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tech / sci.physics.relativity / [SR] Who can confirm this equation?

SubjectAuthor
* [SR] Who can confirm this equation?Richard Hachel
`* Re: [SR] Who can confirm this equation?Python
 `* Re: [SR] Who can confirm this equation?Richard Hachel
  +* Re: [SR] Who can confirm this equation?Python
  |+- Re: [SR] Who can confirm this equation?Maciej Wozniak
  |`* Re: [SR] Who can confirm this equation?Richard Hachel
  | `* Re: [SR] Who can confirm this equation?Python
  |  +- Re: [SR] Who can confirm this equation?Python
  |  `- Re: [SR] Who can confirm this equation?Richard Hachel
  `* Re: [SR] Who can confirm this equation?Joe Chikanatsu
   `* Re: [SR] Who can confirm this equation?Richard Hachel
    `* Re: [SR] Who can confirm this equation?Python
     +- Re: [SR] Who can confirm this equation?Richard Hachel
     `* Re: [SR] Who can confirm this equation?Richard Hachel
      `* Re: [SR] Who can confirm this equation?Python
       `* Re: [SR] Who can confirm this equation?Richard Hachel
        `* Re: [SR] Who can confirm this equation?Python
         +* Re: [SR] Who can confirm this equation?Maciej Wozniak
         |+* Re: [SR] Who can confirm this equation?Python
         ||`- Re: [SR] Who can confirm this equation?Maciej Wozniak
         |`- Re: [SR] Who can confirm this equation?Richard Hachel
         `* Re: [SR] Who can confirm this equation?Richard Hachel
          `* Re: [SR] Who can confirm this equation?Python
           +- Re: [SR] Who can confirm this equation?Maciej Wozniak
           `- Re: [SR] Who can confirm this equation?Richard Hachel

1
[SR] Who can confirm this equation?

<IbqthqtCrEkJoC6dIEUwaL_DGAU@jntp>

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Fri, 15 Apr 2022 00:16 UTC

Who can confirm this equation?

I recently gave the equation to use in the case of a relativistic problem
with acceleration.

For example, it can be used in the Traveler problem of Tau Ceti (12 ly in
10m/s² acceleration).

This problem is not obvious in the sense that the terrestrial observer is
not in the frame of reference of the rocket, and it will be less and less
so as the latter will accelerate.

It is clear to anyone who thinks a little (without the need to do any
calculations) that the acceleration observed in the terrestrial frame of
reference will seem increasingly weak as the observable speed Vo
approaches c.

But what is the equation to use to directly know this acceleration
observed in the terrestrial reference frame?

It is obviously proportional to the constant acceleration which is in the
frame of reference of the rocket (proper acceleration a), and also to the
time which passes in the laboratory (To).

These two measurements must appear in the equation.

I give it here.

<http://news2.nemoweb.net/jntp?IbqthqtCrEkJoC6dIEUwaL_DGAU@jntp/Data.Media:1>

You can test its veracity.

Thank you for listening.

R.H.

--
"Mais ne nous trompons pas. Il n'y a pas que de la violence
avec des armes : il y a des situations de violence."
Abbé Pierre.
<http://news2.nemoweb.net/?DataID=IbqthqtCrEkJoC6dIEUwaL_DGAU@jntp>

Re: [SR] Who can confirm this equation?

<t3af1v$cp0$1@gioia.aioe.org>

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From: pyt...@example.invalid (Python)
Newsgroups: sci.physics.relativity
Subject: Re: [SR] Who can confirm this equation?
Date: Fri, 15 Apr 2022 02:43:08 +0200
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 by: Python - Fri, 15 Apr 2022 00:43 UTC

Richard "Hachel" Lengrand (M.D.) :
> Who can confirm this equation?
>
> I recently gave the equation to use in the case of a relativistic
> problem with acceleration.
>
> For example, it can be used in the Traveler problem of Tau Ceti (12 ly
> in 10m/s² acceleration).
>
> This problem is not obvious in the sense that the terrestrial observer
> is not in the frame of reference of the rocket, and it will be less and
> less so as the latter will accelerate.
>
> It is clear to anyone who thinks a little (without the need to do any
> calculations) that the acceleration observed in the terrestrial frame of
> reference will seem increasingly weak as the observable speed Vo
> approaches c.
>
> But what is the equation to use to directly know this acceleration
> observed in the terrestrial reference frame?
>
> It is obviously proportional to the constant acceleration which is in
> the frame of reference of the rocket (proper acceleration a), and also
> to the time which passes in the laboratory (To).
>
> These two measurements must appear in the equation.
>
> I give it here.
>
> <http://news2.nemoweb.net/jntp?IbqthqtCrEkJoC6dIEUwaL_DGAU@jntp/Data.Media:1>

What prevent you to post it in text form?

i.e. a*(2*sqrt(1+(a*t/c)^2) - 1)^(-3/2)

Using "usual" notations. At least the ones used in Paul's article.

Oh, by the way your formula is not proportional at all to the time t
(what you probably call To), are you really ignorant of what
"proportional" means?

The correct equation can be obtained from:

dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt

Which is quite an easy exercise, right?

Re: [SR] Who can confirm this equation?

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Fri, 15 Apr 2022 02:14 UTC

Le 15/04/2022 à 02:42, Jean-Pierre Messager (Python) a écrit :

>> I give it here.
>>
>> <http://news2.nemoweb.net/jntp?IbqthqtCrEkJoC6dIEUwaL_DGAU@jntp/Data.Media:1>
>
> What prevent you to post it in text form?
>
> a'= a*(2*sqrt(1+(a*t/c)^2)-1)^(-3/2)

Yes.
>
> Using "usual" notations. At least the ones used in Paul's article.
>
> Oh, by the way your formula is not proportional at all to the time t
> (what you probably call To), are you really ignorant of what
> "proportional" means?

You confuse To (observable time) and Tr (proper timer)
>
> The correct equation can be obtained from:
>
> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
>
> Which is quite an easy exercise, right?

I note : a'= a*(2*sqrt(1+(a*To/c)^2)-1)^(-3/2)

dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt

? ? ?

Are you sure that is not a huge conceptual blunder?

R.H.

Re: [SR] Who can confirm this equation?

<t3al3v$4tv$1@gioia.aioe.org>

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From: pyt...@example.invalid (Python)
Newsgroups: sci.physics.relativity
Subject: Re: [SR] Who can confirm this equation?
Date: Fri, 15 Apr 2022 04:26:36 +0200
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 by: Python - Fri, 15 Apr 2022 02:26 UTC

Richard "Hachel" Lengrand (M.D.) wrote:
> Le 15/04/2022 à 02:42, Jean-Pierre Messager (Python) a écrit :
>
>>> I give it here.
>>>
>>> <http://news2.nemoweb.net/jntp?IbqthqtCrEkJoC6dIEUwaL_DGAU@jntp/Data.Media:1>
>>
>>
>> What prevent you to post it in text form?
>>
>> a'= a*(2*sqrt(1+(a*t/c)^2)-1)^(-3/2)
>
> Yes.
>>
>> Using "usual" notations. At least the ones used in Paul's article.
>>
>> Oh, by the way your formula is not proportional at all to the time t
>> (what you probably call To), are you really ignorant of what
>> "proportional" means?
>
>  You confuse To (observable time) and Tr (proper timer)

I'm not even talking about that, your equation is not proportional
to what you pretend it is. *sigh*

>> The correct equation can be obtained from:
>>
>> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
>>
>> Which is quite an easy exercise, right?
>
> I note : a'= a*(2*sqrt(1+(a*To/c)^2)-1)^(-3/2)
>
>
> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
>
> ? ? ?

You know dérivatives ("dérivées") Lengrand?
The derivative of v (as measured in Earth's frame) by
time (as measured in Earth's frame) is equal to
acceleration (etc.)

This is the fucking definition of acceleration!!!

> Are you sure that is not a huge conceptual blunder?

This is quite basic stuff...

Re: [SR] Who can confirm this equation?

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Subject: Re: [SR] Who can confirm this equation?
From: maluwozn...@gmail.com (Maciej Wozniak)
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 by: Maciej Wozniak - Fri, 15 Apr 2022 05:01 UTC

On Friday, 15 April 2022 at 04:26:10 UTC+2, Python wrote:
> Richard "Hachel" Lengrand (M.D.) wrote:
> > Le 15/04/2022 à 02:42, Jean-Pierre Messager (Python) a écrit :
> >
> >>> I give it here.
> >>>
> >>> <http://news2.nemoweb.net/jntp?IbqthqtCrEkJoC6dIEUwaL_DGAU@jntp/Data.Media:1>
> >>
> >>
> >> What prevent you to post it in text form?
> >>
> >> a'= a*(2*sqrt(1+(a*t/c)^2)-1)^(-3/2)
> >
> > Yes.
> >>
> >> Using "usual" notations. At least the ones used in Paul's article.
> >>
> >> Oh, by the way your formula is not proportional at all to the time t
> >> (what you probably call To), are you really ignorant of what
> >> "proportional" means?
> >
> > You confuse To (observable time) and Tr (proper timer)
> I'm not even talking about that, your equation is not proportional
> to what you pretend it is. *sigh*
> >> The correct equation can be obtained from:
> >>
> >> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
> >>
> >> Which is quite an easy exercise, right?
> >
> > I note : a'= a*(2*sqrt(1+(a*To/c)^2)-1)^(-3/2)
> >
> >
> > dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
> >
> > ? ? ?
> You know dérivatives ("dérivées") Lengrand?

Oh, stinker Python is opening its muzzle again,
and trying to pretend he knows something.
Tell me, poor stinker, what is your definition of
a "theory" in the terms of Peano arithmetic?
See: if a theorem is going to be a part of a theory,
it has to be formulable in the language of the
theory. Do you get it? Or are you too stupid even for
that, poor stinker?

> The derivative of v (as measured in Earth's frame) by
> time (as measured in Earth's frame) is equal to
> acceleration (etc.)

A common sense prejudice, refuted by
your idiot guru with his ingenious elevator
gedanken.

Re: [SR] Who can confirm this equation?

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From: qsp...@rybvriqn.cq (Joe Chikanatsu)
Newsgroups: sci.physics.relativity
Subject: Re: [SR] Who can confirm this equation?
Date: Fri, 15 Apr 2022 05:34:17 -0000 (UTC)
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 by: Joe Chikanatsu - Fri, 15 Apr 2022 05:34 UTC

Richard Hachel wrote:

>> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
>> Which is quite an easy exercise, right?
>
> I note : a'= a*(2*sqrt(1+(a*To/c)^2)-1)^(-3/2)
> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt

you guys are making shit up worse than Einstine, jumping things off. There
is no v(t) in that equation. What you say is just "conceptual".

Re: [SR] Who can confirm this equation?

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Fri, 15 Apr 2022 13:34 UTC

Le 15/04/2022 à 04:26, Python a écrit :

>>> a'= a*(2*sqrt(1+(a*t/c)^2)-1)^(-3/2)
>>
>> Yes.

Hachel is the best, the greatest.

> The derivative of v (as measured in Earth's frame) by
> time (as measured in Earth's frame) is equal to
> acceleration (etc.)

Et mes couilles, tu les dérives comment?


>
> This is the fucking definition of acceleration!!!

Non.

Pas dans ce cas de figure relativiste.

Si tu me dis que "Vr by time Tr (temps propre)" is egual to acceleration
a.

Je te dirai oui, selon qu'il est saintement écrit : "Il était
absolument génial, cet Hachel,
allant même jusqu'à reconnaître la bite des autres quand ils disaient
vrai".

Mais la claque dans la gueule va vite venir, Jean-Pierre.

Si tu me dis (ou me répête) que, je te cite :

> The derivative of v (as measured in Earth's frame) by
> time (as measured in Earth's frame) is equal to
> acceleration (etc.)

Là, la claque dans la gueule, elle vient tout de suite.

Maintenant, bouges toi un peu les couilles.

Prends trois tasses de cafés, et réfléchis.

Puis viens me présenter tes excuses.

J'en ai marre de tous ces cons qui, depuis 30 ans, viennent contredire
tous azimuts ce que je dis (pas seulement en relativité, aussi dans
d'autres domaines) sans avoir réfléchi une seconde que les cons,
c'était eux.

Je te supplie d'essayer de comprendre :
v=a.t

Je te supplie de comprendre ça.

Puis de COMPRENDRE qu'on peut poser :

Vr=a.Tr et qu'en cela, on peut même tracer une droite sur un repère.

Et on aura raison, comme on aura raison si on écrit x=1/2 a.t²

En faisant attention de bien le comprendre comme : x(Ro)=(1/2)
a(R)/T²(R)

Putain, je te demande de comprendre ça.

Ca y est, c'est bon, là?

Bon, ensuite, tu vas écrire, parce que tu es curieux et que tu veux
connaître a° par rapport à To :

Vo=a°.To et donc a°=To/Vo

A première vue, ça parait mathématiquement évident, sauf que...

Mais là, tous ceux qui lisent ont déjà quelques frissons dans le slip.

Pourquoi?

Tu comprends ta bourde?

R.H.

Re: [SR] Who can confirm this equation?

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Fri, 15 Apr 2022 13:36 UTC

Le 15/04/2022 à 07:34, Joe Chikanatsu a écrit :
> Richard Hachel wrote:
>
>>> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
>>> Which is quite an easy exercise, right?
>>
>> I note : a'= a*(2*sqrt(1+(a*To/c)^2)-1)^(-3/2)
>> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
>
> you guys are making shit up worse than Einstine, jumping things off. There
> is no v(t) in that equation. What you say is just "conceptual".

I didn't write that.

That's Python bullshit.

R.H.

Re: [SR] Who can confirm this equation?

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From: pyt...@example.invalid (Python)
Newsgroups: sci.physics.relativity
Subject: Re: [SR] Who can confirm this equation?
Date: Fri, 15 Apr 2022 16:25:52 +0200
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 by: Python - Fri, 15 Apr 2022 14:25 UTC

Richard "Hachel" Lengrand (M.D.) wrote:
> Le 15/04/2022 à 04:26, Python a écrit :
>
>>>> a'= a*(2*sqrt(1+(a*t/c)^2)-1)^(-3/2)
>>>
>>> Yes.
>
> Hachel is the best, the greatest.
>> The derivative of v (as measured in Earth's frame) by
>> time (as measured in Earth's frame) is equal to
>> acceleration (etc.)
>
> Et mes couilles, tu les dérives comment?

By kicking them with a baseball bat. The main problem is that
they are so small that it requires high shooting accuracy.

>>
>> This is the fucking definition of acceleration!!!
>
> Non.

Of course it is. Acceleration is the derivative of speed wrt
time, both measured in the same frame of reference. *sigh*

> J'en ai marre de tous ces cons qui, depuis 30 ans, viennent contredire
> tous azimuts ce que je dis (pas seulement en relativité, aussi dans
> d'autres domaines) sans avoir réfléchi une seconde que les cons, c'était
> eux.

Fact is that in all domains you expressed yourself you only
show confusion, blunders and auto-contradiction. In physics,
in math, in history of science, etc. On top of that you have
ZERO integrity.

You are a human failure, Richard, from an intellectual point
of view and a moral point of view.

By the way, as you failed to differentiate the formula I've
provided, I did it for you :

dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt

= a * [ 1 + (a*t)/c^2 ] ^ (-3/2)

Your proposition : a*(2*sqrt(1+(a*t/c)^2)-1)^(-3/2) is WRONG.

Re: [SR] Who can confirm this equation?

<t3bvcb$uqm$2@gioia.aioe.org>

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From: pyt...@example.invalid (Python)
Newsgroups: sci.physics.relativity
Subject: Re: [SR] Who can confirm this equation?
Date: Fri, 15 Apr 2022 16:27:53 +0200
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 by: Python - Fri, 15 Apr 2022 14:27 UTC

Python wrote:
....
> By the way, as you failed to differentiate the formula I've
> provided, I did it for you :
>
> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
>
>          = a * [ 1 + (a*t)/c^2 ] ^ (-3/2)

Typo: a * [ 1 + (a*t/c)^2 ] ^ (-3/2)

> Your proposition : a*(2*sqrt(1+(a*t/c)^2)-1)^(-3/2) is WRONG.

Still...

Re: [SR] Who can confirm this equation?

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Fri, 15 Apr 2022 14:33 UTC

Le 15/04/2022 à 16:25, Python a écrit :

> You are a human failure, Richard, from an intellectual point
> of view and a moral point of view.

Des fois, j'aime ce que tu écris.

Je te trouve beau (sans rire).

R.H.

Re: [SR] Who can confirm this equation?

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From: pyt...@example.invalid (Python)
Newsgroups: sci.physics.relativity
Subject: Re: [SR] Who can confirm this equation?
Date: Fri, 15 Apr 2022 16:47:59 +0200
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 by: Python - Fri, 15 Apr 2022 14:47 UTC

Richard "Hachel" Lengrand (M.D.) wrote:
> Le 15/04/2022 à 07:34, Joe Chikanatsu a écrit :
>> Richard Hachel wrote:
>>
>>>> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
>>>> Which is quite an easy exercise, right?
>>>
>>>  I note : a'= a*(2*sqrt(1+(a*To/c)^2)-1)^(-3/2)
>>> dv(t)/dt = d[ at/sqrt(1+(at/c)^2) ] / dt
>>
>> you guys are making shit up worse than Einstine, jumping things off.
>> There is no v(t) in that equation. What you say is just "conceptual".
>
> I didn't write that.

Nobody pretented you did. Moreover you are answering
to the nym-shifter troll, this is patheticly stupid.

Here is the correct formula for acceleration as function
of time, all measured in Earth's frame of reference.

dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)

The equation you've proposed is WRONG.

Re: [SR] Who can confirm this equation?

<_1rKAUnWCvd-eessQNPcARL7uco@jntp>

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Fri, 15 Apr 2022 14:49 UTC

Le 15/04/2022 à 16:47, Python a écrit :
>> I didn't write that.
>
> Nobody pretented you did. Moreover you are answering
> to the nym-shifter troll, this is patheticly stupid.
>
> Here is the correct formula for acceleration as function
> of time, all measured in Earth's frame of reference.
>
> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>
> The equation you've proposed is WRONG.

Re: [SR] Who can confirm this equation?

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Fri, 15 Apr 2022 14:50 UTC

Le 15/04/2022 à 16:47, Python a écrit :

> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>
> The equation you've proposed is WRONG.

<http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>

R.H.

--
"Mais ne nous trompons pas. Il n'y a pas que de la violence
avec des armes : il y a des situations de violence."
Abbé Pierre.
<http://news2.nemoweb.net/?DataID=4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp>

Re: [SR] Who can confirm this equation?

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From: pyt...@example.invalid (Python)
Newsgroups: sci.physics.relativity
Subject: Re: [SR] Who can confirm this equation?
Date: Fri, 15 Apr 2022 16:56:02 +0200
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 by: Python - Fri, 15 Apr 2022 14:56 UTC

Richard "Hachel" Lengrand (M.D.) wrote:
> Le 15/04/2022 à 16:47, Python a écrit :
>
>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>>
>> The equation you've proposed is WRONG.
>
> <http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>

Still wrong.

Re: [SR] Who can confirm this equation?

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Fri, 15 Apr 2022 14:57 UTC

Le 15/04/2022 à 16:55, Python a écrit :
> Richard "Hachel" Lengrand (M.D.) wrote:
>> Le 15/04/2022 à 16:47, Python a écrit :
>>
>>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>>>
>>> The equation you've proposed is WRONG.
>>
>> <http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>
>
> Still wrong.

Why still?

Why wrong?

R.H.

Re: [SR] Who can confirm this equation?

<t3c19i$1ri2$2@gioia.aioe.org>

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From: pyt...@example.invalid (Python)
Newsgroups: sci.physics.relativity
Subject: Re: [SR] Who can confirm this equation?
Date: Fri, 15 Apr 2022 17:00:32 +0200
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 by: Python - Fri, 15 Apr 2022 15:00 UTC

Richard "Hachel" Lengrand (M.D.) wrote:
> Le 15/04/2022 à 16:55, Python a écrit :
>> Richard "Hachel" Lengrand (M.D.) wrote:
>>> Le 15/04/2022 à 16:47, Python a écrit :
>>>
>>>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>>>>
>>>> The equation you've proposed is WRONG.
>>>
>>> <http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>
>>
>>
>> Still wrong.
>
> Why still?

Because it's still the same sh*t.

> Why wrong?

Check you're derivation, if you have some, you goofed
somewhere.

I derived the equation a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
from Lorentz Transformation. It is the correct formula.

Re: [SR] Who can confirm this equation?

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Subject: Re: [SR] Who can confirm this equation?
From: maluwozn...@gmail.com (Maciej Wozniak)
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 by: Maciej Wozniak - Fri, 15 Apr 2022 15:47 UTC

On Friday, 15 April 2022 at 17:00:05 UTC+2, Python wrote:
> Richard "Hachel" Lengrand (M.D.) wrote:
> > Le 15/04/2022 à 16:55, Python a écrit :
> >> Richard "Hachel" Lengrand (M.D.) wrote:
> >>> Le 15/04/2022 à 16:47, Python a écrit :
> >>>
> >>>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
> >>>>
> >>>> The equation you've proposed is WRONG.
> >>>
> >>> <http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>
> >>
> >>
> >> Still wrong.
> >
> > Why still?
> Because it's still the same sh*t.
Oh, stinker Python is opening its muzzle again,
and trying to pretend he knows something.
Tell me, poor stinker, what is your definition of
a "theory" in the terms of Peano arithmetic?
See: if a theorem is going to be a part of a theory,
it has to be formulable in the language of the
theory. Do you get it? Or are you too stupid even for
that, poor stinker?

Re: [SR] Who can confirm this equation?

<t3c4it$1mtp$1@gioia.aioe.org>

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From: pyt...@example.invalid (Python)
Newsgroups: sci.physics.relativity
Subject: Re: [SR] Who can confirm this equation?
Date: Fri, 15 Apr 2022 17:56:13 +0200
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 by: Python - Fri, 15 Apr 2022 15:56 UTC

Confused ranting senile crank Maciej Wozniak wrote:
> On Friday, 15 April 2022 at 17:00:05 UTC+2, Python wrote:
>> Richard "Hachel" Lengrand (M.D.) wrote:
>>> Le 15/04/2022 à 16:55, Python a écrit :
>>>> Richard "Hachel" Lengrand (M.D.) wrote:
>>>>> Le 15/04/2022 à 16:47, Python a écrit :
>>>>>
>>>>>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>>>>>>
>>>>>> The equation you've proposed is WRONG.
>>>>>
>>>>> <http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>
>>>>
>>>>
>>>> Still wrong.
>>>
>>> Why still?
>> Because it's still the same sh*t.
> Oh, stinker Python is opening its muzzle again,
> and trying to pretend he knows something.
> Tell me, poor stinker, what is your definition of
> a "theory" in the terms of Peano arithmetic?
> See: if a theorem is going to be a part of a theory,
> it has to be formulable in the language of the
> theory. Do you get it? Or are you too stupid even for
> that, poor stinker?

Maciej your confused rant against Gôdel's Theorems is boring.

I'm quite sure you are as confused about many other stuff.

What about ranting about Turing Halting Problem? Cantor's transfinities?
Darwin's evolution?

Re: [SR] Who can confirm this equation?

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Subject: Re: [SR] Who can confirm this equation?
From: maluwozn...@gmail.com (Maciej Wozniak)
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 by: Maciej Wozniak - Fri, 15 Apr 2022 16:18 UTC

On Friday, 15 April 2022 at 17:56:19 UTC+2, Python wrote:
> Confused ranting senile crank Maciej Wozniak wrote:
> > On Friday, 15 April 2022 at 17:00:05 UTC+2, Python wrote:
> >> Richard "Hachel" Lengrand (M.D.) wrote:
> >>> Le 15/04/2022 à 16:55, Python a écrit :
> >>>> Richard "Hachel" Lengrand (M.D.) wrote:
> >>>>> Le 15/04/2022 à 16:47, Python a écrit :
> >>>>>
> >>>>>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
> >>>>>>
> >>>>>> The equation you've proposed is WRONG.
> >>>>>
> >>>>> <http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>
> >>>>
> >>>>
> >>>> Still wrong.
> >>>
> >>> Why still?
> >> Because it's still the same sh*t.
> > Oh, stinker Python is opening its muzzle again,
> > and trying to pretend he knows something.
> > Tell me, poor stinker, what is your definition of
> > a "theory" in the terms of Peano arithmetic?
> > See: if a theorem is going to be a part of a theory,
> > it has to be formulable in the language of the
> > theory. Do you get it? Or are you too stupid even for
> > that, poor stinker?
> Maciej your confused rant against Gôdel's Theorems is boring.

Oh, stinker Python is opening its muzzle again,
and trying to pretend he knows something.
Tell me, poor stinker, what is your definition of
a "theory" in the terms of Peano arithmetic?
See: if a theorem is going to be a part of a theory,
it has to be formulable in the language of the
theory. Do you get it? Or are you too stupid even for
that, poor stinker?

Re: [SR] Who can confirm this equation?

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Fri, 15 Apr 2022 20:59 UTC

Le 15/04/2022 à 17:00, Python a écrit :
> Richard "Hachel" Lengrand (M.D.) wrote:
>> Le 15/04/2022 à 16:55, Python a écrit :
>>> Richard "Hachel" Lengrand (M.D.) wrote:
>>>> Le 15/04/2022 à 16:47, Python a écrit :
>>>>
>>>>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>>>>>
>>>>> The equation you've proposed is WRONG.
>>>>
>>>> <http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>
>>>
>>>
>>> Still wrong.
>>
>> Why still?
>
> Because it's still the same sh*t.
>
>> Why wrong?
>
> Check you're derivation, if you have some, you goofed
> somewhere.
>
> I derived the equation a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
> from Lorentz Transformation. It is the correct formula.

? ? ?

R.H.

Re: [SR] Who can confirm this equation?

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Fri, 15 Apr 2022 21:01 UTC

Le 15/04/2022 à 17:47, Maciej Wozniak a écrit :

>> >>>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>> >>>>
>> >>>> The equation you've proposed is WRONG.

>> > Why still?
>> Because it's still the same sh*t.

> Oh, stinker Python

Python is a fool.

A crank anti-Hachel.

Il dit n'importe quoi.

R.H.

Re: [SR] Who can confirm this equation?

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From: pyt...@example.invalid (Python)
Newsgroups: sci.physics.relativity
Subject: Re: [SR] Who can confirm this equation?
Date: Sat, 16 Apr 2022 04:06:07 +0200
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 by: Python - Sat, 16 Apr 2022 02:06 UTC

Richard "Hachel" Lengrand wrote:
> Le 15/04/2022 à 17:00, Python a écrit :
>> Richard "Hachel" Lengrand (M.D.) wrote:
>>> Le 15/04/2022 à 16:55, Python a écrit :
>>>> Richard "Hachel" Lengrand (M.D.) wrote:
>>>>> Le 15/04/2022 à 16:47, Python a écrit :
>>>>>
>>>>>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>>>>>>
>>>>>> The equation you've proposed is WRONG.
>>>>>
>>>>> <http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>
>>>>
>>>>
>>>>
>>>> Still wrong.
>>>
>>> Why still?
>>
>> Because it's still the same sh*t.
>>
>>> Why wrong?
>>
>> Check you're derivation, if you have some, you goofed
>> somewhere.
>>
>> I derived the equation a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>> from Lorentz Transformation. It is the correct formula.
>
> ? ? ?

You want the full derivation, really? It is TRIVIAL.

Re: [SR] Who can confirm this equation?

<05ed8704-8424-48b3-ada8-49643dc8c433n@googlegroups.com>

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https://www.novabbs.com/tech/article-flat.php?id=87972&group=sci.physics.relativity#87972

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Subject: Re: [SR] Who can confirm this equation?
From: maluwozn...@gmail.com (Maciej Wozniak)
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 by: Maciej Wozniak - Sat, 16 Apr 2022 07:16 UTC

On Saturday, 16 April 2022 at 04:06:09 UTC+2, Python wrote:
> Richard "Hachel" Lengrand wrote:
> > Le 15/04/2022 à 17:00, Python a écrit :
> >> Richard "Hachel" Lengrand (M.D.) wrote:
> >>> Le 15/04/2022 à 16:55, Python a écrit :
> >>>> Richard "Hachel" Lengrand (M.D.) wrote:
> >>>>> Le 15/04/2022 à 16:47, Python a écrit :
> >>>>>
> >>>>>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
> >>>>>>
> >>>>>> The equation you've proposed is WRONG.
> >>>>>
> >>>>> <http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>
> >>>>
> >>>>
> >>>>
> >>>> Still wrong.
> >>>
> >>> Why still?
> >>
> >> Because it's still the same sh*t.
> >>
> >>> Why wrong?
> >>
> >> Check you're derivation, if you have some, you goofed
> >> somewhere.
> >>
> >> I derived the equation a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
> >> from Lorentz Transformation. It is the correct formula.
> >
> > ? ? ?
> You want the full derivation, really? It is TRIVIAL.

Oh, stinker Python is opening its muzzle again,
and trying to pretend he knows something.
Tell me, poor stinker, what is your definition of
a "theory" in the terms of Peano arithmetic?
See: if a theorem is going to be a part of a theory,
it has to be formulable in the language of the
theory. Do you get it? Or are you too stupid even for
that, poor stinker?

Re: [SR] Who can confirm this equation?

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From: r.hac...@tiscali.fr (Richard Hachel)
 by: Richard Hachel - Sat, 16 Apr 2022 14:32 UTC

Le 16/04/2022 à 04:06, Python a écrit :
> Richard "Hachel" Lengrand wrote:
>> Le 15/04/2022 à 17:00, Python a écrit :
>>> Richard "Hachel" Lengrand (M.D.) wrote:
>>>> Le 15/04/2022 à 16:55, Python a écrit :
>>>>> Richard "Hachel" Lengrand (M.D.) wrote:
>>>>>> Le 15/04/2022 à 16:47, Python a écrit :
>>>>>>
>>>>>>> dv(t)/dt = a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>>>>>>>
>>>>>>> The equation you've proposed is WRONG.
>>>>>>
>>>>>> <http://news2.nemoweb.net/jntp?4A1UnKowG8JJNHmoAWQSwOwvT9I@jntp/Data.Media:1>
>>>>>
>>>>>
>>>>>
>>>>> Still wrong.
>>>>
>>>> Why still?
>>>
>>> Because it's still the same sh*t.
>>>
>>>> Why wrong?
>>>
>>> Check you're derivation, if you have some, you goofed
>>> somewhere.
>>>
>>> I derived the equation a * [ 1 + (a*t/c)^2 ] ^ (-3/2)
>>> from Lorentz Transformation. It is the correct formula.
>>
>> ? ? ?
>
> You want the full derivation, really? It is TRIVIAL.

Why not?

R.H.

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