) = 1

Re: .999 repeating add zero

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From: chris.m....@gmail.com (Chris M. Thomasson)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Wed, 1 Dec 2021 20:34:52 -0800
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by: Chris M. Thomasson - Thu, 2 Dec 2021 04:34 UTC

On 12/1/2021 8:06 PM, Serg io wrote:
> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney
>> wrote:
>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>> you get .999 repeating again not 1 instead...
>>>>
>>> I get 1.
>>
>> You don't get it...
>>
>
> just use 1 base(.999 repeating) = 1

..999 repeating is the representation of 1 in base 10.

Re: .999 repeating add zero

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Subject: Re: .999 repeating add zero
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by: zelos...@gmail.com - Thu, 2 Dec 2021 05:18 UTC

onsdag 1 december 2021 kl. 21:46:09 UTC+1 skrev mitchr...@gmail.com:
> you get .999 repeating again not 1 instead...

0.999...+0=1+0=1

Wrong as always :)

Re: .999 repeating add zero

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From: erra...@nomail.afraid.org (FromTheRafters)
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Subject: Re: .999 repeating add zero
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by: FromTheRafters - Thu, 2 Dec 2021 09:49 UTC

Chris M. Thomasson formulated on Wednesday :
> On 12/1/2021 8:06 PM, Serg io wrote:
>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney wrote:
>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>> you get .999 repeating again not 1 instead...
>>>>>
>>>> I get 1.
>>>
>>> You don't get it...
>>>
>>
>> just use 1 base(.999 repeating) = 1
>
> .999 repeating is the representation of 1 in base 10.

One of the representations.

Re: .999 repeating add zero

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From: inva...@invalid.com (Serg io)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Thu, 2 Dec 2021 07:19:59 -0600
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by: Serg io - Thu, 2 Dec 2021 13:19 UTC

On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
> On 12/1/2021 8:06 PM, Serg io wrote:
>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney wrote:
>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>> you get .999 repeating again not 1 instead...
>>>>>
>>>> I get 1.
>>>
>>> You don't get it...
>>>
>>
>> just use 1 base(.999 repeating) = 1
>
> .999 repeating is the representation of 1 in base 10.

I see the mistake;

..999repeating in base(.999 repeating) = 1

Re: .999 repeating add zero

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Subject: Re: .999 repeating add zero
From: mitchrae...@gmail.com (mitchr...@gmail.com)
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by: mitchr...@gmail.com - Thu, 2 Dec 2021 18:38 UTC

On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
> > On 12/1/2021 8:06 PM, Serg io wrote:
> >> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
> >>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney wrote:
> >>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
> >>>>> you get .999 repeating again not 1 instead...
> >>>>>
> >>>> I get 1.
> >>>
> >>> You don't get it...
> >>>
> >>
> >> just use 1 base(.999 repeating) = 1
> >
> > .999 repeating is the representation of 1 in base 10.
> I see the mistake;
>
> .999repeating in base(.999 repeating) = 1

...999 repeating does not reach1.

Mitchell Raemsch

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From: chris.m....@gmail.com (Chris M. Thomasson)
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Subject: Re: .999 repeating add zero
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by: Chris M. Thomasson - Thu, 2 Dec 2021 21:54 UTC

On 12/2/2021 1:49 AM, FromTheRafters wrote:
> Chris M. Thomasson formulated on Wednesday :
>> On 12/1/2021 8:06 PM, Serg io wrote:
>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney
>>>> wrote:
>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>>> you get .999 repeating again not 1 instead...
>>>>>>
>>>>> I get 1.
>>>>
>>>> You don't get it...
>>>>
>>>
>>> just use 1 base(.999 repeating) = 1
>>
>> .999 repeating is the representation of 1 in base 10.
>
> One of the representations.

Yup. I should have not have wrote the word "the"... ;^)

Touche. :^)

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From: chris.m....@gmail.com (Chris M. Thomasson)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Thu, 2 Dec 2021 13:55:15 -0800
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by: Chris M. Thomasson - Thu, 2 Dec 2021 21:55 UTC

On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
>>> On 12/1/2021 8:06 PM, Serg io wrote:
>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney wrote:
>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>>>> you get .999 repeating again not 1 instead...
>>>>>>>
>>>>>> I get 1.
>>>>>
>>>>> You don't get it...
>>>>>
>>>>
>>>> just use 1 base(.999 repeating) = 1
>>>
>>> .999 repeating is the representation of 1 in base 10.
>> I see the mistake;
>>
>> .999repeating in base(.999 repeating) = 1
>
> ..999 repeating does not reach1.

If you take it on a step-by-step basis, yeah, you are correct.

Re: .999 repeating add zero

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From: erra...@nomail.afraid.org (FromTheRafters)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Thu, 02 Dec 2021 17:15:19 -0500
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by: FromTheRafters - Thu, 2 Dec 2021 22:15 UTC

Chris M. Thomasson submitted this idea :
> On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
>> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
>>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
>>>> On 12/1/2021 8:06 PM, Serg io wrote:
>>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney
>>>>>> wrote:
>>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>>>>> you get .999 repeating again not 1 instead...
>>>>>>>>
>>>>>>> I get 1.
>>>>>>
>>>>>> You don't get it...
>>>>>>
>>>>>
>>>>> just use 1 base(.999 repeating) = 1
>>>>
>>>> .999 repeating is the representation of 1 in base 10.
>>> I see the mistake;
>>>
>>> .999repeating in base(.999 repeating) = 1
>>
>> ..999 repeating does not reach1.
>
> If you take it on a step-by-step basis, yeah, you are correct.

How does a number reach?

Re: .999 repeating add zero

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From: chris.m....@gmail.com (Chris M. Thomasson)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Thu, 2 Dec 2021 14:38:58 -0800
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by: Chris M. Thomasson - Thu, 2 Dec 2021 22:38 UTC

On 12/2/2021 2:15 PM, FromTheRafters wrote:
> Chris M. Thomasson submitted this idea :
>> On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
>>> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
>>>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
>>>>> On 12/1/2021 8:06 PM, Serg io wrote:
>>>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael
>>>>>>> Moroney wrote:
>>>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>>>>>> you get .999 repeating again not 1 instead...
>>>>>>>>>
>>>>>>>> I get 1.
>>>>>>>
>>>>>>> You don't get it...
>>>>>>>
>>>>>>
>>>>>> just use 1 base(.999 repeating) = 1
>>>>>
>>>>> .999 repeating is the representation of 1 in base 10.
>>>> I see the mistake;
>>>>
>>>> .999repeating in base(.999 repeating) = 1
>>>
>>> ..999 repeating does not reach1.
>>
>> If you take it on a step-by-step basis, yeah, you are correct.
>
> How does a number reach?

On a step-by-step basis, say:

1 = .9 = false
1 = .99 = false
1 = .999 = false
1 = .9999 = false

We will never get there. However, it does get infinitely close to 1...

Re: .999 repeating add zero

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From: chris.m....@gmail.com (Chris M. Thomasson)
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by: Chris M. Thomasson - Thu, 2 Dec 2021 22:42 UTC

On 12/2/2021 2:38 PM, Chris M. Thomasson wrote:
> On 12/2/2021 2:15 PM, FromTheRafters wrote:
>> Chris M. Thomasson submitted this idea :
>>> On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
>>>> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
>>>>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
>>>>>> On 12/1/2021 8:06 PM, Serg io wrote:
>>>>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>>>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael
>>>>>>>> Moroney wrote:
>>>>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>>>>>>> you get .999 repeating again not 1 instead...
>>>>>>>>>>
>>>>>>>>> I get 1.
>>>>>>>>
>>>>>>>> You don't get it...
>>>>>>>>
>>>>>>>
>>>>>>> just use 1 base(.999 repeating) = 1
>>>>>>
>>>>>> .999 repeating is the representation of 1 in base 10.
>>>>> I see the mistake;
>>>>>
>>>>> .999repeating in base(.999 repeating) = 1
>>>>
>>>> ..999 repeating does not reach1.
>>>
>>> If you take it on a step-by-step basis, yeah, you are correct.
>>
>> How does a number reach?
>
> On a step-by-step basis, say:
>
> 1 = .9 = false
> 1 = .99 = false
> 1 = .999 = false
> 1 = .9999 = false
>
> We will never get there. However, it does get infinitely close to 1...

On a step-by-step basis:

1 = .9 + .1 = true
1 = .99 + .01 = true
1 = .999 + .001 = true
1 = .9999 + .0001 = true

lol. ;^)

Re: .999 repeating add zero

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From: james.g....@att.net (Jim Burns)
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Subject: Re: .999 repeating add zero
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by: Jim Burns - Thu, 2 Dec 2021 23:24 UTC

On 12/2/2021 5:38 PM, Chris M. Thomasson wrote:
> On 12/2/2021 2:15 PM, FromTheRafters wrote:

>> How does a number reach?
>
> On a step-by-step basis, say:
>
> 1 = .9 = false
> 1 = .99 = false
> 1 = .999 = false
> 1 = .9999 = false
>
> We will never get there.

Why isn't that the opposite of reaching?

> However, it does get infinitely close to 1...

For an Archimedean line, for any two positive
distances x and y, there is some (finite) positive
number k of replications of x such that k*x > y

( This describes the line not having
( infinite points or infinitesimal point,
( like our usual geometric line.

Let the distance from 0 to 1 by y,
and the distance from 0.999... to 1 be x
Then 1 = 0.999...

| Therefore,
(1 - 0.999...) is not a positive distance
| 1 = 0.999...

Re: .999 repeating add zero

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Newsgroups: sci.math
Subject: Re: .999 repeating add zero
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by: Serg io - Fri, 3 Dec 2021 03:29 UTC

On 12/2/2021 4:42 PM, Chris M. Thomasson wrote:
> On 12/2/2021 2:38 PM, Chris M. Thomasson wrote:
>> On 12/2/2021 2:15 PM, FromTheRafters wrote:
>>> Chris M. Thomasson submitted this idea :
>>>> On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
>>>>> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
>>>>>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
>>>>>>> On 12/1/2021 8:06 PM, Serg io wrote:
>>>>>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>>>>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney wrote:
>>>>>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>>>>>>>> you get .999 repeating again not 1 instead...
>>>>>>>>>>>
>>>>>>>>>> I get 1.
>>>>>>>>>
>>>>>>>>> You don't get it...
>>>>>>>>>
>>>>>>>>
>>>>>>>> just use 1 base(.999 repeating) = 1
>>>>>>>
>>>>>>> .999 repeating is the representation of 1 in base 10.
>>>>>> I see the mistake;
>>>>>>
>>>>>> .999repeating in base(.999 repeating) = 1
>>>>>
>>>>> ..999 repeating does not reach1.
>>>>
>>>> If you take it on a step-by-step basis, yeah, you are correct.
>>>
>>> How does a number reach?
>>
>> On a step-by-step basis, say:
>>
>> 1 = .9    = false
>> 1 = .99   = false
>> 1 = .999 = false
>> 1 = .9999 = false
>>
>> We will never get there. However, it does get infinitely close to 1...
>
> On a step-by-step basis:
>
> 1 = .9 + .1       = true
> 1 = .99 + .01     = true
> 1 = .999 + .001   = true
> 1 = .9999 + .0001 = true
>
> lol. ;^)

by golly! that IS the solution!

so 1 = .999 repeating + 0 = true

Re: .999 repeating add zero

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From: inva...@invalid.com (Serg io)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Thu, 2 Dec 2021 21:34:37 -0600
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by: Serg io - Fri, 3 Dec 2021 03:34 UTC

On 12/2/2021 5:24 PM, Jim Burns wrote:
> On 12/2/2021 5:38 PM, Chris M. Thomasson wrote:
>> On 12/2/2021 2:15 PM, FromTheRafters wrote:
>
>>> How does a number reach?
>>
>> On a step-by-step basis, say:
>>
>> 1 = .9 = false
>> 1 = .99 = false
>> 1 = .999 = false
>> 1 = .9999 = false
>>
>> We will never get there.
>
> Why isn't that the opposite of reaching?

As verbs the difference between reach and reaching is that reach is to extend; to stretch; to thrust out; to put forth, as a limb, a member, something
held, or the like while reaching is .

As nouns the difference between reach and reaching is that reach is the act of stretching or extending; extension; power of reaching or touching with
the person, or a limb, or something held.

reaching is that reach is (nautical) any point of sail in which the wind comes from the side of a vessel, excluding close-hauled while reaching is
(nautical) sailing on a reach, ie having the wind on either side and coming from an angle that is larger with respect to the bow than when sailing
close-hauled.

what about Reached ? reacheded ?

>
>> However, it does get infinitely close to 1...
>
> For an Archimedean line, for any two positive
> distances x and y, there is some (finite) positive
> number k of replications of x such that k*x > y
>
> ( This describes the line not having
> ( infinite points or infinitesimal point,
> ( like our usual geometric line.
>
> Let the distance from 0 to 1 by y,
> and the distance from 0.999... to 1 be x
> Then 1 = 0.999...
>
> | Assume that x is a positive distance.
> | Then (finite) k ∈ ℕ exists such that k*x > 1
> |
> | k is finite.
> | There is a last power of 10, 10^j < k
> | And 10*10^j * k > 1
> |
> | However,
> | 10*(1 - 0.999...) < 1, so k > 10
> | 100*(1 - 0.999...) < 1, so k > 100
> | 1000*(1 - 0.999...) < 1, so k > 1000
> | 10000*(1 - 0.999...) < 1, so k > 10000
> | ...
> |
> | So, there is no power of 10, 10*10^j*x > 1
> | |Contradiction.
>
> | Therefore,
> (1 - 0.999...) is not a positive distance
> | 1 = 0.999...
>

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Subject: Re: .999 repeating add zero
From: zelos.ma...@gmail.com (zelos...@gmail.com)
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by: zelos...@gmail.com - Fri, 3 Dec 2021 05:21 UTC

torsdag 2 december 2021 kl. 19:39:01 UTC+1 skrev mitchr...@gmail.com:
> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
> > On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
> > > On 12/1/2021 8:06 PM, Serg io wrote:
> > >> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
> > >>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney wrote:
> > >>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
> > >>>>> you get .999 repeating again not 1 instead...
> > >>>>>
> > >>>> I get 1.
> > >>>
> > >>> You don't get it...
> > >>>
> > >>
> > >> just use 1 base(.999 repeating) = 1
> > >
> > > .999 repeating is the representation of 1 in base 10.
> > I see the mistake;
> >
> > .999repeating in base(.999 repeating) = 1
> ..999 repeating does not reach1.
>
> Mitchell Raemsch

it reaches nothing, it IS 1

Re: .999 repeating add zero

<soeaap$187$1@dont-email.me>

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From: chris.m....@gmail.com (Chris M. Thomasson)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Fri, 3 Dec 2021 15:47:37 -0800
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by: Chris M. Thomasson - Fri, 3 Dec 2021 23:47 UTC

On 12/2/2021 7:29 PM, Serg io wrote:
> On 12/2/2021 4:42 PM, Chris M. Thomasson wrote:
>> On 12/2/2021 2:38 PM, Chris M. Thomasson wrote:
>>> On 12/2/2021 2:15 PM, FromTheRafters wrote:
>>>> Chris M. Thomasson submitted this idea :
>>>>> On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
>>>>>> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
>>>>>>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
>>>>>>>> On 12/1/2021 8:06 PM, Serg io wrote:
>>>>>>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>>>>>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael
>>>>>>>>>> Moroney wrote:
>>>>>>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>>>>>>>>> you get .999 repeating again not 1 instead...
>>>>>>>>>>>>
>>>>>>>>>>> I get 1.
>>>>>>>>>>
>>>>>>>>>> You don't get it...
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> just use 1 base(.999 repeating) = 1
>>>>>>>>
>>>>>>>> .999 repeating is the representation of 1 in base 10.
>>>>>>> I see the mistake;
>>>>>>>
>>>>>>> .999repeating in base(.999 repeating) = 1
>>>>>>
>>>>>> ..999 repeating does not reach1.
>>>>>
>>>>> If you take it on a step-by-step basis, yeah, you are correct.
>>>>
>>>> How does a number reach?
>>>
>>> On a step-by-step basis, say:
>>>
>>> 1 = .9    = false
>>> 1 = .99   = false
>>> 1 = .999 = false
>>> 1 = .9999 = false
>>>
>>> We will never get there. However, it does get infinitely close to 1...
>>
>> On a step-by-step basis:
>>
>> 1 = .9 + .1       = true
>> 1 = .99 + .01     = true
>> 1 = .999 + .001   = true
>> 1 = .9999 + .0001 = true
>>
>> lol. ;^)
>
>
>
> by golly!   that IS the solution!
>
>
> so 1 = .999 repeating + 0 = true

Indeed it does! :^D

Re: .999 repeating add zero

<soedvl$l1k$1@dont-email.me>

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From: chris.m....@gmail.com (Chris M. Thomasson)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Fri, 3 Dec 2021 16:49:55 -0800
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by: Chris M. Thomasson - Sat, 4 Dec 2021 00:49 UTC

..999... is one of the ways for base 10 to represent 1. just writing 1 is
another, one. ;^)

Its limit is 1, it is one. Okay. Then for fun, sometimes I imagine a
fantasy scenario that involves two beings that live forever... lol... ;^)

Being_0 tells Being_1 to report when the following recursion equals one:

r[0] = .9 / 10^0 = .9
r[1] = r[0] + .9 / 10^1 = 0.99
r[2] = r[1] + .9 / 10^2 = 0.999
r[3] = r[2] + .9 / 10^3 = 0.9999
r[4] = r[3] + .9 / 10^4 = 0.99999
....

Basically:

r[0] = .9 / 10^0 = .9
r[n] = r[n - 1] + .9 / 10^[n]

At what iteration n will Being_1 report to Being_0 that r[n] is equal to
zero?

;^)

Re: .999 repeating add zero

<soeea9$ml6$1@dont-email.me>

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From: chris.m....@gmail.com (Chris M. Thomasson)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Fri, 3 Dec 2021 16:55:36 -0800
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by: Chris M. Thomasson - Sat, 4 Dec 2021 00:55 UTC

On 12/3/2021 4:49 PM, Chris M. Thomasson wrote:
> On 12/2/2021 7:29 PM, Serg io wrote:
>> On 12/2/2021 4:42 PM, Chris M. Thomasson wrote:
>>> On 12/2/2021 2:38 PM, Chris M. Thomasson wrote:
>>>> On 12/2/2021 2:15 PM, FromTheRafters wrote:
>>>>> Chris M. Thomasson submitted this idea :
>>>>>> On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
>>>>>>> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
>>>>>>>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
>>>>>>>>> On 12/1/2021 8:06 PM, Serg io wrote:
>>>>>>>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>>>>>>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael
>>>>>>>>>>> Moroney wrote:
>>>>>>>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>>>>>>>>>> you get .999 repeating again not 1 instead...
>>>>>>>>>>>>>
>>>>>>>>>>>> I get 1.
>>>>>>>>>>>
>>>>>>>>>>> You don't get it...
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> just use 1 base(.999 repeating) = 1
>>>>>>>>>
>>>>>>>>> .999 repeating is the representation of 1 in base 10.
>>>>>>>> I see the mistake;
>>>>>>>>
>>>>>>>> .999repeating in base(.999 repeating) = 1
>>>>>>>
>>>>>>> ..999 repeating does not reach1.
>>>>>>
>>>>>> If you take it on a step-by-step basis, yeah, you are correct.
>>>>>
>>>>> How does a number reach?
>>>>
>>>> On a step-by-step basis, say:
>>>>
>>>> 1 = .9    = false
>>>> 1 = .99   = false
>>>> 1 = .999 = false
>>>> 1 = .9999 = false
>>>>
>>>> We will never get there. However, it does get infinitely close to 1...
>>>
>>> On a step-by-step basis:
>>>
>>> 1 = .9 + .1       = true
>>> 1 = .99 + .01     = true
>>> 1 = .999 + .001   = true
>>> 1 = .9999 + .0001 = true
>>>
>>> lol. ;^)
>>
>>
>>
>>    by golly!   that IS the solution!
>>
>>
>> so 1 = .999 repeating + 0 = true
>
> .999... is one of the ways for base 10 to represent 1. just writing 1 is
> another, one. ;^)
>
> Its limit is 1, it is one. Okay. Then for fun, sometimes I imagine a
> fantasy scenario that involves two beings that live forever... lol... ;^)
>
> Being_0 tells Being_1 to report when the following recursion equals one:
>
> r[0] = .9 / 10^0 = .9
> r[1] = r[0] + .9 / 10^1 = 0.99
> r[2] = r[1] + .9 / 10^2 = 0.999
> r[3] = r[2] + .9 / 10^3 = 0.9999
> r[4] = r[3] + .9 / 10^4 = 0.99999
> ...
>
> Basically:
>
> r[0] = .9 / 10^0 = .9
> r[n] = r[n - 1] + .9 / 10^[n]
>
> At what iteration n will Being_1 report to Being_0 that r[n] is equal to
> zero?

YIKES!!!! I meant:

At what iteration n will Being_1 report to Being_0 that r[n] is equal to
one?

God damn typos!!! Sorry. ;^o

Damn it!

Re: .999 repeating add zero

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From: inva...@invalid.com (Serg io)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Fri, 3 Dec 2021 22:24:11 -0600
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by: Serg io - Sat, 4 Dec 2021 04:24 UTC

On 12/3/2021 6:49 PM, Chris M. Thomasson wrote:
> On 12/2/2021 7:29 PM, Serg io wrote:
>> On 12/2/2021 4:42 PM, Chris M. Thomasson wrote:
>>> On 12/2/2021 2:38 PM, Chris M. Thomasson wrote:
>>>> On 12/2/2021 2:15 PM, FromTheRafters wrote:
>>>>> Chris M. Thomasson submitted this idea :
>>>>>> On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
>>>>>>> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
>>>>>>>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
>>>>>>>>> On 12/1/2021 8:06 PM, Serg io wrote:
>>>>>>>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>>>>>>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael Moroney wrote:
>>>>>>>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>>>>>>>>>> you get .999 repeating again not 1 instead...
>>>>>>>>>>>>>
>>>>>>>>>>>> I get 1.
>>>>>>>>>>>
>>>>>>>>>>> You don't get it...
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> just use 1 base(.999 repeating) = 1
>>>>>>>>>
>>>>>>>>> .999 repeating is the representation of 1 in base 10.
>>>>>>>> I see the mistake;
>>>>>>>>
>>>>>>>> .999repeating in base(.999 repeating) = 1
>>>>>>>
>>>>>>> ..999 repeating does not reach1.
>>>>>>
>>>>>> If you take it on a step-by-step basis, yeah, you are correct.
>>>>>
>>>>> How does a number reach?
>>>>
>>>> On a step-by-step basis, say:
>>>>
>>>> 1 = .9    = false
>>>> 1 = .99   = false
>>>> 1 = .999 = false
>>>> 1 = .9999 = false
>>>>
>>>> We will never get there. However, it does get infinitely close to 1...
>>>
>>> On a step-by-step basis:
>>>
>>> 1 = .9 + .1       = true
>>> 1 = .99 + .01     = true
>>> 1 = .999 + .001   = true
>>> 1 = .9999 + .0001 = true
>>>
>>> lol. ;^)
>>
>>
>>
>>    by golly!   that IS the solution!
>>
>>
>> so 1 = .999 repeating + 0 = true
>
> .999... is one of the ways for base 10 to represent 1. just writing 1 is another, one. ;^)
>
> Its limit is 1, it is one. Okay. Then for fun, sometimes I imagine a fantasy scenario that involves two beings that live forever... lol... ;^)
>
> Being_0 tells Being_1 to report when the following recursion equals one:
>
> r[0] = .9 / 10^0 = .9
> r[1] = r[0] + .9 / 10^1 = 0.99
> r[2] = r[1] + .9 / 10^2 = 0.999
> r[3] = r[2] + .9 / 10^3 = 0.9999
> r[4] = r[3] + .9 / 10^4 = 0.99999
> ...
>
> Basically:
>
> r[0] = .9 / 10^0 = .9
> r[n] = r[n - 1] + .9 / 10^[n]
>
> At what iteration n will Being_1 report to Being_0 that r[n] is equal to zero?
>
> ;^)

do these Beings have 10^20 computers with 1024 bit CPU, 10^100 T memory, clock speed of 20 GHz ?
(assume 10^10 TByte RAM)

actually, assume you are already counting, and adding over 100 billion 9's per second but you are totally board, and drinking tea, watching the
computer count zing by in a blur... for years and years... a Gov job. All that has occurred is you have arrived at a steady state of generating 9's
as time passes passes by without end.

So what do you do with the output ? is it ever read or examined for errors? QA? is it recorded ? Why or why not? IF no output, you cant show
anybody... So you have to have an output... or just have them look at the high speed stream of 9's going by on the monitor.

They will be impressed, especially with the electric bill,

but you could fool them by recurlating 9's have about 20 9's in a tight loop, speeding by...

Re: .999 repeating add zero

<sof7hg$b7j$1@dont-email.me>

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From: erra...@nomail.afraid.org (FromTheRafters)
Newsgroups: sci.math
Subject: Re: .999 repeating add zero
Date: Sat, 04 Dec 2021 03:05:48 -0500
Organization: Peripheral Visions
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by: FromTheRafters - Sat, 4 Dec 2021 08:05 UTC

Chris M. Thomasson wrote :
> On 12/2/2021 7:29 PM, Serg io wrote:
>> On 12/2/2021 4:42 PM, Chris M. Thomasson wrote:
>>> On 12/2/2021 2:38 PM, Chris M. Thomasson wrote:
>>>> On 12/2/2021 2:15 PM, FromTheRafters wrote:
>>>>> Chris M. Thomasson submitted this idea :
>>>>>> On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
>>>>>>> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
>>>>>>>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
>>>>>>>>> On 12/1/2021 8:06 PM, Serg io wrote:
>>>>>>>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
>>>>>>>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael
>>>>>>>>>>> Moroney wrote:
>>>>>>>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
>>>>>>>>>>>>> you get .999 repeating again not 1 instead...
>>>>>>>>>>>>>
>>>>>>>>>>>> I get 1.
>>>>>>>>>>>
>>>>>>>>>>> You don't get it...
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> just use 1 base(.999 repeating) = 1
>>>>>>>>>
>>>>>>>>> .999 repeating is the representation of 1 in base 10.
>>>>>>>> I see the mistake;
>>>>>>>>
>>>>>>>> .999repeating in base(.999 repeating) = 1
>>>>>>>
>>>>>>> ..999 repeating does not reach1.
>>>>>>
>>>>>> If you take it on a step-by-step basis, yeah, you are correct.
>>>>>
>>>>> How does a number reach?
>>>>
>>>> On a step-by-step basis, say:
>>>>
>>>> 1 = .9    = false
>>>> 1 = .99   = false
>>>> 1 = .999 = false
>>>> 1 = .9999 = false
>>>>
>>>> We will never get there. However, it does get infinitely close to 1...
>>>
>>> On a step-by-step basis:
>>>
>>> 1 = .9 + .1       = true
>>> 1 = .99 + .01     = true
>>> 1 = .999 + .001   = true
>>> 1 = .9999 + .0001 = true
>>>
>>> lol. ;^)
>>
>>
>>
>> by golly!   that IS the solution!
>>
>>
>> so 1 = .999 repeating + 0 = true
>
> .999... is one of the ways for base 10 to represent 1. just writing 1 is
> another, one. ;^)
>
> Its limit is 1, it is one. Okay. Then for fun, sometimes I imagine a fantasy
> scenario that involves two beings that live forever... lol... ;^)
>
> Being_0 tells Being_1 to report when the following recursion equals one:
>
> r[0] = .9 / 10^0 = .9
> r[1] = r[0] + .9 / 10^1 = 0.99
> r[2] = r[1] + .9 / 10^2 = 0.999
> r[3] = r[2] + .9 / 10^3 = 0.9999
> r[4] = r[3] + .9 / 10^4 = 0.99999
> ...
>
> Basically:
>
> r[0] = .9 / 10^0 = .9
> r[n] = r[n - 1] + .9 / 10^[n]
>
> At what iteration n will Being_1 report to Being_0 that r[n] is equal to
> zero?
>
> ;^)

It won't. It only gives a successively better rational approximation
with each iteration.

Re: .999 repeating add zero

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Subject: Re: .999 repeating add zero
From: mitchrae...@gmail.com (mitchr...@gmail.com)
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by: mitchr...@gmail.com - Sat, 4 Dec 2021 21:00 UTC

On Saturday, December 4, 2021 at 12:06:18 AM UTC-8, FromTheRafters wrote:
> Chris M. Thomasson wrote :
> > On 12/2/2021 7:29 PM, Serg io wrote:
> >> On 12/2/2021 4:42 PM, Chris M. Thomasson wrote:
> >>> On 12/2/2021 2:38 PM, Chris M. Thomasson wrote:
> >>>> On 12/2/2021 2:15 PM, FromTheRafters wrote:
> >>>>> Chris M. Thomasson submitted this idea :
> >>>>>> On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
> >>>>>>> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
> >>>>>>>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
> >>>>>>>>> On 12/1/2021 8:06 PM, Serg io wrote:
> >>>>>>>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
> >>>>>>>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael
> >>>>>>>>>>> Moroney wrote:
> >>>>>>>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
> >>>>>>>>>>>>> you get .999 repeating again not 1 instead...
> >>>>>>>>>>>>>
> >>>>>>>>>>>> I get 1.
> >>>>>>>>>>>
> >>>>>>>>>>> You don't get it...
> >>>>>>>>>>>
> >>>>>>>>>>
> >>>>>>>>>> just use 1 base(.999 repeating) = 1
> >>>>>>>>>
> >>>>>>>>> .999 repeating is the representation of 1 in base 10.
> >>>>>>>> I see the mistake;
> >>>>>>>>
> >>>>>>>> .999repeating in base(.999 repeating) = 1
> >>>>>>>
> >>>>>>> ..999 repeating does not reach1.
> >>>>>>
> >>>>>> If you take it on a step-by-step basis, yeah, you are correct.
> >>>>>
> >>>>> How does a number reach?
> >>>>
> >>>> On a step-by-step basis, say:
> >>>>
> >>>> 1 = .9 = false
> >>>> 1 = .99 = false
> >>>> 1 = .999 = false
> >>>> 1 = .9999 = false
> >>>>
> >>>> We will never get there. However, it does get infinitely close to 1...
> >>>
> >>> On a step-by-step basis:
> >>>
> >>> 1 = .9 + .1 = true
> >>> 1 = .99 + .01 = true
> >>> 1 = .999 + .001 = true
> >>> 1 = .9999 + .0001 = true
> >>>
> >>> lol. ;^)
> >>
> >>
> >>
> >> by golly! that IS the solution!
> >>
> >>
> >> so 1 = .999 repeating + 0 = true
> >
> > .999... is one of the ways for base 10 to represent 1. just writing 1 is
> > another, one. ;^)
> >
> > Its limit is 1, it is one. Okay. Then for fun, sometimes I imagine a fantasy
> > scenario that involves two beings that live forever... lol... ;^)
> >
> > Being_0 tells Being_1 to report when the following recursion equals one:
> >
> > r[0] = .9 / 10^0 = .9
> > r[1] = r[0] + .9 / 10^1 = 0.99
> > r[2] = r[1] + .9 / 10^2 = 0.999
> > r[3] = r[2] + .9 / 10^3 = 0.9999
> > r[4] = r[3] + .9 / 10^4 = 0.99999
> > ...
> >
> > Basically:
> >
> > r[0] = .9 / 10^0 = .9
> > r[n] = r[n - 1] + .9 / 10^[n]
> >
> > At what iteration n will Being_1 report to Being_0 that r[n] is equal to
> > zero?
> >
> > ;^)
> It won't. It only gives a successively better rational approximation
> with each iteration.

..999 repeating and the first integer are not the same quantity.
They share a different kind of equality. One that is by the
beginning quantity of Calculus...

Mitchell Raemsch

Re: .999 repeating add zero

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by: zelos...@gmail.com - Mon, 6 Dec 2021 05:28 UTC

lördag 4 december 2021 kl. 22:00:44 UTC+1 skrev mitchr...@gmail.com:
> On Saturday, December 4, 2021 at 12:06:18 AM UTC-8, FromTheRafters wrote:
> > Chris M. Thomasson wrote :
> > > On 12/2/2021 7:29 PM, Serg io wrote:
> > >> On 12/2/2021 4:42 PM, Chris M. Thomasson wrote:
> > >>> On 12/2/2021 2:38 PM, Chris M. Thomasson wrote:
> > >>>> On 12/2/2021 2:15 PM, FromTheRafters wrote:
> > >>>>> Chris M. Thomasson submitted this idea :
> > >>>>>> On 12/2/2021 10:38 AM, mitchr...@gmail.com wrote:
> > >>>>>>> On Thursday, December 2, 2021 at 5:20:12 AM UTC-8, Serg io wrote:
> > >>>>>>>> On 12/1/2021 10:34 PM, Chris M. Thomasson wrote:
> > >>>>>>>>> On 12/1/2021 8:06 PM, Serg io wrote:
> > >>>>>>>>>> On 12/1/2021 5:57 PM, mitchr...@gmail.com wrote:
> > >>>>>>>>>>> On Wednesday, December 1, 2021 at 3:07:47 PM UTC-8, Michael
> > >>>>>>>>>>> Moroney wrote:
> > >>>>>>>>>>>> On 12/1/2021 3:46 PM, mitchr...@gmail.com wrote:
> > >>>>>>>>>>>>> you get .999 repeating again not 1 instead...
> > >>>>>>>>>>>>>
> > >>>>>>>>>>>> I get 1.
> > >>>>>>>>>>>
> > >>>>>>>>>>> You don't get it...
> > >>>>>>>>>>>
> > >>>>>>>>>>
> > >>>>>>>>>> just use 1 base(.999 repeating) = 1
> > >>>>>>>>>
> > >>>>>>>>> .999 repeating is the representation of 1 in base 10.
> > >>>>>>>> I see the mistake;
> > >>>>>>>>
> > >>>>>>>> .999repeating in base(.999 repeating) = 1
> > >>>>>>>
> > >>>>>>> ..999 repeating does not reach1.
> > >>>>>>
> > >>>>>> If you take it on a step-by-step basis, yeah, you are correct.
> > >>>>>
> > >>>>> How does a number reach?
> > >>>>
> > >>>> On a step-by-step basis, say:
> > >>>>
> > >>>> 1 = .9 = false
> > >>>> 1 = .99 = false
> > >>>> 1 = .999 = false
> > >>>> 1 = .9999 = false
> > >>>>
> > >>>> We will never get there. However, it does get infinitely close to 1...
> > >>>
> > >>> On a step-by-step basis:
> > >>>
> > >>> 1 = .9 + .1 = true
> > >>> 1 = .99 + .01 = true
> > >>> 1 = .999 + .001 = true
> > >>> 1 = .9999 + .0001 = true
> > >>>
> > >>> lol. ;^)
> > >>
> > >>
> > >>
> > >> by golly! that IS the solution!
> > >>
> > >>
> > >> so 1 = .999 repeating + 0 = true
> > >
> > > .999... is one of the ways for base 10 to represent 1. just writing 1 is
> > > another, one. ;^)
> > >
> > > Its limit is 1, it is one. Okay. Then for fun, sometimes I imagine a fantasy
> > > scenario that involves two beings that live forever... lol... ;^)
> > >
> > > Being_0 tells Being_1 to report when the following recursion equals one:
> > >
> > > r[0] = .9 / 10^0 = .9
> > > r[1] = r[0] + .9 / 10^1 = 0.99
> > > r[2] = r[1] + .9 / 10^2 = 0.999
> > > r[3] = r[2] + .9 / 10^3 = 0.9999
> > > r[4] = r[3] + .9 / 10^4 = 0.99999
> > > ...
> > >
> > > Basically:
> > >
> > > r[0] = .9 / 10^0 = .9
> > > r[n] = r[n - 1] + .9 / 10^[n]
> > >
> > > At what iteration n will Being_1 report to Being_0 that r[n] is equal to
> > > zero?
> > >
> > > ;^)
> > It won't. It only gives a successively better rational approximation
> > with each iteration.
> .999 repeating and the first integer are not the same quantity.
> They share a different kind of equality. One that is by the
> beginning quantity of Calculus...
>
> Mitchell Raemsch
they are the same, get over it

Factorials were someone's attempt to make math LOOK exciting.

tech / sci.math / .999 repeating add zero

Subject	Author
.999 repeating add zero	mitchr...@gmail.com
Re: .999 repeating add zero	Michael Moroney
Re: .999 repeating add zero	mitchr...@gmail.com
Re: .999 repeating add zero	Serg io
Re: .999 repeating add zero	Chris M. Thomasson
Re: .999 repeating add zero	FromTheRafters
Re: .999 repeating add zero	Chris M. Thomasson
Re: .999 repeating add zero	Serg io
Re: .999 repeating add zero	mitchr...@gmail.com
Re: .999 repeating add zero	Chris M. Thomasson
Re: .999 repeating add zero	FromTheRafters
Re: .999 repeating add zero	Chris M. Thomasson
Re: .999 repeating add zero	Chris M. Thomasson
Re: .999 repeating add zero	Serg io
Re: .999 repeating add zero	Chris M. Thomasson
Re: .999 repeating add zero	Chris M. Thomasson
Re: .999 repeating add zero	Chris M. Thomasson
Re: .999 repeating add zero	Serg io
Re: .999 repeating add zero	FromTheRafters
Re: .999 repeating add zero	mitchr...@gmail.com
Re: .999 repeating add zero	zelos...@gmail.com
Re: .999 repeating add zero	mitchr...@gmail.com
Re: .999 repeating add zero	Serg io
Re: .999 repeating add zero	mitchr...@gmail.com
Re: .999 repeating add zero	Serg io
Re: .999 repeating add zero	mitchr...@gmail.com
Re: .999 repeating add zero	Chris M. Thomasson
Re: .999 repeating add zero	zelos...@gmail.com
Re: .999 repeating add zero	mitchr...@gmail.com
Re: .999 repeating add zero	zelos...@gmail.com
Re: .999 repeating add zero	mitchr...@gmail.com
Re: .999 repeating add zero	Timothy Golden
Re: .999 repeating add zero	FromTheRafters
Re: .999 repeating add zero	Timothy Golden
Re: .999 repeating add zero	FromTheRafters
Re: .999 repeating add zero	Jim Burns
Re: .999 repeating add zero	Serg io
Re: .999 repeating add zero	zelos...@gmail.com
Re: .999 repeating add zero	zelos...@gmail.com