Wilson's (1911) cloud chamber is used to justify the existence of protons that are said to be forming the cloud chamber alcohol tracks. Wilson's cloud chamber contains a radium isotope that forms the alcohol tracks but radium results in numerous different types of particle emissions such as gamma emissions, photon emissions, electron emissions, proton emissions, alpha decay, beta emissions, neutron emissions, and cluster decay yet the Wilson's cloud chamber is said to only be forming alchohol tracks formed by protons yet radium is emitting a variety of different nuclear derived particle emissions. The Lawrence cyclotron (1929) is used to justify the existence of a proton beam but during the acceleration process, the negative polarity, of the oscillating polarity (+/-) dee halves, would attract the positively charged protons to the negatively charged dee halves and eliminate the protons propagating within the cyclotron preventing the formation of a proton beam. Plus, the cyclotron protons are formed by a radium isotope placed at the center of the cyclotron but protons are formed by the secondary decay of radon gas yet radon gas cannot be contained within the open system of the cyclotron since the radon gas would leak into the hollow cyclotron dee halves and escape through the gaps into open space outside the cyclotron's structure, and, it would not be physically possible to enclose the random gas and form a proton beam since protons that are composed of matter cannot penetrate the enclosure of the random gas. Lawrence cyclotron proton beam is represented with a blue light beam (fig 19) which proves the cyclotron proton beam is fictional. The duoplasmatron forms the proton beam used in the Fermilab and LHC particle accelerators. The duoplasmatron proton beam is produced by hydrogen gas that is ignited using a 22 kV arc but positively charged protons attracted to the negatively charged duoplasmatron grid would collide with the 22 kV grid surfaces preventing the formation of a proton beam. Also, it is highly unlikely that protons which originate from the nucleus form the stability required in the production of a proton beam. Proton beam therapy is used to justify the existence of a proton beam but protons that have a mass 1,000 times greater than an electron would destroy human skin, tissue and bone in the path of the proton beam

Why would the sub atomic blow a macro bubble anywhere we can see?

Mitchell Raemsch

On Thursday, January 20, 2022 at 6:49:25 PM UTC-8, mitchr...@gmail.com wrote:
> Why would the sub atomic blow a macro bubble anywhere we can see?
>
> Mitchell Raemsch

Particle physics will never win another Noble prize. period

mitchr...@gmail.com wrote:

> Why would the sub atomic blow a macro bubble anywhere we can see?

stop trusting that quantum shit. It's fake. Not even now they have a
*"quantum_computer"*. All fake like shit.

On Friday, January 21, 2022 at 11:23:35 AM UTC-8, Tommie Ditch wrote:
> mitchr...@gmail.com wrote:
>
> > Why would the sub atomic blow a macro bubble anywhere we can see?
> stop trusting that quantum shit. It's fake. Not even now they have a
> *"quantum_computer"*. All fake like shit.

You are right but light is composed of particles since we have Newton prism effect and Lenard's photoelectric effect. Yes, quantum computers based on an uncertainty are fake but it could be something else and they are calling it quantum computer to be cute. Where did you get that name Tommie Ditch. Sound like Billy Buctethead, of p-Bodkin and ff-Silvia

How can subatomic particles propagate through the steel container of the bubble chamber and then form the spiral liquid hydrogen bubble tracks?

On Monday, January 31, 2022 at 9:43:51 AM UTC-8, thor stoneman wrote:
> How can subatomic particles propagate through the steel container of the bubble chamber and then form the spiral liquid hydrogen bubble tracks?

The Fermilab (1967) particle physics experiment describes an acellerated proton beam collision with a beryllium target that forms subatomic particles which propagate through the steel structure of the bubble chamber producing spiral shape liquid hydrogen bubble tracks that are used to determine the mass and energy of the subatomic particles. The Fermilab proton beam is formed by a duoplasmatron but positively charged protons attracted to the negatively charged duoplasmatron grid would collide with the 22 kV grid surfaces preventing the formation of a proton beam. Plus, the Fermilab RF cavity accelerates the ostensible protons, formed by the duoplasmatron, by oscillating the polarity of the metal surfaces of the RF cavity using an oscillating LRC circuit where the protons propagate through a 6 km circular beam pipe surrounded by magnets that guides the 20,000 passes of the proton beam through the circular beam pipe and RF cavity resulting in the acceleration of the proton beam to the velocity of .7c. Initially, as the protons enter the first segment of the RF cavity, the positively charged protons are attracted to the far negatively charged cathode surface that surrounds the far hole of the first segment of the RF cavity. As the protons approach the far hole, of the first segment of the RF cavity, the negatively charged metal surface that surrounds the far hole switches polarity and becomes positively charged to prevent the positively charged protons from colliding with the sides of the far hole that allows the protons to propagate through the far hole which represents the acceleration of the protons by the first segment of the RF cavity. This mechanism is repeated for each segment of the RF cavity and represents the acceleration of the proton beams. The protons make more than 20,000 passes through the RF cavity and circular beam pipe where the proton beam is said to be accelerated to the velocity of .7c at the end of the acceleration process yet the electrons of a copper wire are propagating at a velocity of 106 m/s. Electrons of a LRC circuit that is forming the oscillating polarity (+/-) of each segment of the RF cavity cannot propagate fast enough to fill the negative surface of the RF cavity in the formation of the polarity oscillation used to accelerate the protons to the speed of .7c since the electrons must fill the outer metallic surface of the RF cavity by propagating along the metallic surface to form the negative charged RF cavity surface that is used to accelerate the protons then the electrons must leave the negative charged RF cavity surface, of the far hole, to form the positive charged surface surrounding the far hole to allow the protons to enter the next segment of the RF cavity. Electrons that are propagating at the velocity of 106 m/s cannot form the RF cavity polarity oscillation fast enough to accelerate the protons to the velocity of .7c; consequently, the maximum proton beam velocity that can be achieved using the RF cavity is 106 m/s.

thor stoneman <consequently7990662@gmail.com> wrote:
> On Monday, January 31, 2022 at 9:43:51 AM UTC-8, thor stoneman wrote:
>> How can subatomic particles propagate through the steel container of the
>> bubble chamber and then form the spiral liquid hydrogen bubble tracks?
>
>
> The Fermilab (1967) particle physics experiment describes an acellerated
> proton beam collision with a beryllium target that forms subatomic
> particles which propagate through the steel structure of the bubble
> chamber producing spiral shape liquid hydrogen bubble tracks that are
> used to determine the mass and energy of the subatomic particles. The
> Fermilab proton beam is formed by a duoplasmatron but positively charged
> protons attracted to the negatively charged duoplasmatron grid would
> collide with the 22 kV grid surfaces preventing the formation of a proton
> beam. Plus, the Fermilab RF cavity accelerates the ostensible protons,
> formed by the duoplasmatron, by oscillating the polarity of the metal
> surfaces of the RF cavity using an oscillating LRC circuit where the
> protons propagate through a 6 km circular beam pipe surrounded by magnets
> that guides the 20,000 passes of the proton beam through the circular
> beam pipe and RF cavity resulting in the acceleration of the proton beam
> to the velocity of .7c. Initially, as the protons enter the first segment
> of the RF cavity, the positively charged protons are attracted to the far
> negatively charged cathode surface that surrounds the far hole of the
> first segment of the RF cavity. As the protons approach the far hole, of
> the first segment of the RF cavity, the negatively charged metal surface
> that surrounds the far hole switches polarity and becomes positively
> charged to prevent the positively charged protons from colliding with the
> sides of the far hole that allows the protons to propagate through the
> far hole which represents the acceleration of the protons by the first
> segment of the RF cavity. This mechanism is repeated for each segment of
> the RF cavity and represents the acceleration of the proton beams. The
> protons make more than 20,000 passes through the RF cavity and circular
> beam pipe where the proton beam is said to be accelerated to the velocity
> of .7c at the end of the acceleration process yet the electrons of a
> copper wire are propagating at a velocity of 106 m/s. Electrons of a LRC
> circuit that is forming the oscillating polarity (+/-) of each segment of
> the RF cavity cannot propagate fast enough to fill the negative surface
> of the RF cavity in the formation of the polarity oscillation used to
> accelerate the protons to the speed of .7c since the electrons must fill
> the outer metallic surface of the RF cavity by propagating along the
> metallic surface to form the negative charged RF cavity surface that is
> used to accelerate the protons then the electrons must leave the negative
> charged RF cavity surface, of the far hole, to form the positive charged
> surface surrounding the far hole to allow the protons to enter the next
> segment of the RF cavity. Electrons that are propagating at the velocity
> of 106 m/s cannot form the RF cavity polarity oscillation fast enough to
> accelerate the protons to the velocity of .7c; consequently, the maximum
> proton beam velocity that can be achieved using the RF cavity is 106 m/s.
>

There are some people, I’m sure, that will have lots of reasons to insist
that a pangolin cannot exist — a mammalian ant-eater with scales. Of
course, all that it would take to completely deflate those reasons is to go
to a zoo and to see one in real life. This is also cause for some people to
find some excuse to never go to a zoo, so that they do not have to confront
reality that conflicts with their “reasons”.

It may come as a surprise to you that Fermilab is an open facility. You can
go there and walk around and ask questions and see all the things happening
that you claim are impossible.

That’s your cue to find an excuse for never visiting Fermilab or a zoo or
any other place that would make reality confront your “reasons”.

--
Odd Bodkin -- maker of fine toys, tools, tables

On Monday, 31 January 2022 at 21:17:11 UTC+1, bodk...@gmail.com wrote:

> There are some people, I’m sure, that will have lots of reasons to insist
> that a pangolin cannot exist — a mammalian ant-eater with scales. Of
> course, all that it would take to completely deflate those reasons is to go
> to a zoo and to see one in real life. This is also cause for some people to
> find some excuse to never go to a zoo, so that they do not have to confront
> reality that conflicts with their “reasons”.

Samely, anyone can check GPS and see, that the clocks
of the real world keep measuring t'=t. But, well, the reality
was never winning against some blind faith of a fanatic
idiot.

Maciej Wozniak wrote:

>> to go to a zoo and to see one in real life. This is also cause for some
>> people to find some excuse to never go to a zoo, so that they do not
>> have to confront reality that conflicts with their “reasons”.
>
> Samely, anyone can check GPS and see, that the clocks of the real world
> keep measuring t'=t. But, well, the reality was never winning against
> some blind faith of a fanatic idiot.

at which frequency. It just came up to me that the frequency is decisive
in relativity.

Den 31.01.2022 20:17, skrev thor stoneman:
>
> The Fermilab (1967) particle physics experiment describes an acellerated proton beam collision with a beryllium target that forms subatomic particles which propagate through the steel structure of the bubble chamber producing spiral shape liquid hydrogen bubble tracks that are used to determine the mass and energy of the subatomic particles. The Fermilab proton beam is formed by a duoplasmatron but positively charged protons attracted to the negatively charged duoplasmatron grid would collide with the 22 kV grid surfaces preventing the formation of a proton beam. Plus, the Fermilab RF cavity accelerates the ostensible protons, formed by the duoplasmatron, by oscillating the polarity of the metal surfaces of the RF cavity using an oscillating LRC circuit where the protons propagate through a 6 km circular beam pipe surrounded by magnets that guides the 20,000 passes of the proton beam through the circular beam pipe and RF cavity resulting in the acceleration of the proton beam to the velocity of .7c. Initially, as the protons enter the first segment of the RF cavity, the positively charged protons are attracted to the far negatively charged cathode surface that surrounds the far hole of the first segment of the RF cavity. As the protons approach the far hole, of the first segment of the RF cavity, the negatively charged metal surface that surrounds the far hole switches polarity and becomes positively charged to prevent the positively charged protons from colliding with the sides of the far hole that allows the protons to propagate through the far hole which represents the acceleration of the protons by the first segment of the RF cavity. This mechanism is repeated for each segment of the RF cavity and represents the acceleration of the proton beams. The protons make more than 20,000 passes through the RF cavity and circular beam pipe where the proton beam is said to be accelerated to the velocity of .7c at the end of the acceleration process yet the electrons of a copper wire are propagating at a velocity of 106 m/s. Electrons of a LRC circuit that is forming the oscillating polarity (+/-) of each segment of the RF cavity cannot propagate fast enough to fill the negative surface of the RF cavity in the formation of the polarity oscillation used to accelerate the protons to the speed of .7c since the electrons must fill the outer metallic surface of the RF cavity by propagating along the metallic surface to form the negative charged RF cavity surface that is used to accelerate the protons then the electrons must leave the negative charged RF cavity surface, of the far hole, to form the positive charged surface surrounding the far hole to allow the protons to enter the next segment of the RF cavity. Electrons that are propagating at the velocity of 106 m/s cannot form the RF cavity polarity oscillation fast enough to accelerate the protons to the velocity of .7c; consequently, the maximum proton beam velocity that can be achieved using the RF cavity is 106 m/s.
Are you seriously claiming that you have proved that
particle accelerators don't work because you understand
that RF cavities can't work? :-D
--
Paul
https://paulba.no/

> Are you seriously claiming that you have proved that
particle accelerators don't work because you understand
that RF cavities can't work?

Yes.

Are electrons used to accelerate the proton beam?

How fast are the electrons in a wire propagating?

thor stoneman <consequently7990662@gmail.com> wrote:
>
>> Are you seriously claiming that you have proved that
> particle accelerators don't work because you understand
> that RF cavities can't work?
>
> Yes.

Ha. This will come as an awful shock to Fermilab, which was accelerating
particles since the 1970s, or so they thought.

>
> Are electrons used to accelerate the proton beam?

Only peripherally. Electric fields accelerate the protons.

>
> How fast are the electrons in a wire propagating?
>

Doesn’t matter for an RF cavity. Maybe you should go watch an RF cavity
work.

--
Odd Bodkin -- maker of fine toys, tools, tables

On Monday, January 31, 2022 at 2:21:11 PM UTC-8, bodk...@gmail.com wrote:
> thor stoneman <consequen...@gmail.com> wrote:
> >
> >> Are you seriously claiming that you have proved that
> > particle accelerators don't work because you understand
> > that RF cavities can't work?

How can particles be watched?

Only peripherally. Electric fields accelerate the protons.

Correct, oscillating electric fields accelerate the protons within the RF cavity and how do the electric fields oscillate?

A circuit oscillates the electric field and what key components oscillates the circuit?

ELECTRONs. What is the maximum velocity of an electron in a circuit?

thor stoneman <consequently7990662@gmail.com> wrote:
>
> Only peripherally. Electric fields accelerate the protons.
>
>
> Correct, oscillating electric fields accelerate the protons within the RF
> cavity and how do the electric fields oscillate?
>
>
> A circuit oscillates the electric field and what key components oscillates the circuit?
>
>
> ELECTRONs. What is the maximum velocity of an electron in a circuit?
>

Pretty sure it’s 3 or 4 bazillion. Maybe closer to 4.

--
Odd Bodkin -- maker of fine toys, tools, tables

> How fast are the electrons in a wire propagating?

Doesn’t matter for an RF cavity. Maybe you should go watch an RF cavity
work.

Are the electrons propagating at the velocity of light in the RF cavity. Please explain how?

How is the accelerator creating a giant electric field with the right direction
where particles are quantized as a sub atomic charge?

Mitchell Raemsch

On 1/31/2022 5:59 PM, thor stoneman wrote:
>> How fast are the electrons in a wire propagating?
>
>
> Doesn’t matter for an RF cavity. Maybe you should go watch an RF cavity
> work.
>
>
> Are the electrons propagating at the velocity of light in the RF cavity. Please explain how?

The electric field propagates through wires (transmission lines) at
between 0.5 and 0.95c. And that's what counts. In the cavity itself, in
a vacuum, the field propagates at essentially c.

How do you think radios work?

On Monday, January 31, 2022 at 4:39:32 PM UTC-8, Michael Moroney wrote:
> On 1/31/2022 5:59 PM, thor stoneman wrote:
> >> How fast are the electrons in a wire propagating?
> >
> >
> > Doesn’t matter for an RF cavity. Maybe you should go watch an RF cavity
> > work.
> >
> >
> > Are the electrons propagating at the velocity of light in the RF cavity.. Please explain how?
> The electric field propagates through wires (transmission lines) at
> between 0.5 and 0.95c. And that's what counts. In the cavity itself,

How does it manifest as a field beyond your wires?
and how would that move?

Mitchell Raemsch

Den 31.01.2022 22:40, skrev thor stoneman:
> Paul B. Andersen wrote:
>> Are you seriously claiming that you have proved that
>> particle accelerators don't work because you understand
>> that RF cavities can't work?
>
> Yes.

In that case you are out of touch with reality and
can't be taken seriously.

But I will play along anyway.

>
> How fast are the electrons in a wire propagating?

Let's consider a simpler case than a particle accelerator.

/
+10V _____/ __________________________________
|
/ O light bulb
0V _____/ __________________________________|

We have a 10 V DC supply which via a switch is connected
to a 100 W light bulb, which will draw 10A when lit.

The two wires from the switch to the light bulb are both 1 metre.
The square area of the wires is 3 square mm.

To your question:
The speeds of the electrons in the conduction band are
very high. The electrons are moving in all directions.
But if there is no current in the wire, then the AVERAGE
speed is zero. If the current is 10A, then the average speed
will be 0.25 mm per second.
===================

So the question:
When you close the switch, how long time will it be before
the current in the light bulb is 10A?

--
Paul

https://paulba.no/

thor stoneman <consequently7990662@gmail.com> wrote:
>> How fast are the electrons in a wire propagating?
>
>
> Doesn’t matter for an RF cavity. Maybe you should go watch an RF cavity
> work.
>
>
> Are the electrons propagating at the velocity of light in the RF cavity.
> Please explain how?
>

Electrons don’t need to propagate at the speed of light in an RF cavity for
the RF cavity to accelerate a proton to nearly the speed of light. A
*static* field gradient (where the electrons aren’t moving AT ALL) can
accelerate a proton.

Perhaps you need to learn how an RF cavity actually works, by seeing one in
action. That way you don’t make a bunch of stupid guesses from your locked,
windowless room.

--
Odd Bodkin -- maker of fine toys, tools, tables

> Electrons don’t need to propagate at the speed of light in an RF cavity for
> the RF cavity to accelerate a proton to nearly the speed of light. A
> *static* field gradient (where the electrons aren’t moving AT ALL) can
> accelerate a proton.
> Odd Bodkin -- maker of fine toys, tools, tables

The circuit that oscillates the RF cavity is based on electrons propagating in a wire of a circuit.

If the current is 10A, then the average speed
> will be 0.25 mm per second.

> Paul

The velocity of .25 mm/s is slower than the velocity of light by more than eight orders.

thor stoneman <consequently7990662@gmail.com> wrote:
>
>> Electrons don’t need to propagate at the speed of light in an RF cavity for
>> the RF cavity to accelerate a proton to nearly the speed of light. A
>> *static* field gradient (where the electrons aren’t moving AT ALL) can
>> accelerate a proton.
>> Odd Bodkin -- maker of fine toys, tools, tables
>
>
> The circuit that oscillates the RF cavity is based on electrons
> propagating in a wire of a circuit.
>

So? Has nothing to do with the speed of the protons in the cavity.

--
Odd Bodkin -- maker of fine toys, tools, tables