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Teorema : (n-d) * n * (n+d) = n^3 - n*d^2

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Subject: Teorema : (n-d) * n * (n+d) = n^3 - n*d^2
From: andreaso...@gmail.com (Socratis T.n.p.)
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by: Socratis T.n.p. - Sat, 8 Jan 2022 18:58 UTC

Teorema : (n-d) * n * (n+d) = n^3 - n*d^2

5 * 6 * 7 = 6^3 -(6*1^2) = 210m^3
5 * 7 * 9 = 7^3 -(7*2^2) = 315m^3

10 * 13 * 16 = 13^3 -(13*3^3) = 2'080m^3
10i *20i *30i = i20^3 -(i20*i10^2)=6000i^3

10i *20i *30i === 6000i^3
1 * 2 * 3 = 6m^3=6000i^3
20i * 30i = 600i^2 = 6m^2

Felice anno 2022 ==> 4.5*9*18 = 9^3.

Re: Teorema : (n-d) * n * (n+d) = n^3 - n*d^2

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Subject: Re: Teorema : (n-d) * n * (n+d) = n^3 - n*d^2
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by: nabru - Sat, 8 Jan 2022 20:10 UTC

Em 08/01/2022 15:58, Socratis T.n.p. escreveu:
> Teorema : (n-d) * n * (n+d) = n^3 - n*d^2

(n-d)(n+d) = n^2-d^2
n(n-d)(n+d) = n^3-nd^2

Nothing really new.
--
This PIZZA symbolizes my COMPLETE EMOTIONAL RECOVERY!! ~nabru.

Re: Teorema : (n-d) * n * (n+d) = n^3 - n*d^2

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Subject: Re: Teorema : (n-d) * n * (n+d) = n^3 - n*d^2
From: andreaso...@gmail.com (Socratis T.n.p.)
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by: Socratis T.n.p. - Sat, 8 Jan 2022 21:13 UTC

Il giorno sabato 8 gennaio 2022 alle 21:10:27 UTC+1 nabru ha scritto:
> Em 08/01/2022 15:58, Socratis T.n.p. escreveu:
> > Teorema : (n-d) * n * (n+d) = n^3 - n*d^2
> (n-d)(n+d) = n^2-d^2
> n(n-d)(n+d) = n^3-nd^2
>
> Nothing really new.

Esisteva questo Teorema ?
Se non esisteva, significa che io l'ho Inventato..a parte il prodotto di polinomi...
Ho creato parecchi Teoremi e leggi..e infine ho inventato La T.n.p.

a^3 +b^3 = a+b * (ab+d^2)
6^3 +8^3 =14 *(48+4) =728m^3-

Grazie perla tua risposta interessante.
Socratis.

Spock: We suffered 23 casualties in that attack, Captain.

tech / sci.math / Re: Teorema : (n-d) * n * (n+d) = n^3 - n*d^2

Subject	Author
Teorema : (n-d) * n * (n+d) = n^3 - n*d^2	Socratis T.n.p.
Re: Teorema : (n-d) * n * (n+d) = n^3 - n*d^2	nabru
*Re: Teorema : (n-d) n * (n+d) = n^3 - nd^2*	Socratis T.n.p.