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tech / sci.math / Re: Revealing... The Logic of the Arcana ...

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* Revealing... The Logic of the Arcana ...Socratis T.n.p.
`* Re: Revealing... The Logic of the Arcana ...Socratis T.n.p.
 `* Re: Revealing... The Logic of the Arcana ...konyberg
  `- Re: Revealing... The Logic of the Arcana ...Socratis T.n.p.

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Revealing... The Logic of the Arcana ...

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Subject: Revealing... The Logic of the Arcana ...
From: andreaso...@gmail.com (Socratis T.n.p.)
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 by: Socratis T.n.p. - Wed, 29 Dec 2021 14:03 UTC

Revealing... The Logic of the Arcana ...

0.1 *0.1 *0.1 = 0.001m^3 = 1i^3
0.1 *0.1 *1 = 0.01m^3 = 10i^3
0.1 *1 *1 = 0.1m^3 = 100i^3 => For 0.1m =1i =1.dm.
1 *1 *1 = 1m^3 = 1000i^3 ======> For 1m = 10.dm.

0.2 *0.2 *0.2 = 0.008m^3 = 8i^3
0.2 *0.2 *2 = 0.08m^3 = 80i^3
0.2 *2 *2 = 0.8m^3 = 800i^3 => For 2m =2i =2.dm.
2 *2 *2 = 8m^3 = 8000i^3 =====> For 2m =20.dm.

That Logica T.d.i. : it is Derivative..It is not..Disputable.
Socratis.Rome.29.dic. 2022. => 2i *20i *20i = 400i^3.

Re: Revealing... The Logic of the Arcana ...

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Subject: Re: Revealing... The Logic of the Arcana ...
From: andreaso...@gmail.com (Socratis T.n.p.)
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 by: Socratis T.n.p. - Wed, 29 Dec 2021 21:51 UTC

Reveal The Logic of the Arcana => for 0.1 = 10c = 1i.

0.1 ***** 0.1 == 0.01m^2 = 10c *** 10c ===100c^2
0.1 *0.1 *0.1 =0.001m^3 = 10c*10c*10c =1000c^3

0.1 ***** 1 == 0.1m^2 = 10c **** 100c ===1000c^2
0.1 *0.1 *1 = 0.01m^3 = 10c*10c*100c =10'000c^3

0.1 ***** 2 == 0.2m^2 = 10c ****** 200c ==2'000c^2
0.1 *0.1 *2 = 0.02m^3 = 10c *10c *200c =20'000c^3.

Note B.: Areas lack the 10cm factor. Where Such
factor added to the previous areas ... produces the Volumes.
Do you still think 10c * 10c can produce 1cm, of m?

It simply produces: n. (100c^2) = n. cent. of m^2 .. and ..
last but not least (10c * 10c*10c).. produce n.mill. of..m^3.
Where Such thousandths of m^3 would be called Liters-kg.

That Logica T.d.i. both .. Derivative .. is .. Very clear.
Happy year. 2022. ==> 3i *2 *2 = 1200i^3 = 1.2m^3.

Re: Revealing... The Logic of the Arcana ...

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Subject: Re: Revealing... The Logic of the Arcana ...
From: konyb...@online.no (konyberg)
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 by: konyberg - Wed, 29 Dec 2021 23:30 UTC

onsdag 29. desember 2021 kl. 22:51:21 UTC+1 skrev Socratis T.n.p.:
> Reveal The Logic of the Arcana => for 0.1 = 10c = 1i.

So c = 0.01 and i = 0.1
What is your point?
KON

>
> 0.1 ***** 0.1 == 0.01m^2 = 10c *** 10c ===100c^2
> 0.1 *0.1 *0.1 =0.001m^3 = 10c*10c*10c =1000c^3
>
> 0.1 ***** 1 == 0.1m^2 = 10c **** 100c ===1000c^2
> 0.1 *0.1 *1 = 0.01m^3 = 10c*10c*100c =10'000c^3
>
> 0.1 ***** 2 == 0.2m^2 = 10c ****** 200c ==2'000c^2
> 0.1 *0.1 *2 = 0.02m^3 = 10c *10c *200c =20'000c^3.
>
> Note B.: Areas lack the 10cm factor. Where Such
> factor added to the previous areas ... produces the Volumes.
> Do you still think 10c * 10c can produce 1cm, of m?
>
> It simply produces: n. (100c^2) = n. cent. of m^2 .. and ..
> last but not least (10c * 10c*10c).. produce n.mill. of..m^3.
> Where Such thousandths of m^3 would be called Liters-kg.
>
> That Logica T.d.i. both .. Derivative .. is .. Very clear.
> Happy year. 2022. ==> 3i *2 *2 = 1200i^3 = 1.2m^3.

Re: Revealing... The Logic of the Arcana ...

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Subject: Re: Revealing... The Logic of the Arcana ...
From: andreaso...@gmail.com (Socratis T.n.p.)
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 by: Socratis T.n.p. - Thu, 30 Dec 2021 10:21 UTC

Il giorno giovedì 30 dicembre 2021 alle 00:30:28 UTC+1 konyberg ha scritto:
> onsdag 29. desember 2021 kl. 22:51:21 UTC+1 skrev Socratis T.n.p.:
> > Reveal The Logic of the Arcana => for 0.1 = 10c = 1i.
> So c = 0.01 and i = 0.1
> What is your point?
> KON

Simple ... how obvious: 0.1 = 1dm = 10cm.
1dm *1dm = 1dm^2 = 10c *10c = 100cm^2 ...
1dm^2 = 1cent of m^2 which is 100c *100c = 10'000c^2.

10m = 100dm ==> 1i *10m = 1i *100i = 100i^2..e Not 1m-Linear

y = 1dm. = 1i.
|__|__|__|__|__||__|__|__|__|__|
|__|__|__|__|__||__|__|__|__|__|
|__|__|__|__|__||__|__|__|__|__|
|__|__|__|__|__||__|__|__|__|__|
|__|__|__|__|__||__|__|__|__|__| ==>10c * 10c = 100c^2 = 0.01m^2.
|__|__|__|__|__||__|__|__|__|__|
|__|__|__|__|__||__|__|__|__|__|
|__|__|__|__|__||__|__|__|__|__|
|__|__|__|__|__||__|__|__|__|__|
|__|__|__|__|__||__|__|__|__|__| ==> x = 1dm. = 1i.

Happy year. 2022. ==> 4i *2 *2 = 1600i^3 = 1.6m^3.

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