x'=x-vt
y'=y
z'=z
t'=t-vx/c^2

inverse equations

x = x' - v't'

v't' = -vt

x = x' + vt
y = y'
z = z'
t = t' + vx/c^2

So the equations are in the form scientists say they insist on. t is the time of a clock in S, t' is the time of a clock in S'. The equations show reality as it actually exists. If a pilot in an airplane has a clock that is slower than a clock on the ground, as Einstein proposed, then t' is the time of the clock in the airplane, and v' is the speed of the airplane according to the time of the clock in the airplane that shows t'. Since there is no length contraction in the Galilean transformation equations, the distance the airplane travels is the same as observed from either frame of reference. This enables us to say

x = x' - v't'
ct = ct' - v't'
ct = ct' +vt
t = t' + vt/c
t = t' + vct/c^2
t = t' + vx/c^2

which is the same equation we got for the times using

x'=x-vt

ct' = ct -vt
t' = t - vt/c
t' = t - vx/c^2

Robert Winn wrote:

> x'=x-vt y'=y z'=z t'=t-vx/c^2
>
> inverse equations

EXTRA: JAPAN HALTS MODERNA VACCINE, ITS CONTAMINATED WITH MAGNETIC
SUBSTANCE MINISTRY SAYS

Op 03-sep.-2021 om 20:51 schreef Robert Winn:
> x'=x-vt
> y'=y
> z'=z
> t'=t-vx/c^2
>
> inverse equations

When I solve these equations for x, y, z, t, I get

x = g^2 ( x' + v t' )
y = y'
z = z'
t = g^2 ( t' + v x / c^2 )
where
g = 1 / sqrt( 1 - v^2/c^2 )

But you have this:

> x = x' - v't'
>
> v't' = -vt
>
> x = x' + vt
> y = y'
> z = z'
> t = t' + vx/c^2

Please solve these last four equations for x', y', z', t'.
Whet do you get?

Dirk Vdm

Robert Winn <rbwinn3@gmail.com> wrote:
> x'=x-vt
> y'=y
> z'=z
> t'=t-vx/c^2
>
> inverse equations
>
> x = x' - v't'
>
> v't' = -vt
>
> x = x' + vt
> y = y'
> z = z'
> t = t' + vx/c^2

These equations were proposed about 120 years ago by another scientist (not
Einstein). It’s probably worth your time finding out who did them before
you, and how it was determined that they are not right.

>
> So the equations are in the form scientists say they insist on. t is the
> time of a clock in S, t' is the time of a clock in S'. The equations
> show reality as it actually exists. If a pilot in an airplane has a
> clock that is slower than a clock on the ground, as Einstein proposed,
> then t' is the time of the clock in the airplane, and v' is the speed of
> the airplane according to the time of the clock in the airplane that
> shows t'. Since there is no length contraction in the Galilean
> transformation equations, the distance the airplane travels is the same
> as observed from either frame of reference. This enables us to say
>
> x = x' - v't'
> ct = ct' - v't'
> ct = ct' +vt
> t = t' + vt/c
> t = t' + vct/c^2
> t = t' + vx/c^2
>
> which is the same equation we got for the times using
>
> x'=x-vt
>
> ct' = ct -vt
> t' = t - vt/c
> t' = t - vx/c^2
>

--
Odd Bodkin -- maker of fine toys, tools, tables

On Friday, September 3, 2021 at 11:51:55 AM UTC-7, Robert Winn wrote:
> x'=x-vt
> y'=y
> z'=z
> t'=t-vx/c^2
>
> inverse equations
>
> x = x' - v't'
Bzzt, wrong. You are unemployed again.

On Friday, September 3, 2021 at 12:40:07 PM UTC-7, Dirk Van de moortel wrote:
> Op 03-sep.-2021 om 20:51 schreef Robert Winn:
> > x'=x-vt
> > y'=y
> > z'=z
> > t'=t-vx/c^2
> >
> > inverse equations
> When I solve these equations for x, y, z, t, I get
>
> x = g^2 ( x' + v t' )
> y = y'
> z = z'
> t = g^2 ( t' + v x / c^2 )
> where
> g = 1 / sqrt( 1 - v^2/c^2 )
>
> But you have this:
> > x = x' - v't'
> >
> > v't' = -vt
> >
> > x = x' + vt
> > y = y'
> > z = z'
> > t = t' + vx/c^2
> Please solve these last four equations for x', y', z', t'.
> Whet do you get?
>
> Dirk Vdm
I know how difficult this must seem.
x = x' + vt
x' = x - vt

y=y'
y'=y

z = z'
z' = z

t = t' + vx/c^2
t' = t - vx/c^2
So what is the problem you see?

=

On Friday, September 3, 2021 at 1:40:58 PM UTC-7, bodk...@gmail.com wrote:
> Robert Winn <rbw...@gmail.com> wrote:
> > x'=x-vt
> > y'=y
> > z'=z
> > t'=t-vx/c^2
> >
> > inverse equations
> >
> > x = x' - v't'
> >
> > v't' = -vt
> >
> > x = x' + vt
> > y = y'
> > z = z'
> > t = t' + vx/c^2
> These equations were proposed about 120 years ago by another scientist (not
> Einstein). It’s probably worth your time finding out who did them before
> you, and how it was determined that they are not right.
> >
> > So the equations are in the form scientists say they insist on. t is the
> > time of a clock in S, t' is the time of a clock in S'. The equations
> > show reality as it actually exists. If a pilot in an airplane has a
> > clock that is slower than a clock on the ground, as Einstein proposed,
> > then t' is the time of the clock in the airplane, and v' is the speed of
> > the airplane according to the time of the clock in the airplane that
> > shows t'. Since there is no length contraction in the Galilean
> > transformation equations, the distance the airplane travels is the same
> > as observed from either frame of reference. This enables us to say
> >
> > x = x' - v't'
> > ct = ct' - v't'
> > ct = ct' +vt
> > t = t' + vt/c
> > t = t' + vct/c^2
> > t = t' + vx/c^2
> >
> > which is the same equation we got for the times using
> >
> > x'=x-vt
> >
> > ct' = ct -vt
> > t' = t - vt/c
> > t' = t - vx/c^2
> >
> --
Well, since you know all about these equations, go ahead and give the details. No?
So how is it that I am supposed to find this information?
> Odd Bodkin -- maker of fine toys, tools, tables

Robert Winn wrote:
> On Friday, September 3, 2021 at 12:40:07 PM UTC-7, Dirk Van de moortel wrote:
>> Op 03-sep.-2021 om 20:51 schreef Robert Winn:
>>> x'=x-vt
>>> y'=y
>>> z'=z
>>> t'=t-vx/c^2
>>>
>>> inverse equations
>> When I solve these equations for x, y, z, t, I get
>>
>> x = g^2 ( x' + v t' )
>> y = y'
>> z = z'
>> t = g^2 ( t' + v x / c^2 )
>> where
>> g = 1 / sqrt( 1 - v^2/c^2 )
>>
>> But you have this:
>>> x = x' - v't'
>>>
>>> v't' = -vt
>>>
>>> x = x' + vt
>>> y = y'
>>> z = z'
>>> t = t' + vx/c^2
>> Please solve these last four equations for x', y', z', t'.
>> Whet do you get?
>>
>> Dirk Vdm
> I know how difficult this must seem.
> x = x' + vt
> x' = x - vt
>
> y=y'
> y'=y
>
> z = z'
> z' = z
>
> t = t' + vx/c^2
> t' = t - vx/c^2
> So what is the problem you see?

Look carefully, at some point you made a basic algebraic mistake.

On Friday, September 3, 2021 at 1:56:59 PM UTC-7, Dono. wrote:
> On Friday, September 3, 2021 at 11:51:55 AM UTC-7, Robert Winn wrote:
> > x'=x-vt
> > y'=y
> > z'=z
> > t'=t-vx/c^2
> >
> > inverse equations
> >
> > x = x' - v't'
> Bzzt, wrong. You are unemployed again.
So go ahead and show the mistake, Dono. No?
Well, nice taking to you again.

On Friday, September 3, 2021 at 4:04:17 PM UTC-7, Python wrote:
> Robert Winn wrote:
> > On Friday, September 3, 2021 at 12:40:07 PM UTC-7, Dirk Van de moortel wrote:
> >> Op 03-sep.-2021 om 20:51 schreef Robert Winn:
> >>> x'=x-vt
> >>> y'=y
> >>> z'=z
> >>> t'=t-vx/c^2
> >>>
> >>> inverse equations
> >> When I solve these equations for x, y, z, t, I get
> >>
> >> x = g^2 ( x' + v t' )
> >> y = y'
> >> z = z'
> >> t = g^2 ( t' + v x / c^2 )
> >> where
> >> g = 1 / sqrt( 1 - v^2/c^2 )
> >>
> >> But you have this:
> >>> x = x' - v't'
> >>>
> >>> v't' = -vt
> >>>
> >>> x = x' + vt
> >>> y = y'
> >>> z = z'
> >>> t = t' + vx/c^2
> >> Please solve these last four equations for x', y', z', t'.
> >> Whet do you get?
> >>
> >> Dirk Vdm
> > I know how difficult this must seem.
> > x = x' + vt
> > x' = x - vt
> >
> > y=y'
> > y'=y
> >
> > z = z'
> > z' = z
> >
> > t = t' + vx/c^2
> > t' = t - vx/c^2
> > So what is the problem you see?
> Look carefully, at some point you made a basic algebraic mistake.
I made a basic algebraic mistake? Well, go ahead and show the mistake, Dono. Don't be so bashful.

Op 04-sep.-2021 om 01:04 schreef Python:
> Robert Winn wrote:
>> On Friday, September 3, 2021 at 12:40:07 PM UTC-7, Dirk Van de moortel
>> wrote:
>>> Op 03-sep.-2021 om 20:51 schreef Robert Winn:
>>>> x'=x-vt
>>>> y'=y
>>>> z'=z
>>>> t'=t-vx/c^2
>>>>
>>>> inverse equations
>>> When I solve these equations for x, y, z, t, I get
>>>
>>> x = g^2 ( x' + v t' )
>>> y = y'
>>> z = z'
>>> t = g^2 ( t' + v x / c^2 )
>>> where
>>> g = 1 / sqrt( 1 - v^2/c^2 )
>>>
>>> But you have this:
>>>> x = x' - v't'
>>>>
>>>> v't' = -vt
>>>>
>>>> x = x' + vt
>>>> y = y'
>>>> z = z'
>>>> t = t' + vx/c^2
>>> Please solve these last four equations for x', y', z', t'.
>>> Whet do you get?
>>>
>>> Dirk Vdm
>> I know how difficult this must seem.
>> x = x' + vt
>> x' = x - vt
>>
>>   y=y'
>> y'=y
>>
>> z = z'
>> z' = z
>>
>> t = t' + vx/c^2
>> t' = t - vx/c^2
>> So what is the problem you see?
>
> Look carefully, at some point you made a basic algebraic mistake.

Never mind.
Telephone poles aren't worth it.

Dirk Vdm

Robert Winn wrote:
> On Friday, September 3, 2021 at 4:04:17 PM UTC-7, Python wrote:
>> Robert Winn wrote:
>>> On Friday, September 3, 2021 at 12:40:07 PM UTC-7, Dirk Van de moortel wrote:
>>>> Op 03-sep.-2021 om 20:51 schreef Robert Winn:
>>>>> x'=x-vt
>>>>> y'=y
>>>>> z'=z
>>>>> t'=t-vx/c^2
>>>>>
>>>>> inverse equations
>>>> When I solve these equations for x, y, z, t, I get
>>>>
>>>> x = g^2 ( x' + v t' )
>>>> y = y'
>>>> z = z'
>>>> t = g^2 ( t' + v x / c^2 )
>>>> where
>>>> g = 1 / sqrt( 1 - v^2/c^2 )
>>>>
>>>> But you have this:
>>>>> x = x' - v't'
>>>>>
>>>>> v't' = -vt
>>>>>
>>>>> x = x' + vt
>>>>> y = y'
>>>>> z = z'
>>>>> t = t' + vx/c^2
>>>> Please solve these last four equations for x', y', z', t'.
>>>> Whet do you get?
>>>>
>>>> Dirk Vdm
>>> I know how difficult this must seem.
>>> x = x' + vt
>>> x' = x - vt
>>>
>>> y=y'
>>> y'=y
>>>
>>> z = z'
>>> z' = z
>>>
>>> t = t' + vx/c^2
>>> t' = t - vx/c^2
>>> So what is the problem you see?
>> Look carefully, at some point you made a basic algebraic mistake.
> I made a basic algebraic mistake? Well, go ahead and show the mistake, Dono. Don't be so bashful.

Now you made two mistakes, one is that I'm not Dono. Look harder,
you may find the other one.

On 9/3/2021 7:05 PM, Robert Winn wrote:
> On Friday, September 3, 2021 at 1:56:59 PM UTC-7, Dono. wrote:
>> On Friday, September 3, 2021 at 11:51:55 AM UTC-7, Robert Winn wrote:
>>> x'=x-vt
>>> y'=y
>>> z'=z
>>> t'=t-vx/c^2
>>>
>>> inverse equations
>>>
>>> x = x' - v't'
>> Bzzt, wrong. You are unemployed again.
> So go ahead and show the mistake, Dono. No?

Dirk already did.
But you blew him off.

> Well, nice taking to you again.
>

On Friday, September 3, 2021 at 4:21:42 PM UTC-7, Dirk Van de moortel wrote:
> Op 04-sep.-2021 om 01:04 schreef Python:
> > Robert Winn wrote:
> >> On Friday, September 3, 2021 at 12:40:07 PM UTC-7, Dirk Van de moortel
> >> wrote:
> >>> Op 03-sep.-2021 om 20:51 schreef Robert Winn:
> >>>> x'=x-vt
> >>>> y'=y
> >>>> z'=z
> >>>> t'=t-vx/c^2
> >>>>
> >>>> inverse equations
> >>> When I solve these equations for x, y, z, t, I get
> >>>
> >>> x = g^2 ( x' + v t' )
> >>> y = y'
> >>> z = z'
> >>> t = g^2 ( t' + v x / c^2 )
> >>> where
> >>> g = 1 / sqrt( 1 - v^2/c^2 )
> >>>
> >>> But you have this:
> >>>> x = x' - v't'
> >>>>
> >>>> v't' = -vt
> >>>>
> >>>> x = x' + vt
> >>>> y = y'
> >>>> z = z'
> >>>> t = t' + vx/c^2
> >>> Please solve these last four equations for x', y', z', t'.
> >>> Whet do you get?
> >>>
> >>> Dirk Vdm
> >> I know how difficult this must seem.
> >> x = x' + vt
> >> x' = x - vt
> >>
> >> y=y'
> >> y'=y
> >>
> >> z = z'
> >> z' = z
> >>
> >> t = t' + vx/c^2
> >> t' = t - vx/c^2
> >> So what is the problem you see?
> >
> > Look carefully, at some point you made a basic algebraic mistake.
> Never mind.
> Telephone poles aren't worth it.
>
> Dirk Vdm
Telephone poles aren't worth it? We used to make telephone poles back in Montana before the Democratic Party claimed all trees on federal land and now only allows them to be used for 500,000 acre forest fires to prove to their party members in cities that there is global warming.
You obviously had something in mind when you wanted these equations solved. What was it?

On Friday, September 3, 2021 at 4:33:21 PM UTC-7, Python wrote:
> Robert Winn wrote:
> > On Friday, September 3, 2021 at 4:04:17 PM UTC-7, Python wrote:
> >> Robert Winn wrote:
> >>> On Friday, September 3, 2021 at 12:40:07 PM UTC-7, Dirk Van de moortel wrote:
> >>>> Op 03-sep.-2021 om 20:51 schreef Robert Winn:
> >>>>> x'=x-vt
> >>>>> y'=y
> >>>>> z'=z
> >>>>> t'=t-vx/c^2
> >>>>>
> >>>>> inverse equations
> >>>> When I solve these equations for x, y, z, t, I get
> >>>>
> >>>> x = g^2 ( x' + v t' )
> >>>> y = y'
> >>>> z = z'
> >>>> t = g^2 ( t' + v x / c^2 )
> >>>> where
> >>>> g = 1 / sqrt( 1 - v^2/c^2 )
> >>>>
> >>>> But you have this:
> >>>>> x = x' - v't'
> >>>>>
> >>>>> v't' = -vt
> >>>>>
> >>>>> x = x' + vt
> >>>>> y = y'
> >>>>> z = z'
> >>>>> t = t' + vx/c^2
> >>>> Please solve these last four equations for x', y', z', t'.
> >>>> Whet do you get?
> >>>>
> >>>> Dirk Vdm
> >>> I know how difficult this must seem.
> >>> x = x' + vt
> >>> x' = x - vt
> >>>
> >>> y=y'
> >>> y'=y
> >>>
> >>> z = z'
> >>> z' = z
> >>>
> >>> t = t' + vx/c^2
> >>> t' = t - vx/c^2
> >>> So what is the problem you see?
> >> Look carefully, at some point you made a basic algebraic mistake.
> > I made a basic algebraic mistake? Well, go ahead and show the mistake, Dono. Don't be so bashful.
> Now you made two mistakes, one is that I'm not Dono. Look harder,
> you may find the other one.
No, can't find a mistake. Go ahead and point it out.

On Friday, September 3, 2021 at 4:35:37 PM UTC-7, Michael Moroney wrote:
> On 9/3/2021 7:05 PM, Robert Winn wrote:
> > On Friday, September 3, 2021 at 1:56:59 PM UTC-7, Dono. wrote:
> >> On Friday, September 3, 2021 at 11:51:55 AM UTC-7, Robert Winn wrote:
> >>> x'=x-vt
> >>> y'=y
> >>> z'=z
> >>> t'=t-vx/c^2
> >>>
> >>> inverse equations
> >>>
> >>> x = x' - v't'
> >> Bzzt, wrong. You are unemployed again.
> > So go ahead and show the mistake, Dono. No?
> Dirk already did.
> But you blew him off.
> > Well, nice taking to you again.
> >
Dirk already did? Dirk told me to derive x',y' z' and t' from the other equations, which I did. If Dirk could find an error in my algebra, obviously, he would say what it was.

Robert Winn <rbwinn3@gmail.com> wrote:
> On Friday, September 3, 2021 at 1:40:58 PM UTC-7, bodk...@gmail.com wrote:
>> Robert Winn <rbw...@gmail.com> wrote:
>>> x'=x-vt
>>> y'=y
>>> z'=z
>>> t'=t-vx/c^2
>>>
>>> inverse equations
>>>
>>> x = x' - v't'
>>>
>>> v't' = -vt
>>>
>>> x = x' + vt
>>> y = y'
>>> z = z'
>>> t = t' + vx/c^2
>> These equations were proposed about 120 years ago by another scientist (not
>> Einstein). It’s probably worth your time finding out who did them before
>> you, and how it was determined that they are not right.
>>>
>>> So the equations are in the form scientists say they insist on. t is the
>>> time of a clock in S, t' is the time of a clock in S'. The equations
>>> show reality as it actually exists. If a pilot in an airplane has a
>>> clock that is slower than a clock on the ground, as Einstein proposed,
>>> then t' is the time of the clock in the airplane, and v' is the speed of
>>> the airplane according to the time of the clock in the airplane that
>>> shows t'. Since there is no length contraction in the Galilean
>>> transformation equations, the distance the airplane travels is the same
>>> as observed from either frame of reference. This enables us to say
>>>
>>> x = x' - v't'
>>> ct = ct' - v't'
>>> ct = ct' +vt
>>> t = t' + vt/c
>>> t = t' + vct/c^2
>>> t = t' + vx/c^2
>>>
>>> which is the same equation we got for the times using
>>>
>>> x'=x-vt
>>>
>>> ct' = ct -vt
>>> t' = t - vt/c
>>> t' = t - vx/c^2
>>>
>> --
> Well, since you know all about these equations, go ahead and give the details. No?
> So how is it that I am supposed to find this information?

A library. A book.

>> Odd Bodkin -- maker of fine toys, tools, tables
>

--
Odd Bodkin — Maker of fine toys, tools, tables

On Friday, September 3, 2021 at 5:09:55 PM UTC-7, bodk...@gmail.com wrote:
> Robert Winn <rbw...@gmail.com> wrote:
> > On Friday, September 3, 2021 at 1:40:58 PM UTC-7, bodk...@gmail.com wrote:
> >> Robert Winn <rbw...@gmail.com> wrote:
> >>> x'=x-vt
> >>> y'=y
> >>> z'=z
> >>> t'=t-vx/c^2
> >>>
> >>> inverse equations
> >>>
> >>> x = x' - v't'
> >>>
> >>> v't' = -vt
> >>>
> >>> x = x' + vt
> >>> y = y'
> >>> z = z'
> >>> t = t' + vx/c^2
> >> These equations were proposed about 120 years ago by another scientist (not
> >> Einstein). It’s probably worth your time finding out who did them before
> >> you, and how it was determined that they are not right.
> >>>
> >>> So the equations are in the form scientists say they insist on. t is the
> >>> time of a clock in S, t' is the time of a clock in S'. The equations
> >>> show reality as it actually exists. If a pilot in an airplane has a
> >>> clock that is slower than a clock on the ground, as Einstein proposed,
> >>> then t' is the time of the clock in the airplane, and v' is the speed of
> >>> the airplane according to the time of the clock in the airplane that
> >>> shows t'. Since there is no length contraction in the Galilean
> >>> transformation equations, the distance the airplane travels is the same
> >>> as observed from either frame of reference. This enables us to say
> >>>
> >>> x = x' - v't'
> >>> ct = ct' - v't'
> >>> ct = ct' +vt
> >>> t = t' + vt/c
> >>> t = t' + vct/c^2
> >>> t = t' + vx/c^2
> >>>
> >>> which is the same equation we got for the times using
> >>>
> >>> x'=x-vt
> >>>
> >>> ct' = ct -vt
> >>> t' = t - vt/c
> >>> t' = t - vx/c^2
> >>>
> >> --
> > Well, since you know all about these equations, go ahead and give the details. No?
> > So how is it that I am supposed to find this information?
> A library. A book.
> >> Odd Bodkin -- maker of fine toys, tools, tables
> >
> --
> Odd Bodkin — Maker of fine toys, tools, tables
Not enough information. So since you know all about it, how about saying something? No? Well, that is nothing new.

Robert Winn wrote:
> On Friday, September 3, 2021 at 4:33:21 PM UTC-7, Python wrote:
>> Robert Winn wrote:
>>> On Friday, September 3, 2021 at 4:04:17 PM UTC-7, Python wrote:
>>>> Robert Winn wrote:
>>>>> On Friday, September 3, 2021 at 12:40:07 PM UTC-7, Dirk Van de moortel wrote:
>>>>>> Op 03-sep.-2021 om 20:51 schreef Robert Winn:
>>>>>>> x'=x-vt
>>>>>>> y'=y
>>>>>>> z'=z
>>>>>>> t'=t-vx/c^2
>>>>>>>
>>>>>>> inverse equations
>>>>>> When I solve these equations for x, y, z, t, I get
>>>>>>
>>>>>> x = g^2 ( x' + v t' )
>>>>>> y = y'
>>>>>> z = z'
>>>>>> t = g^2 ( t' + v x / c^2 )
>>>>>> where
>>>>>> g = 1 / sqrt( 1 - v^2/c^2 )
>>>>>>
>>>>>> But you have this:
>>>>>>> x = x' - v't'
>>>>>>>
>>>>>>> v't' = -vt
>>>>>>>
>>>>>>> x = x' + vt
>>>>>>> y = y'
>>>>>>> z = z'
>>>>>>> t = t' + vx/c^2
>>>>>> Please solve these last four equations for x', y', z', t'.
>>>>>> Whet do you get?
>>>>>>
>>>>>> Dirk Vdm
>>>>> I know how difficult this must seem.
>>>>> x = x' + vt
>>>>> x' = x - vt
>>>>>
>>>>> y=y'
>>>>> y'=y
>>>>>
>>>>> z = z'
>>>>> z' = z
>>>>>
>>>>> t = t' + vx/c^2
>>>>> t' = t - vx/c^2
>>>>> So what is the problem you see?
>>>> Look carefully, at some point you made a basic algebraic mistake.
>>> I made a basic algebraic mistake? Well, go ahead and show the mistake, Dono. Don't be so bashful.
>> Now you made two mistakes, one is that I'm not Dono. Look harder,
>> you may find the other one.
> No, can't find a mistake. Go ahead and point it out.

You didn't look hard enough. The mistake is so elementary that
it is really a bad sign for you, Robert. Try harder.

On Friday, September 3, 2021 at 6:20:26 PM UTC-7, Python wrote:
> Robert Winn wrote:
> > On Friday, September 3, 2021 at 4:33:21 PM UTC-7, Python wrote:
> >> Robert Winn wrote:
> >>> On Friday, September 3, 2021 at 4:04:17 PM UTC-7, Python wrote:
> >>>> Robert Winn wrote:
> >>>>> On Friday, September 3, 2021 at 12:40:07 PM UTC-7, Dirk Van de moortel wrote:
> >>>>>> Op 03-sep.-2021 om 20:51 schreef Robert Winn:
> >>>>>>> x'=x-vt
> >>>>>>> y'=y
> >>>>>>> z'=z
> >>>>>>> t'=t-vx/c^2
> >>>>>>>
> >>>>>>> inverse equations
> >>>>>> When I solve these equations for x, y, z, t, I get
> >>>>>>
> >>>>>> x = g^2 ( x' + v t' )
> >>>>>> y = y'
> >>>>>> z = z'
> >>>>>> t = g^2 ( t' + v x / c^2 )
> >>>>>> where
> >>>>>> g = 1 / sqrt( 1 - v^2/c^2 )
> >>>>>>
> >>>>>> But you have this:
> >>>>>>> x = x' - v't'
> >>>>>>>
> >>>>>>> v't' = -vt
> >>>>>>>
> >>>>>>> x = x' + vt
> >>>>>>> y = y'
> >>>>>>> z = z'
> >>>>>>> t = t' + vx/c^2
> >>>>>> Please solve these last four equations for x', y', z', t'.
> >>>>>> Whet do you get?
> >>>>>>
> >>>>>> Dirk Vdm
> >>>>> I know how difficult this must seem.
> >>>>> x = x' + vt
> >>>>> x' = x - vt
> >>>>>
> >>>>> y=y'
> >>>>> y'=y
> >>>>>
> >>>>> z = z'
> >>>>> z' = z
> >>>>>
> >>>>> t = t' + vx/c^2
> >>>>> t' = t - vx/c^2
> >>>>> So what is the problem you see?
> >>>> Look carefully, at some point you made a basic algebraic mistake.
> >>> I made a basic algebraic mistake? Well, go ahead and show the mistake, Dono. Don't be so bashful.
> >> Now you made two mistakes, one is that I'm not Dono. Look harder,
> >> you may find the other one.
> > No, can't find a mistake. Go ahead and point it out.
> You didn't look hard enough. The mistake is so elementary that
> it is really a bad sign for you, Robert. Try harder.
Baloney. The equations are continuous, unlike the Lorentz equations, which are discontinuous.

Robert Winn <rbwinn3@gmail.com> wrote:
> On Friday, September 3, 2021 at 5:09:55 PM UTC-7, bodk...@gmail.com wrote:
>> Robert Winn <rbw...@gmail.com> wrote:
>>> On Friday, September 3, 2021 at 1:40:58 PM UTC-7, bodk...@gmail.com wrote:
>>>> Robert Winn <rbw...@gmail.com> wrote:
>>>>> x'=x-vt
>>>>> y'=y
>>>>> z'=z
>>>>> t'=t-vx/c^2
>>>>>
>>>>> inverse equations
>>>>>
>>>>> x = x' - v't'
>>>>>
>>>>> v't' = -vt
>>>>>
>>>>> x = x' + vt
>>>>> y = y'
>>>>> z = z'
>>>>> t = t' + vx/c^2
>>>> These equations were proposed about 120 years ago by another scientist (not
>>>> Einstein). It’s probably worth your time finding out who did them before
>>>> you, and how it was determined that they are not right.
>>>>>
>>>>> So the equations are in the form scientists say they insist on. t is the
>>>>> time of a clock in S, t' is the time of a clock in S'. The equations
>>>>> show reality as it actually exists. If a pilot in an airplane has a
>>>>> clock that is slower than a clock on the ground, as Einstein proposed,
>>>>> then t' is the time of the clock in the airplane, and v' is the speed of
>>>>> the airplane according to the time of the clock in the airplane that
>>>>> shows t'. Since there is no length contraction in the Galilean
>>>>> transformation equations, the distance the airplane travels is the same
>>>>> as observed from either frame of reference. This enables us to say
>>>>>
>>>>> x = x' - v't'
>>>>> ct = ct' - v't'
>>>>> ct = ct' +vt
>>>>> t = t' + vt/c
>>>>> t = t' + vct/c^2
>>>>> t = t' + vx/c^2
>>>>>
>>>>> which is the same equation we got for the times using
>>>>>
>>>>> x'=x-vt
>>>>>
>>>>> ct' = ct -vt
>>>>> t' = t - vt/c
>>>>> t' = t - vx/c^2
>>>>>
>>>> --
>>> Well, since you know all about these equations, go ahead and give the details. No?
>>> So how is it that I am supposed to find this information?
>> A library. A book.
>>>> Odd Bodkin -- maker of fine toys, tools, tables
>>>
>> --
>> Odd Bodkin — Maker of fine toys, tools, tables
> Not enough information.

It is for people who do physics.

You’re trying to do physics.

> So since you know all about it, how about saying something? No? Well,
> that is nothing new.
>

--
Odd Bodkin — Maker of fine toys, tools, tables

On 9/3/2021 8:09 PM, Robert Winn wrote:
> On Friday, September 3, 2021 at 4:35:37 PM UTC-7, Michael Moroney wrote:
>> On 9/3/2021 7:05 PM, Robert Winn wrote:
>>> On Friday, September 3, 2021 at 1:56:59 PM UTC-7, Dono. wrote:
>>>> On Friday, September 3, 2021 at 11:51:55 AM UTC-7, Robert Winn wrote:
>>>>> x'=x-vt
>>>>> y'=y
>>>>> z'=z
>>>>> t'=t-vx/c^2
>>>>>
>>>>> inverse equations
>>>>>
>>>>> x = x' - v't'
>>>> Bzzt, wrong. You are unemployed again.
>>> So go ahead and show the mistake, Dono. No?
>> Dirk already did.
>> But you blew him off.
>>> Well, nice taking to you again.
>>>
> Dirk already did? Dirk told me to derive x',y' z' and t' from the other equations, which I did. If Dirk could find an error in my algebra, obviously, he would say what it was.

And he did. If you are unable to read his post, too bad for you, I
guess you really are as dumb as those telephone poles you used to make.

On Friday, September 3, 2021 at 7:04:20 PM UTC-7, bodk...@gmail.com wrote:
> Robert Winn <rbw...@gmail.com> wrote:
> > On Friday, September 3, 2021 at 5:09:55 PM UTC-7, bodk...@gmail.com wrote:
> >> Robert Winn <rbw...@gmail.com> wrote:
> >>> On Friday, September 3, 2021 at 1:40:58 PM UTC-7, bodk...@gmail.com wrote:
> >>>> Robert Winn <rbw...@gmail.com> wrote:
> >>>>> x'=x-vt
> >>>>> y'=y
> >>>>> z'=z
> >>>>> t'=t-vx/c^2
> >>>>>
> >>>>> inverse equations
> >>>>>
> >>>>> x = x' - v't'
> >>>>>
> >>>>> v't' = -vt
> >>>>>
> >>>>> x = x' + vt
> >>>>> y = y'
> >>>>> z = z'
> >>>>> t = t' + vx/c^2
> >>>> These equations were proposed about 120 years ago by another scientist (not
> >>>> Einstein). It’s probably worth your time finding out who did them before
> >>>> you, and how it was determined that they are not right.
> >>>>>
> >>>>> So the equations are in the form scientists say they insist on. t is the
> >>>>> time of a clock in S, t' is the time of a clock in S'. The equations
> >>>>> show reality as it actually exists. If a pilot in an airplane has a
> >>>>> clock that is slower than a clock on the ground, as Einstein proposed,
> >>>>> then t' is the time of the clock in the airplane, and v' is the speed of
> >>>>> the airplane according to the time of the clock in the airplane that
> >>>>> shows t'. Since there is no length contraction in the Galilean
> >>>>> transformation equations, the distance the airplane travels is the same
> >>>>> as observed from either frame of reference. This enables us to say
> >>>>>
> >>>>> x = x' - v't'
> >>>>> ct = ct' - v't'
> >>>>> ct = ct' +vt
> >>>>> t = t' + vt/c
> >>>>> t = t' + vct/c^2
> >>>>> t = t' + vx/c^2
> >>>>>
> >>>>> which is the same equation we got for the times using
> >>>>>
> >>>>> x'=x-vt
> >>>>>
> >>>>> ct' = ct -vt
> >>>>> t' = t - vt/c
> >>>>> t' = t - vx/c^2
> >>>>>
> >>>> --
> >>> Well, since you know all about these equations, go ahead and give the details. No?
> >>> So how is it that I am supposed to find this information?
> >> A library. A book.
> >>>> Odd Bodkin -- maker of fine toys, tools, tables
> >>>
> >> --
> >> Odd Bodkin — Maker of fine toys, tools, tables
> > Not enough information.
> It is for people who do physics.
>
> You’re trying to do physics.
> > So since you know all about it, how about saying something? No? Well,
> > that is nothing new.
> >
> --
> Odd Bodkin — Maker of fine toys, tools, tables
Well, so relativity is physics. Don't want to discuss relativity?
Then you do not want to discuss physics.

On Friday, September 3, 2021 at 7:09:02 PM UTC-7, Michael Moroney wrote:
> On 9/3/2021 8:09 PM, Robert Winn wrote:
> > On Friday, September 3, 2021 at 4:35:37 PM UTC-7, Michael Moroney wrote:
> >> On 9/3/2021 7:05 PM, Robert Winn wrote:
> >>> On Friday, September 3, 2021 at 1:56:59 PM UTC-7, Dono. wrote:
> >>>> On Friday, September 3, 2021 at 11:51:55 AM UTC-7, Robert Winn wrote:
> >>>>> x'=x-vt
> >>>>> y'=y
> >>>>> z'=z
> >>>>> t'=t-vx/c^2
> >>>>>
> >>>>> inverse equations
> >>>>>
> >>>>> x = x' - v't'
> >>>> Bzzt, wrong. You are unemployed again.
> >>> So go ahead and show the mistake, Dono. No?
> >> Dirk already did.
> >> But you blew him off.
> >>> Well, nice taking to you again.
> >>>
> > Dirk already did? Dirk told me to derive x',y' z' and t' from the other equations, which I did. If Dirk could find an error in my algebra, obviously, he would say what it was.
> And he did. If you are unable to read his post, too bad for you, I
> guess you really are as dumb as those telephone poles you used to make.
Well, if you had something to say, you would say it. So you have nothing to say. Telephone poles hold up phone lines. At least they do something useful.
Dirk told me to derive x',y',z', and t' from the last four equations I had shown, which I did. Then Dirk made his comment about telephone poles, and we have not heard from him since then. So you are all saying that there is some mysterious error in my algebra, but no one will say what it is. I do not believe there is an error.

Robert Winn wrote:
> On Friday, September 3, 2021 at 6:20:26 PM UTC-7, Python wrote:
>> Robert Winn wrote:
>>> On Friday, September 3, 2021 at 4:33:21 PM UTC-7, Python wrote:
>>>> Robert Winn wrote:
>>>>> On Friday, September 3, 2021 at 4:04:17 PM UTC-7, Python wrote:
>>>>>> Robert Winn wrote:
>>>>>>> On Friday, September 3, 2021 at 12:40:07 PM UTC-7, Dirk Van de moortel wrote:
>>>>>>>> Op 03-sep.-2021 om 20:51 schreef Robert Winn:
>>>>>>>>> x'=x-vt
>>>>>>>>> y'=y
>>>>>>>>> z'=z
>>>>>>>>> t'=t-vx/c^2
>>>>>>>>>
>>>>>>>>> inverse equations
>>>>>>>> When I solve these equations for x, y, z, t, I get
>>>>>>>>
>>>>>>>> x = g^2 ( x' + v t' )
>>>>>>>> y = y'
>>>>>>>> z = z'
>>>>>>>> t = g^2 ( t' + v x / c^2 )
>>>>>>>> where
>>>>>>>> g = 1 / sqrt( 1 - v^2/c^2 )
>>>>>>>>
>>>>>>>> But you have this:
>>>>>>>>> x = x' - v't'
>>>>>>>>>
>>>>>>>>> v't' = -vt
>>>>>>>>>
>>>>>>>>> x = x' + vt
>>>>>>>>> y = y'
>>>>>>>>> z = z'
>>>>>>>>> t = t' + vx/c^2
>>>>>>>> Please solve these last four equations for x', y', z', t'.
>>>>>>>> Whet do you get?
>>>>>>>>
>>>>>>>> Dirk Vdm
>>>>>>> I know how difficult this must seem.
>>>>>>> x = x' + vt
>>>>>>> x' = x - vt
>>>>>>>
>>>>>>> y=y'
>>>>>>> y'=y
>>>>>>>
>>>>>>> z = z'
>>>>>>> z' = z
>>>>>>>
>>>>>>> t = t' + vx/c^2
>>>>>>> t' = t - vx/c^2
>>>>>>> So what is the problem you see?
>>>>>> Look carefully, at some point you made a basic algebraic mistake.
>>>>> I made a basic algebraic mistake? Well, go ahead and show the mistake, Dono. Don't be so bashful.
>>>> Now you made two mistakes, one is that I'm not Dono. Look harder,
>>>> you may find the other one.
>>> No, can't find a mistake. Go ahead and point it out.
>> You didn't look hard enough. The mistake is so elementary that
>> it is really a bad sign for you, Robert. Try harder.
> Baloney. The equations are continuous, unlike the Lorentz equations, which are discontinuous.

I wonder what you mean by continuous in the context. Anyway, your
mistake is an obvious one, and you've got an hint. How come you cannot
spot it?